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moongazer Group TitleBest ResponseYou've already chosen the best response.1
I only got to the part: dy/dt = 2at/3y^2
 one year ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
Just derive again, so you can solve the d^2y/dt^2. :))
 one year ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
it's like solve for y''
 one year ago

amriju Group TitleBest ResponseYou've already chosen the best response.0
let it remain as 3y^2=2at..differntiate again....using multiplication rule....
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
it says the answer is: 2a/9y^2 but I am getting a different answer
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
is "a" here constant?
 one year ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
Quotient rule, remember?
 one year ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
for easier calculation, you can factor out 2a/3 and just derive (t/y^2)
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
could you show me the first step for the second derivative? maybe I did something wrong
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
i'll try again :)
 one year ago

amriju Group TitleBest ResponseYou've already chosen the best response.0
may be u need to substitute y as (at^2)^2/3
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I got: (6ay^4  8a^2 t^2 y)/9y^6 I think I am doing something wrong.
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
i'll try again :)
 one year ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
\[y' = \frac{ 2at }{ 3y^2 }\], right? Therefore, \[y' = \frac{ 2a }{ 3 } (\frac{ t }{ y^2 })\] \[y'' = \frac{ 2a }{ 3 } [\frac{ y^2  2tyy') }{ y^4 }]\] \[y'' = \frac{ 2a }{ 3 } \frac{ y^2  2ty(\frac{ 2a }{ 3 })(\frac{ t }{ y^2 }) }{ y^4 }\] Simplifying this equation we will get. \[y'' = \frac{ 2a }{ 3 } [ \frac{ 3y^4 4at^2y }{ 3y^6 }]\]
 one year ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
can you follow @moongazer ?
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
That's what I got. I think there is some typo in my answer sheet. Thanks :)
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Well you could simplify
 one year ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
@moongazer, it isn't the answer in simplest form. Maybe you can continue this and let us verify if we get the same answers.
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
@myininaya could you simply it further? @Yttrium yes, I understood your solution
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Could I? Yes. Can you?
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Eye ball the numerator and the denominator. You should see they share a common factor.
 one year ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
For our class, the definition of simplest form is that it is factored out completely. Just factor out some stuff and do cancellation.
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
2a(3y^3  4at^2) / 9y^5
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
that's what I got
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You can also choose to write at^2 as y^3
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Recall our initial equation: y^3=at^2
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I see at^2
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Replace it y^3 then combine like terms
 one year ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
@moongazer , do you what myininaya told you?
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
@moongazer I'm leaving for tonight but I think Yttrium is still here to help. Goodnight you guys. I think you guys got it from here for sure. :)
 one year ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
WOW! Thank you very much to both of you. I failed to notice that until you said it. Thanks :) I now got the answer. :)
 one year ago
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