If y^3 = at^2 , then (d^2 y)/dt^2 ?

If y^3 = at^2 , then (d^2 y)/dt^2 ?

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I only got to the part: dy/dt = 2at/3y^2

Just derive again, so you can solve the d^2y/dt^2. :))

it's like solve for y''

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