Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

If y^3 = at^2 , then (d^2 y)/dt^2 ?

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

I only got to the part: dy/dt = 2at/3y^2
Just derive again, so you can solve the d^2y/dt^2. :))
it's like solve for y''

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

let it remain as 3y^2=2at..differntiate again....using multiplication rule....
it says the answer is: -2a/9y^2 but I am getting a different answer
is "a" here constant?
Quotient rule, remember?
yo constnt
for easier calculation, you can factor out 2a/3 and just derive (t/y^2)
could you show me the first step for the second derivative? maybe I did something wrong
i'll try again :)
may be u need to substitute y as (at^2)^2/3
I got: (6ay^4 - 8a^2 t^2 y)/9y^6 I think I am doing something wrong.
i'll try again :)
\[y' = \frac{ 2at }{ 3y^2 }\], right? Therefore, \[y' = \frac{ 2a }{ 3 } (\frac{ t }{ y^2 })\] \[y'' = \frac{ 2a }{ 3 } [\frac{ y^2 - 2tyy') }{ y^4 }]\] \[y'' = \frac{ 2a }{ 3 } \frac{ y^2 - 2ty(\frac{ 2a }{ 3 })(\frac{ t }{ y^2 }) }{ y^4 }\] Simplifying this equation we will get. \[y'' = \frac{ 2a }{ 3 } [ \frac{ 3y^4 -4at^2y }{ 3y^6 }]\]
can you follow @moongazer ?
That's what I got. I think there is some typo in my answer sheet. Thanks :)
Well you could simplify
@moongazer, it isn't the answer in simplest form. Maybe you can continue this and let us verify if we get the same answers.
@myininaya could you simply it further? @Yttrium yes, I understood your solution
Could I? Yes. Can you?
Eye ball the numerator and the denominator. You should see they share a common factor.
For our class, the definition of simplest form is that it is factored out completely. Just factor out some stuff and do cancellation.
2a(3y^3 - 4at^2) / 9y^5
that's what I got
You can also choose to write at^2 as y^3
Recall our initial equation: y^3=at^2
I see at^2
Replace it y^3 then combine like terms
@moongazer , do you what myininaya told you?
@moongazer I'm leaving for tonight but I think Yttrium is still here to help. Goodnight you guys. I think you guys got it from here for sure. :)
WOW! Thank you very much to both of you. I failed to notice that until you said it. Thanks :) I now got the answer. :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question