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moongazer Group TitleBest ResponseYou've already chosen the best response.1
I only got to the part: dy/dt = 2at/3y^2
 10 months ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
Just derive again, so you can solve the d^2y/dt^2. :))
 10 months ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
it's like solve for y''
 10 months ago

amriju Group TitleBest ResponseYou've already chosen the best response.0
let it remain as 3y^2=2at..differntiate again....using multiplication rule....
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
it says the answer is: 2a/9y^2 but I am getting a different answer
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
is "a" here constant?
 10 months ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
Quotient rule, remember?
 10 months ago

amriju Group TitleBest ResponseYou've already chosen the best response.0
yo constnt
 10 months ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
for easier calculation, you can factor out 2a/3 and just derive (t/y^2)
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
could you show me the first step for the second derivative? maybe I did something wrong
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
i'll try again :)
 10 months ago

amriju Group TitleBest ResponseYou've already chosen the best response.0
may be u need to substitute y as (at^2)^2/3
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I got: (6ay^4  8a^2 t^2 y)/9y^6 I think I am doing something wrong.
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
i'll try again :)
 10 months ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
\[y' = \frac{ 2at }{ 3y^2 }\], right? Therefore, \[y' = \frac{ 2a }{ 3 } (\frac{ t }{ y^2 })\] \[y'' = \frac{ 2a }{ 3 } [\frac{ y^2  2tyy') }{ y^4 }]\] \[y'' = \frac{ 2a }{ 3 } \frac{ y^2  2ty(\frac{ 2a }{ 3 })(\frac{ t }{ y^2 }) }{ y^4 }\] Simplifying this equation we will get. \[y'' = \frac{ 2a }{ 3 } [ \frac{ 3y^4 4at^2y }{ 3y^6 }]\]
 10 months ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
can you follow @moongazer ?
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
That's what I got. I think there is some typo in my answer sheet. Thanks :)
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Well you could simplify
 10 months ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
@moongazer, it isn't the answer in simplest form. Maybe you can continue this and let us verify if we get the same answers.
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
@myininaya could you simply it further? @Yttrium yes, I understood your solution
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Could I? Yes. Can you?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Eye ball the numerator and the denominator. You should see they share a common factor.
 10 months ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
For our class, the definition of simplest form is that it is factored out completely. Just factor out some stuff and do cancellation.
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
2a(3y^3  4at^2) / 9y^5
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
that's what I got
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You can also choose to write at^2 as y^3
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Recall our initial equation: y^3=at^2
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I see at^2
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Replace it y^3 then combine like terms
 10 months ago

Yttrium Group TitleBest ResponseYou've already chosen the best response.1
@moongazer , do you what myininaya told you?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
@moongazer I'm leaving for tonight but I think Yttrium is still here to help. Goodnight you guys. I think you guys got it from here for sure. :)
 10 months ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
WOW! Thank you very much to both of you. I failed to notice that until you said it. Thanks :) I now got the answer. :)
 10 months ago
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