IsTim
  • IsTim
In Part A, you determined that the heat added to the coffee is what you got. If it takes 4.2 J of energy to raise the temperature of 1.0 mL of coffee by 1.0∘C, then it should take twice as much energy to raise the temperature of 2.0 mL of coffee by 1.0∘C, or to raise the temperature of 1.0 mL of coffee by 2.0∘C. Multiply carefully to find the total amount of energy needed to raise the temperature of 200 mL of coffee by the required number of degrees.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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IsTim
  • IsTim
This is a hint to an assignment I am currently doing.
IsTim
  • IsTim
I haven't read thru the textbook much or my notes; I'ved tried, and instead made a formula sheet, although I don't know what formula to apply to this.
***[ISURU]***
  • ***[ISURU]***
use \[E = mc \theta \] Since there r lot of data this one can be use easily ... I think u should be familiar with this...

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IsTim
  • IsTim
Actually, haven't seen this in my formula sheet. But I'll try it out.
***[ISURU]***
  • ***[ISURU]***
wt's the value of "required no.of degrees" mentioned in the question ?
IsTim
  • IsTim
1?
***[ISURU]***
  • ***[ISURU]***
then I think u can use a relationship with ratios to solve this one cause the problem says "Multiply carefully to find " which mean question doesn't expect use of any formula instead it expect to build the answer from given data... change of 1 degree in 1ml = 4.2 J change of 1 degree in 2ml = 8.4 J change of 1 degree in 200 ml = 8.4*100 J
IsTim
  • IsTim
These are the answers that I gave to the work, which it stated was incorrect. It requires 3 significant figures. Submitted Answers ANSWER 1: Deduction: -3% "what you get" = 8.4⋅102 J ANSWER 2: Deduction: -3% "what you get" = 8.40⋅102 J
IsTim
  • IsTim
the 102 is suppose to be 10^2
IsTim
  • IsTim
So yes, I did use your answer, but apparently it was incorrect here.
***[ISURU]***
  • ***[ISURU]***
It requires 3 significant figures. = is it same for the 840 J ?
IsTim
  • IsTim
wouldn't 8.40*10^3 J have worked?
IsTim
  • IsTim
Because 840 is only 2 sig digs without using a decimal point
***[ISURU]***
  • ***[ISURU]***
no .. I just told that 'cause it's the same answer I get even if I use E = mc*theta
IsTim
  • IsTim
So, both answers would be considered incorrect with this question then?
***[ISURU]***
  • ***[ISURU]***
@ganeshie8 , @thomaster
IsTim
  • IsTim
I managed to get the question after that correct, if it helps at all.
***[ISURU]***
  • ***[ISURU]***
if 840 J is wrong .... there is one possible reason: we calculate 840 J to a temp. change of 1 degree. But the question asks the energy need for a temp. change of required no. of degrees. And we assume that is also as 1 degree. But this question has a section name part A. Does that part mention about some reading of temperature regarding this coffee cup
IsTim
  • IsTim
Yes. This is a 'hint' to a larger question.
IsTim
  • IsTim
Suppose that you have left a 200-mL cup of coffee sitting until it has cooled to 30∘C , which you find totally unacceptable. Your microwave oven draws 1100 W of electrical power when it is running. If it takes 45 s for this microwave oven to raise the temperature of the coffee to 60∘C , what is the efficiency of heating with this oven? Find the efficiency e of the oven. You will need to use the fact that 4.2 J of energy is required to raise the temperature of 1.0 mL of coffee by 1.0∘C .
***[ISURU]***
  • ***[ISURU]***
yo ... that's the missing point!
IsTim
  • IsTim
?
***[ISURU]***
  • ***[ISURU]***
the temperature of the coffee cup was 30 degree at the beginning and it has to be increased up to 60 degree
IsTim
  • IsTim
But I dunno if those 2 questions are directly related/
***[ISURU]***
  • ***[ISURU]***
So we must calculate energy need to change the heat of 200ml by 30 degree
***[ISURU]***
  • ***[ISURU]***
not just by one degree which is 840 J instead it should be 8.4*30 * 100 J which is 252*100 J and it also satisfy the condition of 3 digit ... try that one!
IsTim
  • IsTim
I've got 2 tries left. i'll test it out
***[ISURU]***
  • ***[ISURU]***
wt happened ?
IsTim
  • IsTim
err sorry. i'm asking this question on several different mediums, and i'm just 'cross referencing'
IsTim
  • IsTim
Err, 8.4*30 * 100 J looks like \[8.4*10*100\] 252*100 J looks like \[252*100\]
IsTim
  • IsTim
Because if that was true, wouldn't that make the question incorrect?
***[ISURU]***
  • ***[ISURU]***
srry.. could u explain it more ... it's not clear
IsTim
  • IsTim
The stars; do they represent the 'multiply' or the 'exponent' function?
***[ISURU]***
  • ***[ISURU]***
multiply
IsTim
  • IsTim
Ok. Thanks.

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