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IsTim

  • 2 years ago

In Part A, you determined that the heat added to the coffee is what you got. If it takes 4.2 J of energy to raise the temperature of 1.0 mL of coffee by 1.0∘C, then it should take twice as much energy to raise the temperature of 2.0 mL of coffee by 1.0∘C, or to raise the temperature of 1.0 mL of coffee by 2.0∘C. Multiply carefully to find the total amount of energy needed to raise the temperature of 200 mL of coffee by the required number of degrees.

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  1. IsTim
    • 2 years ago
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    This is a hint to an assignment I am currently doing.

  2. IsTim
    • 2 years ago
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    I haven't read thru the textbook much or my notes; I'ved tried, and instead made a formula sheet, although I don't know what formula to apply to this.

  3. ***[ISURU]***
    • 2 years ago
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    use \[E = mc \theta \] Since there r lot of data this one can be use easily ... I think u should be familiar with this...

  4. IsTim
    • 2 years ago
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    Actually, haven't seen this in my formula sheet. But I'll try it out.

  5. ***[ISURU]***
    • 2 years ago
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    wt's the value of "required no.of degrees" mentioned in the question ?

  6. IsTim
    • 2 years ago
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    1?

  7. ***[ISURU]***
    • 2 years ago
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    then I think u can use a relationship with ratios to solve this one cause the problem says "Multiply carefully to find " which mean question doesn't expect use of any formula instead it expect to build the answer from given data... change of 1 degree in 1ml = 4.2 J change of 1 degree in 2ml = 8.4 J change of 1 degree in 200 ml = 8.4*100 J

  8. IsTim
    • 2 years ago
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    These are the answers that I gave to the work, which it stated was incorrect. It requires 3 significant figures. Submitted Answers ANSWER 1: Deduction: -3% "what you get" = 8.4⋅102 J ANSWER 2: Deduction: -3% "what you get" = 8.40⋅102 J

  9. IsTim
    • 2 years ago
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    the 102 is suppose to be 10^2

  10. IsTim
    • 2 years ago
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    So yes, I did use your answer, but apparently it was incorrect here.

  11. ***[ISURU]***
    • 2 years ago
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    It requires 3 significant figures. = is it same for the 840 J ?

  12. IsTim
    • 2 years ago
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    wouldn't 8.40*10^3 J have worked?

  13. IsTim
    • 2 years ago
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    Because 840 is only 2 sig digs without using a decimal point

  14. ***[ISURU]***
    • 2 years ago
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    no .. I just told that 'cause it's the same answer I get even if I use E = mc*theta

  15. IsTim
    • 2 years ago
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    So, both answers would be considered incorrect with this question then?

  16. ***[ISURU]***
    • 2 years ago
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    @ganeshie8 , @thomaster

  17. IsTim
    • 2 years ago
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    I managed to get the question after that correct, if it helps at all.

  18. ***[ISURU]***
    • 2 years ago
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    if 840 J is wrong .... there is one possible reason: we calculate 840 J to a temp. change of 1 degree. But the question asks the energy need for a temp. change of required no. of degrees. And we assume that is also as 1 degree. But this question has a section name part A. Does that part mention about some reading of temperature regarding this coffee cup

  19. IsTim
    • 2 years ago
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    Yes. This is a 'hint' to a larger question.

  20. IsTim
    • 2 years ago
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    Suppose that you have left a 200-mL cup of coffee sitting until it has cooled to 30∘C , which you find totally unacceptable. Your microwave oven draws 1100 W of electrical power when it is running. If it takes 45 s for this microwave oven to raise the temperature of the coffee to 60∘C , what is the efficiency of heating with this oven? Find the efficiency e of the oven. You will need to use the fact that 4.2 J of energy is required to raise the temperature of 1.0 mL of coffee by 1.0∘C .

  21. ***[ISURU]***
    • 2 years ago
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    yo ... that's the missing point!

  22. IsTim
    • 2 years ago
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    ?

  23. ***[ISURU]***
    • 2 years ago
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    the temperature of the coffee cup was 30 degree at the beginning and it has to be increased up to 60 degree

  24. IsTim
    • 2 years ago
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    But I dunno if those 2 questions are directly related/

  25. ***[ISURU]***
    • 2 years ago
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    So we must calculate energy need to change the heat of 200ml by 30 degree

  26. ***[ISURU]***
    • 2 years ago
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    not just by one degree which is 840 J instead it should be 8.4*30 * 100 J which is 252*100 J and it also satisfy the condition of 3 digit ... try that one!

  27. IsTim
    • 2 years ago
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    I've got 2 tries left. i'll test it out

  28. ***[ISURU]***
    • 2 years ago
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    wt happened ?

  29. IsTim
    • 2 years ago
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    err sorry. i'm asking this question on several different mediums, and i'm just 'cross referencing'

  30. IsTim
    • 2 years ago
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    Err, 8.4*30 * 100 J looks like \[8.4*10*100\] 252*100 J looks like \[252*100\]

  31. IsTim
    • 2 years ago
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    Because if that was true, wouldn't that make the question incorrect?

  32. ***[ISURU]***
    • 2 years ago
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    srry.. could u explain it more ... it's not clear

  33. IsTim
    • 2 years ago
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    The stars; do they represent the 'multiply' or the 'exponent' function?

  34. ***[ISURU]***
    • 2 years ago
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    multiply

  35. IsTim
    • 2 years ago
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    Ok. Thanks.

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