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anonymous

  • 3 years ago

Solve v= p/2(c+L) for L

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  1. sasogeek
    • 3 years ago
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    do you have an idea what to do or have you tried something already?

  2. anonymous
    • 3 years ago
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    Well, I got |dw:1379882997265:dw| but it's incorrect

  3. sasogeek
    • 3 years ago
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    yeah, alright, let's fix this :)

  4. anonymous
    • 3 years ago
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    ok :)

  5. sasogeek
    • 3 years ago
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    Do you understand this? |dw:1379883062090:dw|

  6. anonymous
    • 3 years ago
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    Yes, so we get 2c+2L=p/v

  7. sasogeek
    • 3 years ago
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    yes, next step

  8. sasogeek
    • 3 years ago
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    Get it? |dw:1379883307166:dw|

  9. anonymous
    • 3 years ago
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    Yes.

  10. sasogeek
    • 3 years ago
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    alright, next step

  11. sasogeek
    • 3 years ago
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    Multiply both sides by 1/2, in other words, divide both sides by 2 |dw:1379883445598:dw|

  12. sasogeek
    • 3 years ago
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    made a mistake, one sec

  13. sasogeek
    • 3 years ago
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    |dw:1379883756318:dw|

  14. sasogeek
    • 3 years ago
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    get it?

  15. anonymous
    • 3 years ago
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    sure

  16. sasogeek
    • 3 years ago
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    alright, what do you think is the result?

  17. anonymous
    • 3 years ago
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    Okay, so we divied everything by 1/2

  18. sasogeek
    • 3 years ago
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    we multiply* everything by 1/2

  19. anonymous
    • 3 years ago
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    opps srry mistake. yes multiply

  20. sasogeek
    • 3 years ago
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    don't confuse the two statements. we multiply everything by 1/2, same as we divide everything by 2 :)

  21. sasogeek
    • 3 years ago
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    so what next?

  22. anonymous
    • 3 years ago
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    well now I am confused. wherre did the 1/2 come out of?

  23. sasogeek
    • 3 years ago
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    alright, here's what. \(\huge 1-1=0 \) do you agree?

  24. anonymous
    • 3 years ago
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    yes

  25. sasogeek
    • 3 years ago
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    alright, and do you know that, to move 1 to the other side of the equation, means to do this \(\huge 1-1+1=0+1 \) ?

  26. anonymous
    • 3 years ago
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    yes

  27. sasogeek
    • 3 years ago
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    alright, then you know that, whatever you do to the left side of an equation, you do the same to the right... yeah?

  28. anonymous
    • 3 years ago
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    ah okay so that's y you put the 1/2 in.

  29. sasogeek
    • 3 years ago
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    exactly, we put the half in initially to cancel out out the 2 in 2L, but once we multiply the left side by 1/2, we have to multiply the right side by 1/2 as well

  30. sasogeek
    • 3 years ago
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    do you understand now?

  31. anonymous
    • 3 years ago
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    okay so i got L= (1/2) p/v- (1/2)-2c

  32. sasogeek
    • 3 years ago
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    yup, can you simplify that?

  33. anonymous
    • 3 years ago
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    i dont know how I would simplify the 1/2's

  34. sasogeek
    • 3 years ago
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    alright, i'll help you out

  35. sasogeek
    • 3 years ago
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    you'll have this, because the 2's will cancel out |dw:1379884930249:dw|

  36. anonymous
    • 3 years ago
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    Thats what I got. Oh so I was rtight :)

  37. sasogeek
    • 3 years ago
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    you got the 2v up that's what was wrong lol :P the 2v must be down if you do it how i showed you

  38. anonymous
    • 3 years ago
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    okay thanks :)

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