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BulletProof Group Title

Solve v= p/2(c+L) for L

  • one year ago
  • one year ago

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  1. sasogeek Group Title
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    do you have an idea what to do or have you tried something already?

    • one year ago
  2. BulletProof Group Title
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    Well, I got |dw:1379882997265:dw| but it's incorrect

    • one year ago
  3. sasogeek Group Title
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    yeah, alright, let's fix this :)

    • one year ago
  4. BulletProof Group Title
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    ok :)

    • one year ago
  5. sasogeek Group Title
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    Do you understand this? |dw:1379883062090:dw|

    • one year ago
  6. BulletProof Group Title
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    Yes, so we get 2c+2L=p/v

    • one year ago
  7. sasogeek Group Title
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    yes, next step

    • one year ago
  8. sasogeek Group Title
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    Get it? |dw:1379883307166:dw|

    • one year ago
  9. BulletProof Group Title
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    Yes.

    • one year ago
  10. sasogeek Group Title
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    alright, next step

    • one year ago
  11. sasogeek Group Title
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    Multiply both sides by 1/2, in other words, divide both sides by 2 |dw:1379883445598:dw|

    • one year ago
  12. sasogeek Group Title
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    made a mistake, one sec

    • one year ago
  13. sasogeek Group Title
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    |dw:1379883756318:dw|

    • one year ago
  14. sasogeek Group Title
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    get it?

    • one year ago
  15. BulletProof Group Title
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    sure

    • one year ago
  16. sasogeek Group Title
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    alright, what do you think is the result?

    • one year ago
  17. BulletProof Group Title
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    Okay, so we divied everything by 1/2

    • one year ago
  18. sasogeek Group Title
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    we multiply* everything by 1/2

    • one year ago
  19. BulletProof Group Title
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    opps srry mistake. yes multiply

    • one year ago
  20. sasogeek Group Title
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    don't confuse the two statements. we multiply everything by 1/2, same as we divide everything by 2 :)

    • one year ago
  21. sasogeek Group Title
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    so what next?

    • one year ago
  22. BulletProof Group Title
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    well now I am confused. wherre did the 1/2 come out of?

    • one year ago
  23. sasogeek Group Title
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    alright, here's what. \(\huge 1-1=0 \) do you agree?

    • one year ago
  24. BulletProof Group Title
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    yes

    • one year ago
  25. sasogeek Group Title
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    alright, and do you know that, to move 1 to the other side of the equation, means to do this \(\huge 1-1+1=0+1 \) ?

    • one year ago
  26. BulletProof Group Title
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    yes

    • one year ago
  27. sasogeek Group Title
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    alright, then you know that, whatever you do to the left side of an equation, you do the same to the right... yeah?

    • one year ago
  28. BulletProof Group Title
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    ah okay so that's y you put the 1/2 in.

    • one year ago
  29. sasogeek Group Title
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    exactly, we put the half in initially to cancel out out the 2 in 2L, but once we multiply the left side by 1/2, we have to multiply the right side by 1/2 as well

    • one year ago
  30. sasogeek Group Title
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    do you understand now?

    • one year ago
  31. BulletProof Group Title
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    okay so i got L= (1/2) p/v- (1/2)-2c

    • one year ago
  32. sasogeek Group Title
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    yup, can you simplify that?

    • one year ago
  33. BulletProof Group Title
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    i dont know how I would simplify the 1/2's

    • one year ago
  34. sasogeek Group Title
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    alright, i'll help you out

    • one year ago
  35. sasogeek Group Title
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    you'll have this, because the 2's will cancel out |dw:1379884930249:dw|

    • one year ago
  36. BulletProof Group Title
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    Thats what I got. Oh so I was rtight :)

    • one year ago
  37. sasogeek Group Title
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    you got the 2v up that's what was wrong lol :P the 2v must be down if you do it how i showed you

    • one year ago
  38. BulletProof Group Title
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    okay thanks :)

    • one year ago
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