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bibas

  • one year ago

Two fair dice are rolled. Let X be the difference between the numbers showing on the two dice. Find its pdf pX.? collage statistics , can u please show work

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  1. DebbieG
    • one year ago
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    Well, think about your sample space. there are 6^2=36 possible combinations of rolls (some have the same numbers showing). The possible outcomes (the difference between the numbers showing on the dice) are 0, 1, 2, 3, 4, 5. So you need to figure out the probability for each of the 6 outcomes, which is the number of ways that outcome can occur / 36 E.g. for X=0 you have the following rolls: 1, 1 2, 2 3, 3 4, 4 5, 5 6, 6 So P(0)=6/36 = 1/6 Now consider the possibilities for each of the other values for X, 1 - 5.

  2. DebbieG
    • one year ago
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    For X=1: 1, 2 2, 1 2, 3 3, 2 3, 4 4, 3 4, 5 5, 4 5, 6 6, 5 So P(1)=10/36 = 5/18 Remember, when you have done all the possible outcomes, the probabilities should sum to 1.

  3. bibas
    • one year ago
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    thanks

  4. bibas
    • one year ago
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    so up to how money time

  5. DebbieG
    • one year ago
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    what???

  6. bibas
    • one year ago
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    no i mean to do the sum do i have to to next steps is with 2 then 3, 4, 5, 6 or just stop in 5th

  7. DebbieG
    • one year ago
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    Your random variable X is "the difference between the numbers showing on the two dice". You can't roll 2 dice and have a difference of 6 (since you cant roll anything less than 1 or higher than 6). So you need to find the probabilities for 0, 1, 3, 4, and 5. I did the first two for you.

  8. bibas
    • one year ago
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    ok thanks so much i get the idea now

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