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bibas

  • 2 years ago

Two fair dice are rolled. Let X be the difference between the numbers showing on the two dice. Find its pdf pX.? collage statistics , can u please show work

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  1. DebbieG
    • 2 years ago
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    Well, think about your sample space. there are 6^2=36 possible combinations of rolls (some have the same numbers showing). The possible outcomes (the difference between the numbers showing on the dice) are 0, 1, 2, 3, 4, 5. So you need to figure out the probability for each of the 6 outcomes, which is the number of ways that outcome can occur / 36 E.g. for X=0 you have the following rolls: 1, 1 2, 2 3, 3 4, 4 5, 5 6, 6 So P(0)=6/36 = 1/6 Now consider the possibilities for each of the other values for X, 1 - 5.

  2. DebbieG
    • 2 years ago
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    For X=1: 1, 2 2, 1 2, 3 3, 2 3, 4 4, 3 4, 5 5, 4 5, 6 6, 5 So P(1)=10/36 = 5/18 Remember, when you have done all the possible outcomes, the probabilities should sum to 1.

  3. bibas
    • 2 years ago
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    thanks

  4. bibas
    • 2 years ago
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    so up to how money time

  5. DebbieG
    • 2 years ago
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    what???

  6. bibas
    • 2 years ago
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    no i mean to do the sum do i have to to next steps is with 2 then 3, 4, 5, 6 or just stop in 5th

  7. DebbieG
    • 2 years ago
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    Your random variable X is "the difference between the numbers showing on the two dice". You can't roll 2 dice and have a difference of 6 (since you cant roll anything less than 1 or higher than 6). So you need to find the probabilities for 0, 1, 3, 4, and 5. I did the first two for you.

  8. bibas
    • 2 years ago
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    ok thanks so much i get the idea now

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