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bibas

Two fair dice are rolled. Let X be the difference between the numbers showing on the two dice. Find its pdf pX.? collage statistics , can u please show work

  • 6 months ago
  • 6 months ago

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  1. DebbieG
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    Well, think about your sample space. there are 6^2=36 possible combinations of rolls (some have the same numbers showing). The possible outcomes (the difference between the numbers showing on the dice) are 0, 1, 2, 3, 4, 5. So you need to figure out the probability for each of the 6 outcomes, which is the number of ways that outcome can occur / 36 E.g. for X=0 you have the following rolls: 1, 1 2, 2 3, 3 4, 4 5, 5 6, 6 So P(0)=6/36 = 1/6 Now consider the possibilities for each of the other values for X, 1 - 5.

    • 6 months ago
  2. DebbieG
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    For X=1: 1, 2 2, 1 2, 3 3, 2 3, 4 4, 3 4, 5 5, 4 5, 6 6, 5 So P(1)=10/36 = 5/18 Remember, when you have done all the possible outcomes, the probabilities should sum to 1.

    • 6 months ago
  3. bibas
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    thanks

    • 6 months ago
  4. bibas
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    so up to how money time

    • 6 months ago
  5. DebbieG
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    what???

    • 6 months ago
  6. bibas
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    no i mean to do the sum do i have to to next steps is with 2 then 3, 4, 5, 6 or just stop in 5th

    • 6 months ago
  7. DebbieG
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    Your random variable X is "the difference between the numbers showing on the two dice". You can't roll 2 dice and have a difference of 6 (since you cant roll anything less than 1 or higher than 6). So you need to find the probabilities for 0, 1, 3, 4, and 5. I did the first two for you.

    • 6 months ago
  8. bibas
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    ok thanks so much i get the idea now

    • 6 months ago
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