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KatieG123

  • 2 years ago

let f(x)= sin (2x) give the value of lim as h approaches 0; f(h) - f (0)/h

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  1. iouri.gordon
    • 2 years ago
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    are you asking for \[\lim_{h \rightarrow 0}(\sin2h-\sin0)/h\] ?

  2. iaru2
    • 2 years ago
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    We Know the fact that \[\lim_{x \rightarrow 0}\frac{ \sin x }{ x } = 1\] to use this equation, transform formulus. \[\lim_{h \rightarrow 0}\frac{ \sin 2h }{2h } * 2 \] now, you result in solution.

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