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iouri.gordon
 one year ago
Best ResponseYou've already chosen the best response.0are you asking for \[\lim_{h \rightarrow 0}(\sin2h\sin0)/h\] ?

iaru2
 one year ago
Best ResponseYou've already chosen the best response.0We Know the fact that \[\lim_{x \rightarrow 0}\frac{ \sin x }{ x } = 1\] to use this equation, transform formulus. \[\lim_{h \rightarrow 0}\frac{ \sin 2h }{2h } * 2 \] now, you result in solution.
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