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ihatemath33
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show that
not(pvq) v (not p^q) v not(not p^not q) is logically equivalent to: not(p^not q)
 one year ago
 one year ago
ihatemath33 Group Title
show that not(pvq) v (not p^q) v not(not p^not q) is logically equivalent to: not(p^not q)
 one year ago
 one year ago

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Loser66 Group TitleBest ResponseYou've already chosen the best response.1
the easiest way is make truth table, hehehe.. a little bit annoyed but surely you get the answer
 one year ago
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