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anonymous
 3 years ago
The graph of f(x)=1/x^2c has a vertical asymptote at x=3. Find c. PreCalculus help please
anonymous
 3 years ago
The graph of f(x)=1/x^2c has a vertical asymptote at x=3. Find c. PreCalculus help please

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0tell me if 1/x^2c is a fraction form?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes it is in fraction form, 1 on top and x^2c on the bottom

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is calculus y do u want to find c

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't know... It confuses me... This is more of an algebra question than calculus.. and I sucked at algebra....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i cant find c with f(x) thingie

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay.. Thanks anyway :)

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2If f has a vertical asymptote at x=3, then that means the function shouldn't exist at x=3. The function doesn't exist when the fraction doesn't exist. The fraction doesn't exist when the denominator is 0 (when the bottom is 0). When is x^2c equal to 0? And since the vertical asymptote is at x=3 then we no 3^2c equal to 0 will give us a value of c that makes the function undefined at x=3.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2know not no (darn it)

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Yep! That would give us f(x)=1/(x^29) As you can see this function does not exist at x=3 (or x=3 <but whatever :p)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Awesome!! Thanks a million!!! Do you think you could help me with this one too? Find the equation of the slant asymptote for the graph of y=\[y=\frac{ 3x ^{2}+2x3 }{ x1 }\] @myininaya

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2All you really need to do is divide.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I know I have to turn it into a division problem.. But after that I'm not sure... Because the long division with Xs confuses me..

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2If you can do the division correctly and if the numerator is 1 degree higher than the numerator, then the slant asymptote will be the quotient.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1379947728986:dw

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2how many times does x go into 3x^2?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.23x^2/x=3xx/x What cancels?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2So you are left with just 3x right?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Since 3x^2/x=3x, then 3x is the amount of times x goes into 3x^2. So we put this up on top of that little half rectangle thing (or division problem). dw:1379948010561:dw Take that number we just wrote and multiply it by (x1) to find out how much remains.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wouldn't 3x times x1 be 3x^22x?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.23x(x1)=3x(x)3x(1) =3x^23x

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1379948242687:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh okay, then I subtract that by 3x^2+2x and get 1x don't I?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ugh the signs mess me up.. it would be 6

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Still no. 2(3)=2+3=5

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1379948443191:dw

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1379948484905:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Gah! I'm multiplying when I should be adding >_< okay so now you bring down the 3 and have 5x3

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Yes. Now you can still do x into 5x how many times? Or what is 5x/x=?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Right. So we have dw:1379948593951:dw

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Now you could finish it out, right? 5 times (x1)

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Yes so we have dw:1379948698015:dw Tell me what is remaining?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.08 is remaining, so my answer would be 3x+5+8? Could I combine them and make it 3x+13?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2no no... 3(5)=3+5=2 This means we can stop with the division since there are no x's in 2. Also this means that \[\frac{3x^2+2x3}{x1}=3x+5+\frac{2}{x1}\] But as goes to infinity 2/(x1) goes to zero which means our slant asymptote is just the quotient (3x+5).

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2as x goes to infinity*

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ugh I'm bad at this... So my answer would be 3x+5?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Do you want to try one?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Find the slant asymptote for \[g(x)=\frac{x^3+2x^2+5x+1}{x^2+1}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Awesome, thank you sooooo much for helping me out and putting up with me this long.. It's muchly appreciated! Okay so first I would put it in division form... \[x ^{2}+1\div x ^{3}+2x ^{2}+5x+1\]

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2\[(x^3+2x^2+5x+1) \div (x^2+1)\] But were you trying to write dw:1379949456171:dw Also you can reply using my picture. (You can click my picture in the upper right hand corner and should be able to use it) It is not any trouble for me. I'm doing this because I just want to.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Err... My picture doesn't show the +1. Do you see everything?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah I can see all of it, yeah that's what I was trying to put.. dw:1379950041284:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1379950178748:dw

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1379950290680:dw You might want to align your like terms so you don't forget which one you should be subtracting from.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1379950632494:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wait I'm confused.. why is the x under the 5x?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Because we are putting our like terms together

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2We are doing (x^3+2x^2+5x+1)(x^3+x) =x^3+2x^2+5x+1x^3x =x^3x^3+2x^2+5xx+1 =(x^3x^3)+2x^2+(5xx)+1 =(0)+2x^2+(4x)+1 =2x^2+4x+1

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2You only combine like terms.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh okay gotcha so do I bring to 2x^2 down when I subtract?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2If you want you can put 0 placeholders in there dw:1379951194918:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1379951263384:dw So like this?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1379951375025:dw And I can't see the plus one but we also need to bring him down The reason I change your 4 to a +4 is because 51=4 not 4.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ah okay, makes sense dw:1379951489180:dw is this right?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2also did you put a 2 under the 1(my screen is cutting the picture off)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes it is +2 on top. No I didn't, I see why I need to thoughdw:1379952081201:dw

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2Tell me what you got for the remainder?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2That part is cut off for me.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.2It should be 4x1 is the remainder. Yes. And we know there are no x^2's in 4x so we are done. \[\frac{x^3+2x^2+5x+1}{x^2+1}=x+2+\frac{4x1}{x^2+1}\] Since that R/(x^2+1) goes to 0 then y=x+2 is the slant asymptote. As long as R/D goes to O, then y=Q will be the slant asymptote. This will happen with we have the numerator is 1 degree higher than the denominator. deg(x^3+2x+5x+1)=3 deg(x^2+1)=2 3 is 1 more than 2 so there is a slant asmyptote for (x^3+2x^2+5x+1)/(x^2+1) and it is y=x+2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah that's what I got ^^

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yep! Thanks for the help! :D
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