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The graph of f(x)=1/x^2c has a vertical asymptote at x=3. Find c. PreCalculus help please
 7 months ago
 7 months ago
The graph of f(x)=1/x^2c has a vertical asymptote at x=3. Find c. PreCalculus help please
 7 months ago
 7 months ago

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samsterzBest ResponseYou've already chosen the best response.0
tell me if 1/x^2c is a fraction form?
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Yes it is in fraction form, 1 on top and x^2c on the bottom
 7 months ago

samsterzBest ResponseYou've already chosen the best response.0
this is calculus y do u want to find c
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
I don't know... It confuses me... This is more of an algebra question than calculus.. and I sucked at algebra....
 7 months ago

samsterzBest ResponseYou've already chosen the best response.0
i cant find c with f(x) thingie
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Okay.. Thanks anyway :)
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
If f has a vertical asymptote at x=3, then that means the function shouldn't exist at x=3. The function doesn't exist when the fraction doesn't exist. The fraction doesn't exist when the denominator is 0 (when the bottom is 0). When is x^2c equal to 0? And since the vertical asymptote is at x=3 then we no 3^2c equal to 0 will give us a value of c that makes the function undefined at x=3.
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
know not no (darn it)
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Yep! That would give us f(x)=1/(x^29) As you can see this function does not exist at x=3 (or x=3 <but whatever :p)
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Awesome!! Thanks a million!!! Do you think you could help me with this one too? Find the equation of the slant asymptote for the graph of y=\[y=\frac{ 3x ^{2}+2x3 }{ x1 }\] @myininaya
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
All you really need to do is divide.
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
I know I have to turn it into a division problem.. But after that I'm not sure... Because the long division with Xs confuses me..
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
If you can do the division correctly and if the numerator is 1 degree higher than the numerator, then the slant asymptote will be the quotient.
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
dw:1379947728986:dw
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
how many times does x go into 3x^2?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
3x^2/x=3xx/x What cancels?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
So you are left with just 3x right?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Since 3x^2/x=3x, then 3x is the amount of times x goes into 3x^2. So we put this up on top of that little half rectangle thing (or division problem). dw:1379948010561:dw Take that number we just wrote and multiply it by (x1) to find out how much remains.
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Wouldn't 3x times x1 be 3x^22x?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
3x(x1)=3x(x)3x(1) =3x^23x
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
dw:1379948242687:dw
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Oh okay, then I subtract that by 3x^2+2x and get 1x don't I?
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Ugh the signs mess me up.. it would be 6
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Still no. 2(3)=2+3=5
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
dw:1379948443191:dw
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
dw:1379948484905:dw
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Gah! I'm multiplying when I should be adding >_< okay so now you bring down the 3 and have 5x3
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Yes. Now you can still do x into 5x how many times? Or what is 5x/x=?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Right. So we have dw:1379948593951:dw
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Now you could finish it out, right? 5 times (x1)
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Yes so we have dw:1379948698015:dw Tell me what is remaining?
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
8 is remaining, so my answer would be 3x+5+8? Could I combine them and make it 3x+13?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
no no... 3(5)=3+5=2 This means we can stop with the division since there are no x's in 2. Also this means that \[\frac{3x^2+2x3}{x1}=3x+5+\frac{2}{x1}\] But as goes to infinity 2/(x1) goes to zero which means our slant asymptote is just the quotient (3x+5).
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
as x goes to infinity*
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Ugh I'm bad at this... So my answer would be 3x+5?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Do you want to try one?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Find the slant asymptote for \[g(x)=\frac{x^3+2x^2+5x+1}{x^2+1}\]
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Awesome, thank you sooooo much for helping me out and putting up with me this long.. It's muchly appreciated! Okay so first I would put it in division form... \[x ^{2}+1\div x ^{3}+2x ^{2}+5x+1\]
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
\[(x^3+2x^2+5x+1) \div (x^2+1)\] But were you trying to write dw:1379949456171:dw Also you can reply using my picture. (You can click my picture in the upper right hand corner and should be able to use it) It is not any trouble for me. I'm doing this because I just want to.
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Err... My picture doesn't show the +1. Do you see everything?
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Yeah I can see all of it, yeah that's what I was trying to put.. dw:1379950041284:dw
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
dw:1379950178748:dw
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
dw:1379950290680:dw You might want to align your like terms so you don't forget which one you should be subtracting from.
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
dw:1379950632494:dw
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Wait I'm confused.. why is the x under the 5x?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Because we are putting our like terms together
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
We are doing (x^3+2x^2+5x+1)(x^3+x) =x^3+2x^2+5x+1x^3x =x^3x^3+2x^2+5xx+1 =(x^3x^3)+2x^2+(5xx)+1 =(0)+2x^2+(4x)+1 =2x^2+4x+1
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
You only combine like terms.
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Oh okay gotcha so do I bring to 2x^2 down when I subtract?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
If you want you can put 0 placeholders in there dw:1379951194918:dw
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
dw:1379951263384:dw So like this?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
dw:1379951375025:dw And I can't see the plus one but we also need to bring him down The reason I change your 4 to a +4 is because 51=4 not 4.
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Ah okay, makes sense dw:1379951489180:dw is this right?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
is that +2 up there?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
also did you put a 2 under the 1(my screen is cutting the picture off)
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Yes it is +2 on top. No I didn't, I see why I need to thoughdw:1379952081201:dw
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Tell me what you got for the remainder?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
That part is cut off for me.
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
It should be 4x1 is the remainder. Yes. And we know there are no x^2's in 4x so we are done. \[\frac{x^3+2x^2+5x+1}{x^2+1}=x+2+\frac{4x1}{x^2+1}\] Since that R/(x^2+1) goes to 0 then y=x+2 is the slant asymptote. As long as R/D goes to O, then y=Q will be the slant asymptote. This will happen with we have the numerator is 1 degree higher than the denominator. deg(x^3+2x+5x+1)=3 deg(x^2+1)=2 3 is 1 more than 2 so there is a slant asmyptote for (x^3+2x^2+5x+1)/(x^2+1) and it is y=x+2
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Yeah that's what I got ^^
 7 months ago

CollieBeanBest ResponseYou've already chosen the best response.0
Yep! Thanks for the help! :D
 7 months ago
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