Hey, Quick help Please: Transform the given IVP into an equivalent problem with the initial pt. at the origin. \(\frac{dy}{dt}=t^2+y^2\) (I know it's easy... I'm just having a brain fart)

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put it in the form \(y'-t^2=y^2\)

whoops forgot the IV \(y(1)=2\)

I need a little more please @abb0t ... It's not my ODE type of day

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