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ganeshie8Best ResponseYou've already chosen the best response.1
plugin the numbers into the given equation ?
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
\(\large \sqrt{xy} + m = d\)
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
y is last two digits of ur birth year (u may fake if u want ;) ) m is month d is day
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
wat do u get for the equation ?
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
I can't get the answer .. I don't know how to work this out ! :(
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
if u can show me wat do u have... maybe i can help :)
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
did u plugin the values in equation ?
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
I don't know how to work it out .. Like I don't know where to start . I'm not good with radicals . All I did was try to find a way to work it out online but I couldn't find anything to help . Do I start with what's in the radical ?
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
nope, have u read the question ? it wants u to put ur date of birth in the given equation, and solve x
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
\(\large \sqrt{xy} + m = d\) ^
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
put the year u born in that place
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
Don't I use the values given in the question ?
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
Ohhh nevermind , I just read the question wrong . My bad
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
No, those values are for ur great great grandpa Nikola Tesla.... they're not urs lol
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
Okay so I was born in 96
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
\(\large \sqrt{x96} + m = d\) ^
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
there it goes ! wat about month and date
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
i feel like im interviewing u lol
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
Haha month is 4 and day is 22
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
thanks for giving it one shot :)
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
\(\large \sqrt{x96} + 4 = 22\)
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
Alright so now what to do :o
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
start by subtracting 4 both sides
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\)
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
Yes ! next, square both sides
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
You mean square 96 and 18 ?? :o
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\) square both sides \(\large (\sqrt{x96})^2 = (18)^2\)
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
since u r not happy wid radical, we're killing it by squaring both sides !
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\) square both sides \(\large (\sqrt{x96})^2 = (18)^2\) \(\large x96 = 324\)
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
wats our next step ?
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
Add 96 to both sides ?
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
Okay so that would be 420 ? (;
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
Yay :D So that's the answer , correct ? Now what does it mean when it asks if the solution is extraneous ?? :o
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
oh, it asks to check if the solution is extraneous or now.
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
Yeah , I don't know what that means .
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
its very easy to check, simply put the solution u got for x in the original (ur bday ) equaiton
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
ur bday equation : \(\large \sqrt{x96} + 4 = 22\) put x = 420 here, IF this satisfies this equation, then its NOT an extraneous solution.
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
I worked it out and I got 420=324 :o
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
careful, check again
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
But that's not true , so does that mean the solution IS extraneous ?
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
i want u check again,
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\)
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\)
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\)
 6 months ago

LaynaMaeBest ResponseYou've already chosen the best response.1
Ohhhh okay ! That makes more sense !
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\) \(\large 22 = 22\) TRUE, so x=420 is NOT an extraneous solution.
 6 months ago
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