A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 3 years ago

HELP PLEASE !! Medal will be rewarded !

  • This Question is Closed
  1. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  2. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    plugin the numbers into the given equation ?

  3. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\large \sqrt{x-y} + m = d\)

  4. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    y is last two digits of ur birth year (u may fake if u want ;) ) m is month d is day

  5. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay

  6. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    wat do u get for the equation ?

  7. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Let me work it out

  8. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    okie

  9. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I can't get the answer .. I don't know how to work this out ! :(

  10. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if u can show me wat do u have... maybe i can help :)

  11. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    did u plugin the values in equation ?

  12. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't know how to work it out .. Like I don't know where to start . I'm not good with radicals . All I did was try to find a way to work it out online but I couldn't find anything to help . Do I start with what's in the radical ?

  13. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    nope, have u read the question ? it wants u to put ur date of birth in the given equation, and solve x

  14. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\large \sqrt{x-y} + m = d\) ^

  15. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay

  16. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    put the year u born in that place

  17. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    which year ?

  18. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Don't I use the values given in the question ?

  19. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ohhh nevermind , I just read the question wrong . My bad

  20. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    No, those values are for ur great great grandpa Nikola Tesla.... they're not urs lol

  21. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    cool :)

  22. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay so I was born in 96

  23. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\large \sqrt{x-96} + m = d\) ^

  24. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    there it goes ! wat about month and date

  25. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i feel like im interviewing u lol

  26. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Haha month is 4 and day is 22

  27. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    thanks for giving it one shot :)

  28. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\large \sqrt{x-96} + 4 = 22\)

  29. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Alright so now what to do :o

  30. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    solve for x

  31. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    start by subtracting 4 both sides

  32. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay

  33. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\)

  34. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    18

  35. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes ! next, square both sides

  36. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You mean square 96 and 18 ?? :o

  37. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\) square both sides \(\large (\sqrt{x-96})^2 = (18)^2\)

  38. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    like this..

  39. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    since u r not happy wid radical, we're killing it by squaring both sides !

  40. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\) square both sides \(\large (\sqrt{x-96})^2 = (18)^2\) \(\large x-96 = 324\)

  41. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh okay !

  42. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    wats our next step ?

  43. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Add 96 to both sides ?

  44. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    thats it !

  45. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay so that would be 420 ? (;

  46. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes ! good job !!

  47. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yay :D So that's the answer , correct ? Now what does it mean when it asks if the solution is extraneous ?? :o

  48. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh, it asks to check if the solution is extraneous or now.

  49. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    *not

  50. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yeah , I don't know what that means .

  51. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    its very easy to check, simply put the solution u got for x in the original (ur bday ) equaiton

  52. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Alright

  53. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ur bday equation :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 here, IF this satisfies this equation, then its NOT an extraneous solution.

  54. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I worked it out and I got 420=324 :o

  55. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    careful, check again

  56. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    But that's not true , so does that mean the solution IS extraneous ?

  57. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh okay ..

  58. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i want u check again,

  59. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\)

  60. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Right

  61. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\)

  62. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\)

  63. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ohhhh okay ! That makes more sense !

  64. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    THANK YOU

  65. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\) \(\large 22 = 22\) TRUE, so x=420 is NOT an extraneous solution.

  66. ganeshie8
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    np :) yw !

  67. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.