## anonymous 2 years ago HELP PLEASE !! Medal will be rewarded !

1. anonymous

2. ganeshie8

plugin the numbers into the given equation ?

3. ganeshie8

$$\large \sqrt{x-y} + m = d$$

4. ganeshie8

y is last two digits of ur birth year (u may fake if u want ;) ) m is month d is day

5. anonymous

Okay

6. ganeshie8

wat do u get for the equation ?

7. anonymous

Let me work it out

8. ganeshie8

okie

9. anonymous

I can't get the answer .. I don't know how to work this out ! :(

10. ganeshie8

if u can show me wat do u have... maybe i can help :)

11. ganeshie8

did u plugin the values in equation ?

12. anonymous

I don't know how to work it out .. Like I don't know where to start . I'm not good with radicals . All I did was try to find a way to work it out online but I couldn't find anything to help . Do I start with what's in the radical ?

13. ganeshie8

nope, have u read the question ? it wants u to put ur date of birth in the given equation, and solve x

14. ganeshie8

$$\large \sqrt{x-y} + m = d$$ ^

15. anonymous

Okay

16. ganeshie8

put the year u born in that place

17. ganeshie8

which year ?

18. anonymous

Don't I use the values given in the question ?

19. anonymous

Ohhh nevermind , I just read the question wrong . My bad

20. ganeshie8

No, those values are for ur great great grandpa Nikola Tesla.... they're not urs lol

21. ganeshie8

cool :)

22. anonymous

Okay so I was born in 96

23. ganeshie8

$$\large \sqrt{x-96} + m = d$$ ^

24. ganeshie8

there it goes ! wat about month and date

25. ganeshie8

i feel like im interviewing u lol

26. anonymous

Haha month is 4 and day is 22

27. ganeshie8

thanks for giving it one shot :)

28. ganeshie8

$$\large \sqrt{x-96} + 4 = 22$$

29. anonymous

Alright so now what to do :o

30. ganeshie8

solve for x

31. ganeshie8

start by subtracting 4 both sides

32. anonymous

Okay

33. ganeshie8

$$\large \sqrt{x-96} + 4 = 22$$ subtract 4 both sides $$\large \sqrt{x-96} = 18$$

34. anonymous

18

35. ganeshie8

Yes ! next, square both sides

36. anonymous

You mean square 96 and 18 ?? :o

37. ganeshie8

$$\large \sqrt{x-96} + 4 = 22$$ subtract 4 both sides $$\large \sqrt{x-96} = 18$$ square both sides $$\large (\sqrt{x-96})^2 = (18)^2$$

38. ganeshie8

like this..

39. ganeshie8

since u r not happy wid radical, we're killing it by squaring both sides !

40. ganeshie8

$$\large \sqrt{x-96} + 4 = 22$$ subtract 4 both sides $$\large \sqrt{x-96} = 18$$ square both sides $$\large (\sqrt{x-96})^2 = (18)^2$$ $$\large x-96 = 324$$

41. anonymous

Oh okay !

42. ganeshie8

wats our next step ?

43. anonymous

Add 96 to both sides ?

44. ganeshie8

thats it !

45. anonymous

Okay so that would be 420 ? (;

46. ganeshie8

Yes ! good job !!

47. anonymous

Yay :D So that's the answer , correct ? Now what does it mean when it asks if the solution is extraneous ?? :o

48. ganeshie8

oh, it asks to check if the solution is extraneous or now.

49. ganeshie8

*not

50. anonymous

Yeah , I don't know what that means .

51. ganeshie8

its very easy to check, simply put the solution u got for x in the original (ur bday ) equaiton

52. anonymous

Alright

53. ganeshie8

ur bday equation :- $$\large \sqrt{x-96} + 4 = 22$$ put x = 420 here, IF this satisfies this equation, then its NOT an extraneous solution.

54. anonymous

I worked it out and I got 420=324 :o

55. ganeshie8

careful, check again

56. anonymous

But that's not true , so does that mean the solution IS extraneous ?

57. anonymous

Oh okay ..

58. ganeshie8

i want u check again,

59. ganeshie8

Checking if x=420 is extraneous solution or not :- $$\large \sqrt{x-96} + 4 = 22$$ put x = 420 $$\large \sqrt{420-96} + 4 = 22$$

60. anonymous

Right

61. ganeshie8

Checking if x=420 is extraneous solution or not :- $$\large \sqrt{x-96} + 4 = 22$$ put x = 420 $$\large \sqrt{420-96} + 4 = 22$$ $$\large \sqrt{324} + 4 = 22$$

62. ganeshie8

Checking if x=420 is extraneous solution or not :- $$\large \sqrt{x-96} + 4 = 22$$ put x = 420 $$\large \sqrt{420-96} + 4 = 22$$ $$\large \sqrt{324} + 4 = 22$$ $$\large 18 + 4 = 22$$

63. anonymous

Ohhhh okay ! That makes more sense !

64. anonymous

THANK YOU

65. ganeshie8

Checking if x=420 is extraneous solution or not :- $$\large \sqrt{x-96} + 4 = 22$$ put x = 420 $$\large \sqrt{420-96} + 4 = 22$$ $$\large \sqrt{324} + 4 = 22$$ $$\large 18 + 4 = 22$$ $$\large 22 = 22$$ TRUE, so x=420 is NOT an extraneous solution.

66. ganeshie8

np :) yw !