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anonymous
 3 years ago
HELP PLEASE !! Medal will be rewarded !
anonymous
 3 years ago
HELP PLEASE !! Medal will be rewarded !

This Question is Closed

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1plugin the numbers into the given equation ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{xy} + m = d\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1y is last two digits of ur birth year (u may fake if u want ;) ) m is month d is day

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1wat do u get for the equation ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I can't get the answer .. I don't know how to work this out ! :(

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1if u can show me wat do u have... maybe i can help :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1did u plugin the values in equation ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't know how to work it out .. Like I don't know where to start . I'm not good with radicals . All I did was try to find a way to work it out online but I couldn't find anything to help . Do I start with what's in the radical ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1nope, have u read the question ? it wants u to put ur date of birth in the given equation, and solve x

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{xy} + m = d\) ^

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1put the year u born in that place

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Don't I use the values given in the question ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ohhh nevermind , I just read the question wrong . My bad

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1No, those values are for ur great great grandpa Nikola Tesla.... they're not urs lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay so I was born in 96

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{x96} + m = d\) ^

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1there it goes ! wat about month and date

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1i feel like im interviewing u lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Haha month is 4 and day is 22

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1thanks for giving it one shot :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{x96} + 4 = 22\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Alright so now what to do :o

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1start by subtracting 4 both sides

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1Yes ! next, square both sides

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You mean square 96 and 18 ?? :o

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\) square both sides \(\large (\sqrt{x96})^2 = (18)^2\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1since u r not happy wid radical, we're killing it by squaring both sides !

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\) square both sides \(\large (\sqrt{x96})^2 = (18)^2\) \(\large x96 = 324\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Add 96 to both sides ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay so that would be 420 ? (;

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yay :D So that's the answer , correct ? Now what does it mean when it asks if the solution is extraneous ?? :o

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1oh, it asks to check if the solution is extraneous or now.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah , I don't know what that means .

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1its very easy to check, simply put the solution u got for x in the original (ur bday ) equaiton

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1ur bday equation : \(\large \sqrt{x96} + 4 = 22\) put x = 420 here, IF this satisfies this equation, then its NOT an extraneous solution.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I worked it out and I got 420=324 :o

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But that's not true , so does that mean the solution IS extraneous ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1i want u check again,

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ohhhh okay ! That makes more sense !

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\) \(\large 22 = 22\) TRUE, so x=420 is NOT an extraneous solution.
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