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ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
plugin the numbers into the given equation ?
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large \sqrt{xy} + m = d\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y is last two digits of ur birth year (u may fake if u want ;) ) m is month d is day
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
wat do u get for the equation ?
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Let me work it out
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
I can't get the answer .. I don't know how to work this out ! :(
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
if u can show me wat do u have... maybe i can help :)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
did u plugin the values in equation ?
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
I don't know how to work it out .. Like I don't know where to start . I'm not good with radicals . All I did was try to find a way to work it out online but I couldn't find anything to help . Do I start with what's in the radical ?
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
nope, have u read the question ? it wants u to put ur date of birth in the given equation, and solve x
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large \sqrt{xy} + m = d\) ^
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
put the year u born in that place
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
which year ?
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Don't I use the values given in the question ?
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Ohhh nevermind , I just read the question wrong . My bad
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
No, those values are for ur great great grandpa Nikola Tesla.... they're not urs lol
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
cool :)
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Okay so I was born in 96
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large \sqrt{x96} + m = d\) ^
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
there it goes ! wat about month and date
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
i feel like im interviewing u lol
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Haha month is 4 and day is 22
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
thanks for giving it one shot :)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large \sqrt{x96} + 4 = 22\)
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Alright so now what to do :o
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
solve for x
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
start by subtracting 4 both sides
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
Yes ! next, square both sides
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
You mean square 96 and 18 ?? :o
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\) square both sides \(\large (\sqrt{x96})^2 = (18)^2\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
like this..
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
since u r not happy wid radical, we're killing it by squaring both sides !
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\) square both sides \(\large (\sqrt{x96})^2 = (18)^2\) \(\large x96 = 324\)
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Oh okay !
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
wats our next step ?
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Add 96 to both sides ?
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
thats it !
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Okay so that would be 420 ? (;
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
Yes ! good job !!
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Yay :D So that's the answer , correct ? Now what does it mean when it asks if the solution is extraneous ?? :o
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
oh, it asks to check if the solution is extraneous or now.
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Yeah , I don't know what that means .
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
its very easy to check, simply put the solution u got for x in the original (ur bday ) equaiton
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
ur bday equation : \(\large \sqrt{x96} + 4 = 22\) put x = 420 here, IF this satisfies this equation, then its NOT an extraneous solution.
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
I worked it out and I got 420=324 :o
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
careful, check again
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
But that's not true , so does that mean the solution IS extraneous ?
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Oh okay ..
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
i want u check again,
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\)
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
Ohhhh okay ! That makes more sense !
 10 months ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.1
THANK YOU
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\) \(\large 22 = 22\) TRUE, so x=420 is NOT an extraneous solution.
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
np :) yw !
 10 months ago
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