anonymous
  • anonymous
HELP PLEASE !! Medal will be rewarded !
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
1 Attachment
ganeshie8
  • ganeshie8
plugin the numbers into the given equation ?
ganeshie8
  • ganeshie8
\(\large \sqrt{x-y} + m = d\)

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ganeshie8
  • ganeshie8
y is last two digits of ur birth year (u may fake if u want ;) ) m is month d is day
anonymous
  • anonymous
Okay
ganeshie8
  • ganeshie8
wat do u get for the equation ?
anonymous
  • anonymous
Let me work it out
ganeshie8
  • ganeshie8
okie
anonymous
  • anonymous
I can't get the answer .. I don't know how to work this out ! :(
ganeshie8
  • ganeshie8
if u can show me wat do u have... maybe i can help :)
ganeshie8
  • ganeshie8
did u plugin the values in equation ?
anonymous
  • anonymous
I don't know how to work it out .. Like I don't know where to start . I'm not good with radicals . All I did was try to find a way to work it out online but I couldn't find anything to help . Do I start with what's in the radical ?
ganeshie8
  • ganeshie8
nope, have u read the question ? it wants u to put ur date of birth in the given equation, and solve x
ganeshie8
  • ganeshie8
\(\large \sqrt{x-y} + m = d\) ^
anonymous
  • anonymous
Okay
ganeshie8
  • ganeshie8
put the year u born in that place
ganeshie8
  • ganeshie8
which year ?
anonymous
  • anonymous
Don't I use the values given in the question ?
anonymous
  • anonymous
Ohhh nevermind , I just read the question wrong . My bad
ganeshie8
  • ganeshie8
No, those values are for ur great great grandpa Nikola Tesla.... they're not urs lol
ganeshie8
  • ganeshie8
cool :)
anonymous
  • anonymous
Okay so I was born in 96
ganeshie8
  • ganeshie8
\(\large \sqrt{x-96} + m = d\) ^
ganeshie8
  • ganeshie8
there it goes ! wat about month and date
ganeshie8
  • ganeshie8
i feel like im interviewing u lol
anonymous
  • anonymous
Haha month is 4 and day is 22
ganeshie8
  • ganeshie8
thanks for giving it one shot :)
ganeshie8
  • ganeshie8
\(\large \sqrt{x-96} + 4 = 22\)
anonymous
  • anonymous
Alright so now what to do :o
ganeshie8
  • ganeshie8
solve for x
ganeshie8
  • ganeshie8
start by subtracting 4 both sides
anonymous
  • anonymous
Okay
ganeshie8
  • ganeshie8
\(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\)
anonymous
  • anonymous
18
ganeshie8
  • ganeshie8
Yes ! next, square both sides
anonymous
  • anonymous
You mean square 96 and 18 ?? :o
ganeshie8
  • ganeshie8
\(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\) square both sides \(\large (\sqrt{x-96})^2 = (18)^2\)
ganeshie8
  • ganeshie8
like this..
ganeshie8
  • ganeshie8
since u r not happy wid radical, we're killing it by squaring both sides !
ganeshie8
  • ganeshie8
\(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\) square both sides \(\large (\sqrt{x-96})^2 = (18)^2\) \(\large x-96 = 324\)
anonymous
  • anonymous
Oh okay !
ganeshie8
  • ganeshie8
wats our next step ?
anonymous
  • anonymous
Add 96 to both sides ?
ganeshie8
  • ganeshie8
thats it !
anonymous
  • anonymous
Okay so that would be 420 ? (;
ganeshie8
  • ganeshie8
Yes ! good job !!
anonymous
  • anonymous
Yay :D So that's the answer , correct ? Now what does it mean when it asks if the solution is extraneous ?? :o
ganeshie8
  • ganeshie8
oh, it asks to check if the solution is extraneous or now.
ganeshie8
  • ganeshie8
*not
anonymous
  • anonymous
Yeah , I don't know what that means .
ganeshie8
  • ganeshie8
its very easy to check, simply put the solution u got for x in the original (ur bday ) equaiton
anonymous
  • anonymous
Alright
ganeshie8
  • ganeshie8
ur bday equation :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 here, IF this satisfies this equation, then its NOT an extraneous solution.
anonymous
  • anonymous
I worked it out and I got 420=324 :o
ganeshie8
  • ganeshie8
careful, check again
anonymous
  • anonymous
But that's not true , so does that mean the solution IS extraneous ?
anonymous
  • anonymous
Oh okay ..
ganeshie8
  • ganeshie8
i want u check again,
ganeshie8
  • ganeshie8
Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\)
anonymous
  • anonymous
Right
ganeshie8
  • ganeshie8
Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\)
ganeshie8
  • ganeshie8
Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\)
anonymous
  • anonymous
Ohhhh okay ! That makes more sense !
anonymous
  • anonymous
THANK YOU
ganeshie8
  • ganeshie8
Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\) \(\large 22 = 22\) TRUE, so x=420 is NOT an extraneous solution.
ganeshie8
  • ganeshie8
np :) yw !

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