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LaynaMae

  • one year ago

HELP PLEASE !! Medal will be rewarded !

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  1. LaynaMae
    • one year ago
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  2. ganeshie8
    • one year ago
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    plugin the numbers into the given equation ?

  3. ganeshie8
    • one year ago
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    \(\large \sqrt{x-y} + m = d\)

  4. ganeshie8
    • one year ago
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    y is last two digits of ur birth year (u may fake if u want ;) ) m is month d is day

  5. LaynaMae
    • one year ago
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    Okay

  6. ganeshie8
    • one year ago
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    wat do u get for the equation ?

  7. LaynaMae
    • one year ago
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    Let me work it out

  8. ganeshie8
    • one year ago
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    okie

  9. LaynaMae
    • one year ago
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    I can't get the answer .. I don't know how to work this out ! :(

  10. ganeshie8
    • one year ago
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    if u can show me wat do u have... maybe i can help :)

  11. ganeshie8
    • one year ago
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    did u plugin the values in equation ?

  12. LaynaMae
    • one year ago
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    I don't know how to work it out .. Like I don't know where to start . I'm not good with radicals . All I did was try to find a way to work it out online but I couldn't find anything to help . Do I start with what's in the radical ?

  13. ganeshie8
    • one year ago
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    nope, have u read the question ? it wants u to put ur date of birth in the given equation, and solve x

  14. ganeshie8
    • one year ago
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    \(\large \sqrt{x-y} + m = d\) ^

  15. LaynaMae
    • one year ago
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    Okay

  16. ganeshie8
    • one year ago
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    put the year u born in that place

  17. ganeshie8
    • one year ago
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    which year ?

  18. LaynaMae
    • one year ago
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    Don't I use the values given in the question ?

  19. LaynaMae
    • one year ago
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    Ohhh nevermind , I just read the question wrong . My bad

  20. ganeshie8
    • one year ago
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    No, those values are for ur great great grandpa Nikola Tesla.... they're not urs lol

  21. ganeshie8
    • one year ago
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    cool :)

  22. LaynaMae
    • one year ago
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    Okay so I was born in 96

  23. ganeshie8
    • one year ago
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    \(\large \sqrt{x-96} + m = d\) ^

  24. ganeshie8
    • one year ago
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    there it goes ! wat about month and date

  25. ganeshie8
    • one year ago
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    i feel like im interviewing u lol

  26. LaynaMae
    • one year ago
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    Haha month is 4 and day is 22

  27. ganeshie8
    • one year ago
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    thanks for giving it one shot :)

  28. ganeshie8
    • one year ago
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    \(\large \sqrt{x-96} + 4 = 22\)

  29. LaynaMae
    • one year ago
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    Alright so now what to do :o

  30. ganeshie8
    • one year ago
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    solve for x

  31. ganeshie8
    • one year ago
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    start by subtracting 4 both sides

  32. LaynaMae
    • one year ago
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    Okay

  33. ganeshie8
    • one year ago
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    \(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\)

  34. LaynaMae
    • one year ago
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    18

  35. ganeshie8
    • one year ago
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    Yes ! next, square both sides

  36. LaynaMae
    • one year ago
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    You mean square 96 and 18 ?? :o

  37. ganeshie8
    • one year ago
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    \(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\) square both sides \(\large (\sqrt{x-96})^2 = (18)^2\)

  38. ganeshie8
    • one year ago
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    like this..

  39. ganeshie8
    • one year ago
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    since u r not happy wid radical, we're killing it by squaring both sides !

  40. ganeshie8
    • one year ago
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    \(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\) square both sides \(\large (\sqrt{x-96})^2 = (18)^2\) \(\large x-96 = 324\)

  41. LaynaMae
    • one year ago
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    Oh okay !

  42. ganeshie8
    • one year ago
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    wats our next step ?

  43. LaynaMae
    • one year ago
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    Add 96 to both sides ?

  44. ganeshie8
    • one year ago
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    thats it !

  45. LaynaMae
    • one year ago
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    Okay so that would be 420 ? (;

  46. ganeshie8
    • one year ago
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    Yes ! good job !!

  47. LaynaMae
    • one year ago
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    Yay :D So that's the answer , correct ? Now what does it mean when it asks if the solution is extraneous ?? :o

  48. ganeshie8
    • one year ago
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    oh, it asks to check if the solution is extraneous or now.

  49. ganeshie8
    • one year ago
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    *not

  50. LaynaMae
    • one year ago
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    Yeah , I don't know what that means .

  51. ganeshie8
    • one year ago
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    its very easy to check, simply put the solution u got for x in the original (ur bday ) equaiton

  52. LaynaMae
    • one year ago
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    Alright

  53. ganeshie8
    • one year ago
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    ur bday equation :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 here, IF this satisfies this equation, then its NOT an extraneous solution.

  54. LaynaMae
    • one year ago
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    I worked it out and I got 420=324 :o

  55. ganeshie8
    • one year ago
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    careful, check again

  56. LaynaMae
    • one year ago
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    But that's not true , so does that mean the solution IS extraneous ?

  57. LaynaMae
    • one year ago
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    Oh okay ..

  58. ganeshie8
    • one year ago
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    i want u check again,

  59. ganeshie8
    • one year ago
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    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\)

  60. LaynaMae
    • one year ago
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    Right

  61. ganeshie8
    • one year ago
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    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\)

  62. ganeshie8
    • one year ago
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    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\)

  63. LaynaMae
    • one year ago
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    Ohhhh okay ! That makes more sense !

  64. LaynaMae
    • one year ago
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    THANK YOU

  65. ganeshie8
    • one year ago
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    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\) \(\large 22 = 22\) TRUE, so x=420 is NOT an extraneous solution.

  66. ganeshie8
    • one year ago
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    np :) yw !

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