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LaynaMae
 one year ago
HELP PLEASE !! Medal will be rewarded !
LaynaMae
 one year ago
HELP PLEASE !! Medal will be rewarded !

This Question is Closed

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1plugin the numbers into the given equation ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{xy} + m = d\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1y is last two digits of ur birth year (u may fake if u want ;) ) m is month d is day

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1wat do u get for the equation ?

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1I can't get the answer .. I don't know how to work this out ! :(

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1if u can show me wat do u have... maybe i can help :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1did u plugin the values in equation ?

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1I don't know how to work it out .. Like I don't know where to start . I'm not good with radicals . All I did was try to find a way to work it out online but I couldn't find anything to help . Do I start with what's in the radical ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1nope, have u read the question ? it wants u to put ur date of birth in the given equation, and solve x

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{xy} + m = d\) ^

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1put the year u born in that place

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1Don't I use the values given in the question ?

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1Ohhh nevermind , I just read the question wrong . My bad

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1No, those values are for ur great great grandpa Nikola Tesla.... they're not urs lol

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1Okay so I was born in 96

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{x96} + m = d\) ^

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1there it goes ! wat about month and date

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1i feel like im interviewing u lol

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1Haha month is 4 and day is 22

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1thanks for giving it one shot :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{x96} + 4 = 22\)

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1Alright so now what to do :o

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1start by subtracting 4 both sides

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Yes ! next, square both sides

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1You mean square 96 and 18 ?? :o

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\) square both sides \(\large (\sqrt{x96})^2 = (18)^2\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1since u r not happy wid radical, we're killing it by squaring both sides !

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \sqrt{x96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x96} = 18\) square both sides \(\large (\sqrt{x96})^2 = (18)^2\) \(\large x96 = 324\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1wats our next step ?

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1Add 96 to both sides ?

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1Okay so that would be 420 ? (;

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1Yay :D So that's the answer , correct ? Now what does it mean when it asks if the solution is extraneous ?? :o

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1oh, it asks to check if the solution is extraneous or now.

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1Yeah , I don't know what that means .

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1its very easy to check, simply put the solution u got for x in the original (ur bday ) equaiton

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1ur bday equation : \(\large \sqrt{x96} + 4 = 22\) put x = 420 here, IF this satisfies this equation, then its NOT an extraneous solution.

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1I worked it out and I got 420=324 :o

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1careful, check again

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1But that's not true , so does that mean the solution IS extraneous ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1i want u check again,

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\)

LaynaMae
 one year ago
Best ResponseYou've already chosen the best response.1Ohhhh okay ! That makes more sense !

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Checking if x=420 is extraneous solution or not : \(\large \sqrt{x96} + 4 = 22\) put x = 420 \(\large \sqrt{42096} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\) \(\large 22 = 22\) TRUE, so x=420 is NOT an extraneous solution.
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