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LaynaMae

HELP PLEASE !! Medal will be rewarded !

  • 6 months ago
  • 6 months ago

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  1. LaynaMae
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    • 6 months ago
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  2. ganeshie8
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    plugin the numbers into the given equation ?

    • 6 months ago
  3. ganeshie8
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    \(\large \sqrt{x-y} + m = d\)

    • 6 months ago
  4. ganeshie8
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    y is last two digits of ur birth year (u may fake if u want ;) ) m is month d is day

    • 6 months ago
  5. LaynaMae
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    Okay

    • 6 months ago
  6. ganeshie8
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    wat do u get for the equation ?

    • 6 months ago
  7. LaynaMae
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    Let me work it out

    • 6 months ago
  8. ganeshie8
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    okie

    • 6 months ago
  9. LaynaMae
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    I can't get the answer .. I don't know how to work this out ! :(

    • 6 months ago
  10. ganeshie8
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    if u can show me wat do u have... maybe i can help :)

    • 6 months ago
  11. ganeshie8
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    did u plugin the values in equation ?

    • 6 months ago
  12. LaynaMae
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    I don't know how to work it out .. Like I don't know where to start . I'm not good with radicals . All I did was try to find a way to work it out online but I couldn't find anything to help . Do I start with what's in the radical ?

    • 6 months ago
  13. ganeshie8
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    nope, have u read the question ? it wants u to put ur date of birth in the given equation, and solve x

    • 6 months ago
  14. ganeshie8
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    \(\large \sqrt{x-y} + m = d\) ^

    • 6 months ago
  15. LaynaMae
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    Okay

    • 6 months ago
  16. ganeshie8
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    put the year u born in that place

    • 6 months ago
  17. ganeshie8
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    which year ?

    • 6 months ago
  18. LaynaMae
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    Don't I use the values given in the question ?

    • 6 months ago
  19. LaynaMae
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    Ohhh nevermind , I just read the question wrong . My bad

    • 6 months ago
  20. ganeshie8
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    No, those values are for ur great great grandpa Nikola Tesla.... they're not urs lol

    • 6 months ago
  21. ganeshie8
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    cool :)

    • 6 months ago
  22. LaynaMae
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    Okay so I was born in 96

    • 6 months ago
  23. ganeshie8
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    \(\large \sqrt{x-96} + m = d\) ^

    • 6 months ago
  24. ganeshie8
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    there it goes ! wat about month and date

    • 6 months ago
  25. ganeshie8
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    i feel like im interviewing u lol

    • 6 months ago
  26. LaynaMae
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    Haha month is 4 and day is 22

    • 6 months ago
  27. ganeshie8
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    thanks for giving it one shot :)

    • 6 months ago
  28. ganeshie8
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    \(\large \sqrt{x-96} + 4 = 22\)

    • 6 months ago
  29. LaynaMae
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    Alright so now what to do :o

    • 6 months ago
  30. ganeshie8
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    solve for x

    • 6 months ago
  31. ganeshie8
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    start by subtracting 4 both sides

    • 6 months ago
  32. LaynaMae
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    Okay

    • 6 months ago
  33. ganeshie8
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    \(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\)

    • 6 months ago
  34. LaynaMae
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    18

    • 6 months ago
  35. ganeshie8
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    Yes ! next, square both sides

    • 6 months ago
  36. LaynaMae
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    You mean square 96 and 18 ?? :o

    • 6 months ago
  37. ganeshie8
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    \(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\) square both sides \(\large (\sqrt{x-96})^2 = (18)^2\)

    • 6 months ago
  38. ganeshie8
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    like this..

    • 6 months ago
  39. ganeshie8
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    since u r not happy wid radical, we're killing it by squaring both sides !

    • 6 months ago
  40. ganeshie8
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    \(\large \sqrt{x-96} + 4 = 22\) subtract 4 both sides \(\large \sqrt{x-96} = 18\) square both sides \(\large (\sqrt{x-96})^2 = (18)^2\) \(\large x-96 = 324\)

    • 6 months ago
  41. LaynaMae
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    Oh okay !

    • 6 months ago
  42. ganeshie8
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    wats our next step ?

    • 6 months ago
  43. LaynaMae
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    Add 96 to both sides ?

    • 6 months ago
  44. ganeshie8
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    thats it !

    • 6 months ago
  45. LaynaMae
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    Okay so that would be 420 ? (;

    • 6 months ago
  46. ganeshie8
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    Yes ! good job !!

    • 6 months ago
  47. LaynaMae
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    Yay :D So that's the answer , correct ? Now what does it mean when it asks if the solution is extraneous ?? :o

    • 6 months ago
  48. ganeshie8
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    oh, it asks to check if the solution is extraneous or now.

    • 6 months ago
  49. ganeshie8
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    *not

    • 6 months ago
  50. LaynaMae
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    Yeah , I don't know what that means .

    • 6 months ago
  51. ganeshie8
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    its very easy to check, simply put the solution u got for x in the original (ur bday ) equaiton

    • 6 months ago
  52. LaynaMae
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    Alright

    • 6 months ago
  53. ganeshie8
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    ur bday equation :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 here, IF this satisfies this equation, then its NOT an extraneous solution.

    • 6 months ago
  54. LaynaMae
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    I worked it out and I got 420=324 :o

    • 6 months ago
  55. ganeshie8
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    careful, check again

    • 6 months ago
  56. LaynaMae
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    But that's not true , so does that mean the solution IS extraneous ?

    • 6 months ago
  57. LaynaMae
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    Oh okay ..

    • 6 months ago
  58. ganeshie8
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    i want u check again,

    • 6 months ago
  59. ganeshie8
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    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\)

    • 6 months ago
  60. LaynaMae
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    Right

    • 6 months ago
  61. ganeshie8
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    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\)

    • 6 months ago
  62. ganeshie8
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    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\)

    • 6 months ago
  63. LaynaMae
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    Ohhhh okay ! That makes more sense !

    • 6 months ago
  64. LaynaMae
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    THANK YOU

    • 6 months ago
  65. ganeshie8
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    Checking if x=420 is extraneous solution or not :- \(\large \sqrt{x-96} + 4 = 22\) put x = 420 \(\large \sqrt{420-96} + 4 = 22\) \(\large \sqrt{324} + 4 = 22\) \(\large 18 + 4 = 22\) \(\large 22 = 22\) TRUE, so x=420 is NOT an extraneous solution.

    • 6 months ago
  66. ganeshie8
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    np :) yw !

    • 6 months ago
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