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ton

  • 2 years ago

y''-2y'-2y=0

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  1. myininaya
    • 2 years ago
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    Solve r^2-2r-2=0

  2. myininaya
    • 2 years ago
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    If you have a_[n]*y^[n]+a_[n-1]*y^[n-1]+a_[n-2]*y^[n-2]+....+a_[0]*y=0 where the a's are constants and the number in the ^[ ] is which derivative we are referring to, then the first step is to solve a_[n]*r^n+a_[n-1]*r^(n-1)+....+a_[0]=0. If r is real and say r=pm a, then your solution will be y=c1*e^(at)+c2*e^(bt). If r is complex (or just includes the imaginary part), then your answer will involve cos(x) and sin(x) instead of exponentials.

  3. ton
    • 2 years ago
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    i need detailed answer..tnx

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