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AriM

  • 2 years ago

Help me solve this piecewise function pls. f(x) = 0 if x <0 0 if x is greater than or equal to 0 g(x) = -x if x < 0 0, if x is greater than or equal to 0 f+g=?

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  1. SnuggieLad
    • 2 years ago
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    What don't you understand?

  2. AriM
    • 2 years ago
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    im just not sure what to do. Thats why i just need an example of f+g so i can see it. It's like you add the first line of each right?

  3. SnuggieLad
    • 2 years ago
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    Try graphing it...Do you know how? I am not very good at explaining mathmatics without graph paper and not in person but you know who is excellent at it? @satellite73 @amistre64 @hartnn @Callisto ! There is a reason they are mods here!

  4. SnuggieLad
    • 2 years ago
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    Now, try not to have to fall back on the mods too much because they are very busy. Be patient, they will help when they get a chance.

  5. AriM
    • 2 years ago
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    I have a test in 2 hours though :(

  6. AriM
    • 2 years ago
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    @surjithayer can you help please?

  7. SnuggieLad
    • 2 years ago
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    Its okay, they will be here soon!

  8. AriM
    • 2 years ago
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    I literally just need this one answer so i can see how its done so i can do f-g, f*g, and f/g

  9. SnuggieLad
    • 2 years ago
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    Well, I will stick here with you to make sure you get some help. Give them some time I have contacted them.

  10. AriM
    • 2 years ago
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    ok

  11. AriM
    • 2 years ago
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    @SnuggieLad can you maybe help me with something eles than?

  12. Callisto
    • 2 years ago
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    f(x) = 0 if x <0 0 if x is greater than or equal to 0 What does this function imply?

  13. Callisto
    • 2 years ago
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    Whatever x you have, it is still....?

  14. AriM
    • 2 years ago
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    for f+g i got -x if x<0 and x if x is greater than or = to 0

  15. Callisto
    • 2 years ago
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    Right. f has no effect when doing the addition as its value is always 0. So, f+g just depends on g.

  16. AriM
    • 2 years ago
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    oh, ok.

  17. AriM
    • 2 years ago
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    do you think u can help me with another problem?

  18. anonymous
    • 2 years ago
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    it is really \(f(x)=0\) in both cases? or is there a typo there?

  19. AriM
    • 2 years ago
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    umm no? i don't know. All i know is i just based it off an answer i saw in the book so thats how i did it.

  20. Callisto
    • 2 years ago
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    I am sorry that I have to go now. Best of luck for your test.

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