anonymous
  • anonymous
Help me solve this piecewise function pls. f(x) = 0 if x <0 0 if x is greater than or equal to 0 g(x) = -x if x < 0 0, if x is greater than or equal to 0 f+g=?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
SnuggieLad
  • SnuggieLad
What don't you understand?
anonymous
  • anonymous
im just not sure what to do. Thats why i just need an example of f+g so i can see it. It's like you add the first line of each right?
SnuggieLad
  • SnuggieLad
Try graphing it...Do you know how? I am not very good at explaining mathmatics without graph paper and not in person but you know who is excellent at it? @satellite73 @amistre64 @hartnn @Callisto ! There is a reason they are mods here!

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SnuggieLad
  • SnuggieLad
Now, try not to have to fall back on the mods too much because they are very busy. Be patient, they will help when they get a chance.
anonymous
  • anonymous
I have a test in 2 hours though :(
anonymous
  • anonymous
@surjithayer can you help please?
SnuggieLad
  • SnuggieLad
Its okay, they will be here soon!
anonymous
  • anonymous
I literally just need this one answer so i can see how its done so i can do f-g, f*g, and f/g
SnuggieLad
  • SnuggieLad
Well, I will stick here with you to make sure you get some help. Give them some time I have contacted them.
anonymous
  • anonymous
ok
anonymous
  • anonymous
@SnuggieLad can you maybe help me with something eles than?
Callisto
  • Callisto
f(x) = 0 if x <0 0 if x is greater than or equal to 0 What does this function imply?
Callisto
  • Callisto
Whatever x you have, it is still....?
anonymous
  • anonymous
for f+g i got -x if x<0 and x if x is greater than or = to 0
Callisto
  • Callisto
Right. f has no effect when doing the addition as its value is always 0. So, f+g just depends on g.
anonymous
  • anonymous
oh, ok.
anonymous
  • anonymous
do you think u can help me with another problem?
anonymous
  • anonymous
it is really \(f(x)=0\) in both cases? or is there a typo there?
anonymous
  • anonymous
umm no? i don't know. All i know is i just based it off an answer i saw in the book so thats how i did it.
Callisto
  • Callisto
I am sorry that I have to go now. Best of luck for your test.

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