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valiyuh
Group Title
Find the equation perpendicular to 2y4x=8 and passes the point (8,2) .
Can someone explain how to do it please?
Geometry
 one year ago
 one year ago
valiyuh Group Title
Find the equation perpendicular to 2y4x=8 and passes the point (8,2) . Can someone explain how to do it please? Geometry
 one year ago
 one year ago

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DSS Group TitleBest ResponseYou've already chosen the best response.1
Change the given equation to slope intercept form, y=mx+b That will help you determine the slope of the given line
 one year ago

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What did you get
 one year ago

DSS Group TitleBest ResponseYou've already chosen the best response.1
close 2y = 4x + 8 No divide everything by 2 so you get y= mx+b
 one year ago

DSS Group TitleBest ResponseYou've already chosen the best response.1
did u get y=2x+4
 one year ago

DSS Group TitleBest ResponseYou've already chosen the best response.1
You'll see that the slope of the given line is 2. To have a perpendicular line, the slope is the opposite reciprocal.....1/2
 one year ago

DSS Group TitleBest ResponseYou've already chosen the best response.1
Using the slope intercept formula and the point given (8,2) plug in and find b.
 one year ago

DSS Group TitleBest ResponseYou've already chosen the best response.1
Are you still there
 one year ago

DSS Group TitleBest ResponseYou've already chosen the best response.1
2=4+b 6=b Now you can give the equation of a line perpendicular to the given line at the point (8,2). y=1/2x+6
 one year ago
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