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valiyuh Group Title

Find the equation perpendicular to 2y-4x=8 and passes the point (8,2) . Can someone explain how to do it please? -Geometry

  • 10 months ago
  • 10 months ago

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  1. DSS Group Title
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    Change the given equation to slope intercept form, y=mx+b That will help you determine the slope of the given line

    • 10 months ago
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    What did you get

    • 10 months ago
  3. valiyuh Group Title
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    2y=4x+b ?

    • 10 months ago
  4. DSS Group Title
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    close 2y = 4x + 8 No divide everything by 2 so you get y= mx+b

    • 10 months ago
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    Now

    • 10 months ago
  6. DSS Group Title
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    did u get y=2x+4

    • 10 months ago
  7. valiyuh Group Title
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    yes

    • 10 months ago
  8. DSS Group Title
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    You'll see that the slope of the given line is 2. To have a perpendicular line, the slope is the opposite reciprocal.....-1/2

    • 10 months ago
  9. DSS Group Title
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    Using the slope intercept formula and the point given (8,2) plug in and find b.

    • 10 months ago
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    2=-1/2(8)+b

    • 10 months ago
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    Are you still there

    • 10 months ago
  12. DSS Group Title
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    2=-4+b 6=b Now you can give the equation of a line perpendicular to the given line at the point (8,2). y=-1/2x+6

    • 10 months ago
  13. valiyuh Group Title
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    oh i see

    • 10 months ago
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