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valiyuh

  • one year ago

Find the equation perpendicular to 2y-4x=8 and passes the point (8,2) . Can someone explain how to do it please? -Geometry

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  1. DSS
    • one year ago
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    Change the given equation to slope intercept form, y=mx+b That will help you determine the slope of the given line

  2. DSS
    • one year ago
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    What did you get

  3. valiyuh
    • one year ago
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    2y=4x+b ?

  4. DSS
    • one year ago
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    close 2y = 4x + 8 No divide everything by 2 so you get y= mx+b

  5. DSS
    • one year ago
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    Now

  6. DSS
    • one year ago
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    did u get y=2x+4

  7. valiyuh
    • one year ago
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    yes

  8. DSS
    • one year ago
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    You'll see that the slope of the given line is 2. To have a perpendicular line, the slope is the opposite reciprocal.....-1/2

  9. DSS
    • one year ago
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    Using the slope intercept formula and the point given (8,2) plug in and find b.

  10. DSS
    • one year ago
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    2=-1/2(8)+b

  11. DSS
    • one year ago
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    Are you still there

  12. DSS
    • one year ago
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    2=-4+b 6=b Now you can give the equation of a line perpendicular to the given line at the point (8,2). y=-1/2x+6

  13. valiyuh
    • one year ago
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    oh i see

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