valiyuh
Find the equation perpendicular to 2y4x=8 and passes the point (8,2) .
Can someone explain how to do it please?
Geometry



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DSS
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Change the given equation to slope intercept form, y=mx+b That will help you determine the slope of the given line

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What did you get

valiyuh
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2y=4x+b ?

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close 2y = 4x + 8
No divide everything by 2 so you get y= mx+b

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Now

DSS
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did u get y=2x+4

valiyuh
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yes

DSS
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You'll see that the slope of the given line is 2. To have a perpendicular line, the slope is the opposite reciprocal.....1/2

DSS
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Using the slope intercept formula and the point given (8,2) plug in and find b.

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2=1/2(8)+b

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Are you still there

DSS
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2=4+b
6=b
Now you can give the equation of a line perpendicular to the given line at the point (8,2).
y=1/2x+6

valiyuh
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oh i see