A community for students.
Here's the question you clicked on:
 0 viewing
iouri.gordon
 2 years ago
I wander if my thinking is right when solving this equation. I put details in the post. Don't know how to write an equation in the initial message. So when you click on the message you'll see details.
iouri.gordon
 2 years ago
I wander if my thinking is right when solving this equation. I put details in the post. Don't know how to write an equation in the initial message. So when you click on the message you'll see details.

This Question is Closed

iouri.gordon
 2 years ago
Best ResponseYou've already chosen the best response.0Find \[F \prime \left( X \right)\] if \[F \left( X \right)=\int\limits_{x}^{x ^{2}}\tan u du\]. So what I though is by FTC 1 \[F \left( X \right)=F \left( X ^{2} \right)F \left( X \right)\], now taking derivative of both sides gives: \[F \prime \left( X \right) = 2XF \prime \left( X ^{2} \right)F \prime \left( X \right)\], which in turn could be rewritten as: \[2x \frac{ d }{ dx }\int\limits_{0}^{x ^{2}}\tan u du  \frac{ d }{ dx }\int\limits_{0}^{x}\tan udu\] which in turn equals: \[2x \tan x ^{2}\tan x\]. Am I doing the right thing?

jostiniane
 2 years ago
Best ResponseYou've already chosen the best response.0I dont think my friend ?_? you could take another function G(X) instead taking the same F(X) ... but why not integrating tan(X) like sin/cos => sin/cos => (sin/cos) => f'/f => lncos

Anunnaki
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{x}^{x^2}\tan(u)du \rightarrow \ln \left( \cos(x) \right)  \ln(\cos(x ^{2}))\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.