A community for students.
Here's the question you clicked on:
 0 viewing
IsTim
 3 years ago
Balance: C5H12+O2>10CO2
12H2O
IsTim
 3 years ago
Balance: C5H12+O2>10CO2 12H2O

This Question is Closed

IsTim
 3 years ago
Best ResponseYou've already chosen the best response.0FURThest i got was 2 CH12O+ 10O2>10CO2+ 12H20

IsTim
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry, I mean 2C5H12O+10O2>10CO2+12H2O

wolfe8
 3 years ago
Best ResponseYou've already chosen the best response.1What my teacher told me years ago was to first balance the C, then O, and lastly H.

IsTim
 3 years ago
Best ResponseYou've already chosen the best response.0is what i do, but somehow i can't reduce this.

wolfe8
 3 years ago
Best ResponseYou've already chosen the best response.1Well since there is O2 without other elements with is, I guess it's best to do O last then. Let me try.

wolfe8
 3 years ago
Best ResponseYou've already chosen the best response.1\[C _{5}H _{12}+8O _{2}\rightarrow5CO _{2}+6H _{2}O\]

IsTim
 3 years ago
Best ResponseYou've already chosen the best response.0sorry its C5H12O+O2>1CO2+H2O

wolfe8
 3 years ago
Best ResponseYou've already chosen the best response.1Ah I left an O. Hold on.

wolfe8
 3 years ago
Best ResponseYou've already chosen the best response.1Hint: you can use fractions. Can you get it?

IsTim
 3 years ago
Best ResponseYou've already chosen the best response.0NO, IM NOT ALLOWED USING FRACTions for this assignment

wolfe8
 3 years ago
Best ResponseYou've already chosen the best response.1Well...then I guess after you get it with a fraction, multiply everything with the denominator :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.