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anonymous

  • 2 years ago

Evaluate f(x) = x 2 + 1 for f(-1). a.0 b.undefined c.2

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  1. SnuggieLad
    • 2 years ago
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    Do this the same way you did it before. X=1...put -1 in for x in that problem

  2. SnuggieLad
    • 2 years ago
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    (-1)*2+1

  3. SnuggieLad
    • 2 years ago
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    or also written it is 2(-1) + 1

  4. Hero
    • 2 years ago
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    f(x) = x^2 + 1 f(-1)= (-1)^2 + 1 = 1 + 1 = ?

  5. SnuggieLad
    • 2 years ago
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    Hold on? Is that a square root? Be sure to write that out next time

  6. SnuggieLad
    • 2 years ago
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    Well done @Hero

  7. Hero
    • 2 years ago
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    Its \(f(x) = x^2 + 1\) Sometimes when students copy and paste, they forget to add the caret.

  8. anonymous
    • 2 years ago
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    ok so the answer is 2 thanks a lot

  9. SnuggieLad
    • 2 years ago
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    Yes, I should have picked up on that.

  10. anonymous
    • 2 years ago
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    can you guys help me with one more its Evaluate f(x) = x^ 2 + 1 for f(10). a.2√2 b.101 c.21

  11. Hero
    • 2 years ago
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    f(x) = x^2 + 1 f(10) = (10)^2 + 1 = 100 + 1 = ?

  12. anonymous
    • 2 years ago
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    what about this one? If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)] 2. a.1 b.2 c.9

  13. Hero
    • 2 years ago
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    I thought you said you only had one more....You tricked me :)

  14. anonymous
    • 2 years ago
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    sorry...lol this is the last one.

  15. Hero
    • 2 years ago
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    f(2) - g(1) = (2)^2 + 1 -(3(1) + 1) = 4 + 1 - 3 - 1 = 5 - 4 = ?

  16. anonymous
    • 2 years ago
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    thanks

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