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minimum is at the vertex
compute \(-\frac{b}{2a}\) with \(b=700,a=1\)

oh, i see you did that.
hmmmm

weird
i guess to minimize the cost, produce nothing

i understood part d.... it's 280

you found the vertex correctly, but you can't produce -350 items

where on earth did the 280 come from?

That's the production level that will minimize the average cost

oh, i guess i have no idea what an average cost is

oooooh!

i did c(X)/x, differentiated, then set it to zero. and got x=280

why is that an "average cost"?

The minimal average cost?

okaay but let's find part e please.

learn something new every day

that's my main concern...

i did

x=280

i don't understand

OK, you good for e now?

yes

Sorry - don't understand what?

but it's wrong.

What did you get?

Just evaluate the average cost function at x=280

so plug x into ?

The average cost function:
A(x)=78400/x+700+x
which is just C(x)/x

what did you get? :)

right.280!

well -78400/x^2+1...

oooooooo

how about if i want to find the production level that will maximize profit.