Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Does anyone know where you could find the deduction of the inverse of tanh(x) starting from the standard hyperbolic trigonometry definitions? (Or does anyone possibly know how to deduce it from them?)
 6 months ago
 6 months ago
Does anyone know where you could find the deduction of the inverse of tanh(x) starting from the standard hyperbolic trigonometry definitions? (Or does anyone possibly know how to deduce it from them?)
 6 months ago
 6 months ago

This Question is Closed

NoliecBest ResponseYou've already chosen the best response.2
@hartnn , @TuringTest , @AravindG Please help ;_;
 6 months ago

NoliecBest ResponseYou've already chosen the best response.2
I basically get it, down to tanh(x)=(e^(2x)1)/(e^(2x)+1)
 6 months ago

NoliecBest ResponseYou've already chosen the best response.2
Indeed, but how do you go from here to the inverse of tanh(x)?
 6 months ago

hartnnBest ResponseYou've already chosen the best response.1
do u know componendo  dividendo ?
 6 months ago

AravindGBest ResponseYou've already chosen the best response.0
Take tanh x=y. Then apply log on both sides.
 6 months ago

hartnnBest ResponseYou've already chosen the best response.1
if a/b = c/d then (a+b) /(ab) = (c+d)/ (cd) did u know this ?
 6 months ago

NoliecBest ResponseYou've already chosen the best response.2
That's what I did, I didn't get anywhere on the log expression though. Hmm, not sure hartnn.
 6 months ago

hartnnBest ResponseYou've already chosen the best response.1
that rule is called componendodividendo apply that for y/1= (e^(2x)1)/(e^(2x)+1)
 6 months ago

NoliecBest ResponseYou've already chosen the best response.2
I'd have to give a proof in order to utilize it though. D: It's supposed to be solved without it.
 6 months ago

hartnnBest ResponseYou've already chosen the best response.1
that will isolate e^2x and hence you can apply log
 6 months ago

hartnnBest ResponseYou've already chosen the best response.1
lol ok, don't apply that rule (bdw, that was algebraic property) y= (e^(2x)1)/(e^(2x)+1) y (e^2x +1) = e^2x 1 y e^2x + y = e^2x 1 y e^2x e^2x = 1y need i go further ?
 6 months ago

hartnnBest ResponseYou've already chosen the best response.1
hint for next step factor out e^2x from on left side
 6 months ago

hartnnBest ResponseYou've already chosen the best response.1
but did u get what i did ?
 6 months ago

hartnnBest ResponseYou've already chosen the best response.1
\(\huge \dfrac{1}{2}\ln (\dfrac{1+x}{1x})\) you should get this
 6 months ago

hartnnBest ResponseYou've already chosen the best response.1
1y / y1 = (1+y)/ (1y) the 1/2 will come outside ln right ? because 2x= ln (...)
 6 months ago

NoliecBest ResponseYou've already chosen the best response.2
What happens after you apply ln?
 6 months ago

hartnnBest ResponseYou've already chosen the best response.1
e^2x =[(1+y)/(1y) ] clear till here ??
 6 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.