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natasha.aries Group Title

***I WILL GIVE BEST ANSWER!***HEYY! CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION!? I HAVE A TEST COMING UP AND I AM SOO CONFUZZLED! PLEASE INCLUDE THE NUMBERS AND SOLUTIONS IN ANSWER! (please dont round)

  • 9 months ago
  • 9 months ago

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  1. natasha.aries Group Title
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    • 9 months ago
  2. natasha.aries Group Title
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    The question is what is the height of where the collision takes place!

    • 9 months ago
  3. RANE Group Title
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    r u given the answer ?

    • 9 months ago
  4. natasha.aries Group Title
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    sadly, no :(

    • 9 months ago
  5. RANE Group Title
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    ahan well i dis q's like this last year , i think i remember it

    • 9 months ago
  6. natasha.aries Group Title
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    really!? how do u do it!?

    • 9 months ago
  7. RANE Group Title
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    i think so, let me try first

    • 9 months ago
  8. natasha.aries Group Title
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    okay! thankk youu!

    • 9 months ago
  9. natasha.aries Group Title
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    i get a few tries to see if i got the question right so if you give me an answer i could put it in and see if youre right. and then you could explain it! but you cant round on anything! and this is only if youre willing to help me! sorry

    • 9 months ago
  10. RANE Group Title
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    ok i did it and i got 91.6m but im not sure if thats the answer

    • 9 months ago
  11. natasha.aries Group Title
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    did you round anything?

    • 9 months ago
  12. RANE Group Title
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    nop

    • 9 months ago
  13. RANE Group Title
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    was i suppose to?

    • 9 months ago
  14. natasha.aries Group Title
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    nope! okay let me check

    • 9 months ago
  15. natasha.aries Group Title
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    nope its wrong :(

    • 9 months ago
  16. RANE Group Title
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    whts the answer then?

    • 9 months ago
  17. natasha.aries Group Title
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    idk i can put in answers and it will tell me if its right or wrong

    • 9 months ago
  18. RANE Group Title
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    idk then i cant figure out any other way to do it

    • 9 months ago
  19. natasha.aries Group Title
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    its okay thanks anyways!

    • 9 months ago
  20. RANE Group Title
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    np:) but dont u have nay clue wht could be the answer around ?

    • 9 months ago
  21. natasha.aries Group Title
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    absolutely no idea lol

    • 9 months ago
  22. RANE Group Title
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    have u done q's like that before?

    • 9 months ago
  23. natasha.aries Group Title
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    not as hard!

    • 9 months ago
  24. natasha.aries Group Title
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    this one is really complex

    • 9 months ago
  25. RANE Group Title
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    sure it is

    • 9 months ago
  26. RANE Group Title
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    maybe he can help @UnkleRhaukus

    • 9 months ago
  27. natasha.aries Group Title
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    YES PLEASE @UnkleRhaukus lol

    • 9 months ago
  28. oksuz_ Group Title
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    |dw:1380448186791:dw| You know Vx and d. So you can calculate time t. Then you can find what the AP is by using \[\left| AP \right| =\frac{ g*t ^{2} }{ 2 }\] Then you can calculate BP easily. |BP|=|AB|-|AP|

    • 9 months ago
  29. CarlosGP Group Title
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    For target:\[h_t=h_0-1/2g t^2\]For bullet\[h_b=v_0\sin(\theta)t-1/2g t^2\]At time t_c both bodies collide:\[h_b=h_t \rightarrow v_0\sin(\theta)t_c-1/2g t_c^2=h_0-1/2g t_c^2 \rightarrow t_c=\frac{ h_0 }{ v_0\sin(\theta) }\]and at that moment, target is at:\[h_t(t_c)=h_0-\frac{ 1 }{ 2 }g \left( \frac{ h_0 }{ v_0\sin(\theta) } \right)^2=91.7-4.9·\left( \frac{ 91.7 }{ 109·\sin(48.4)} \right)^2\]

    • 9 months ago
  30. CarlosGP Group Title
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    and during time t_c, bullet has to cover distance "d". Let us see:\[x(t=t_c)=v_0\cos(\theta)t_c=v_0\cos(\theta)\frac{ h_0 }{ v_0\sin(\theta) }=h_0/\tan(\theta)=d\]

    • 9 months ago
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