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natasha.aries Group Title

***I WILL GIVE BEST ANSWER!***HEYY! CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION!? I HAVE A TEST COMING UP AND I AM SOO CONFUZZLED! PLEASE INCLUDE THE NUMBERS AND SOLUTIONS IN ANSWER! (please dont round)

  • one year ago
  • one year ago

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  1. natasha.aries Group Title
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    • one year ago
  2. natasha.aries Group Title
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    The question is what is the height of where the collision takes place!

    • one year ago
  3. RANE Group Title
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    r u given the answer ?

    • one year ago
  4. natasha.aries Group Title
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    sadly, no :(

    • one year ago
  5. RANE Group Title
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    ahan well i dis q's like this last year , i think i remember it

    • one year ago
  6. natasha.aries Group Title
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    really!? how do u do it!?

    • one year ago
  7. RANE Group Title
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    i think so, let me try first

    • one year ago
  8. natasha.aries Group Title
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    okay! thankk youu!

    • one year ago
  9. natasha.aries Group Title
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    i get a few tries to see if i got the question right so if you give me an answer i could put it in and see if youre right. and then you could explain it! but you cant round on anything! and this is only if youre willing to help me! sorry

    • one year ago
  10. RANE Group Title
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    ok i did it and i got 91.6m but im not sure if thats the answer

    • one year ago
  11. natasha.aries Group Title
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    did you round anything?

    • one year ago
  12. RANE Group Title
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    nop

    • one year ago
  13. RANE Group Title
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    was i suppose to?

    • one year ago
  14. natasha.aries Group Title
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    nope! okay let me check

    • one year ago
  15. natasha.aries Group Title
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    nope its wrong :(

    • one year ago
  16. RANE Group Title
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    whts the answer then?

    • one year ago
  17. natasha.aries Group Title
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    idk i can put in answers and it will tell me if its right or wrong

    • one year ago
  18. RANE Group Title
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    idk then i cant figure out any other way to do it

    • one year ago
  19. natasha.aries Group Title
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    its okay thanks anyways!

    • one year ago
  20. RANE Group Title
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    np:) but dont u have nay clue wht could be the answer around ?

    • one year ago
  21. natasha.aries Group Title
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    absolutely no idea lol

    • one year ago
  22. RANE Group Title
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    have u done q's like that before?

    • one year ago
  23. natasha.aries Group Title
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    not as hard!

    • one year ago
  24. natasha.aries Group Title
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    this one is really complex

    • one year ago
  25. RANE Group Title
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    sure it is

    • one year ago
  26. RANE Group Title
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    maybe he can help @UnkleRhaukus

    • one year ago
  27. natasha.aries Group Title
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    YES PLEASE @UnkleRhaukus lol

    • one year ago
  28. oksuz_ Group Title
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    |dw:1380448186791:dw| You know Vx and d. So you can calculate time t. Then you can find what the AP is by using \[\left| AP \right| =\frac{ g*t ^{2} }{ 2 }\] Then you can calculate BP easily. |BP|=|AB|-|AP|

    • one year ago
  29. CarlosGP Group Title
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    For target:\[h_t=h_0-1/2g t^2\]For bullet\[h_b=v_0\sin(\theta)t-1/2g t^2\]At time t_c both bodies collide:\[h_b=h_t \rightarrow v_0\sin(\theta)t_c-1/2g t_c^2=h_0-1/2g t_c^2 \rightarrow t_c=\frac{ h_0 }{ v_0\sin(\theta) }\]and at that moment, target is at:\[h_t(t_c)=h_0-\frac{ 1 }{ 2 }g \left( \frac{ h_0 }{ v_0\sin(\theta) } \right)^2=91.7-4.9·\left( \frac{ 91.7 }{ 109·\sin(48.4)} \right)^2\]

    • one year ago
  30. CarlosGP Group Title
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    and during time t_c, bullet has to cover distance "d". Let us see:\[x(t=t_c)=v_0\cos(\theta)t_c=v_0\cos(\theta)\frac{ h_0 }{ v_0\sin(\theta) }=h_0/\tan(\theta)=d\]

    • one year ago
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