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anonymous

  • 2 years ago

***I WILL GIVE BEST ANSWER!***HEYY! CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION!? I HAVE A TEST COMING UP AND I AM SOO CONFUZZLED! PLEASE INCLUDE THE NUMBERS AND SOLUTIONS IN ANSWER! (please dont round)

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  1. anonymous
    • 2 years ago
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  2. anonymous
    • 2 years ago
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    The question is what is the height of where the collision takes place!

  3. RANE
    • 2 years ago
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    r u given the answer ?

  4. anonymous
    • 2 years ago
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    sadly, no :(

  5. RANE
    • 2 years ago
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    ahan well i dis q's like this last year , i think i remember it

  6. anonymous
    • 2 years ago
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    really!? how do u do it!?

  7. RANE
    • 2 years ago
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    i think so, let me try first

  8. anonymous
    • 2 years ago
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    okay! thankk youu!

  9. anonymous
    • 2 years ago
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    i get a few tries to see if i got the question right so if you give me an answer i could put it in and see if youre right. and then you could explain it! but you cant round on anything! and this is only if youre willing to help me! sorry

  10. RANE
    • 2 years ago
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    ok i did it and i got 91.6m but im not sure if thats the answer

  11. anonymous
    • 2 years ago
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    did you round anything?

  12. RANE
    • 2 years ago
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    nop

  13. RANE
    • 2 years ago
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    was i suppose to?

  14. anonymous
    • 2 years ago
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    nope! okay let me check

  15. anonymous
    • 2 years ago
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    nope its wrong :(

  16. RANE
    • 2 years ago
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    whts the answer then?

  17. anonymous
    • 2 years ago
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    idk i can put in answers and it will tell me if its right or wrong

  18. RANE
    • 2 years ago
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    idk then i cant figure out any other way to do it

  19. anonymous
    • 2 years ago
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    its okay thanks anyways!

  20. RANE
    • 2 years ago
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    np:) but dont u have nay clue wht could be the answer around ?

  21. anonymous
    • 2 years ago
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    absolutely no idea lol

  22. RANE
    • 2 years ago
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    have u done q's like that before?

  23. anonymous
    • 2 years ago
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    not as hard!

  24. anonymous
    • 2 years ago
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    this one is really complex

  25. RANE
    • 2 years ago
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    sure it is

  26. RANE
    • 2 years ago
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    maybe he can help @UnkleRhaukus

  27. anonymous
    • 2 years ago
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    YES PLEASE @UnkleRhaukus lol

  28. anonymous
    • 2 years ago
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    |dw:1380448186791:dw| You know Vx and d. So you can calculate time t. Then you can find what the AP is by using \[\left| AP \right| =\frac{ g*t ^{2} }{ 2 }\] Then you can calculate BP easily. |BP|=|AB|-|AP|

  29. anonymous
    • 2 years ago
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    For target:\[h_t=h_0-1/2g t^2\]For bullet\[h_b=v_0\sin(\theta)t-1/2g t^2\]At time t_c both bodies collide:\[h_b=h_t \rightarrow v_0\sin(\theta)t_c-1/2g t_c^2=h_0-1/2g t_c^2 \rightarrow t_c=\frac{ h_0 }{ v_0\sin(\theta) }\]and at that moment, target is at:\[h_t(t_c)=h_0-\frac{ 1 }{ 2 }g \left( \frac{ h_0 }{ v_0\sin(\theta) } \right)^2=91.7-4.9·\left( \frac{ 91.7 }{ 109·\sin(48.4)} \right)^2\]

  30. anonymous
    • 2 years ago
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    and during time t_c, bullet has to cover distance "d". Let us see:\[x(t=t_c)=v_0\cos(\theta)t_c=v_0\cos(\theta)\frac{ h_0 }{ v_0\sin(\theta) }=h_0/\tan(\theta)=d\]

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