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natasha.aries

  • one year ago

***I WILL GIVE BEST ANSWER!***HEYY! CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION!? I HAVE A TEST COMING UP AND I AM SOO CONFUZZLED! PLEASE INCLUDE THE NUMBERS AND SOLUTIONS IN ANSWER! (please dont round)

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  1. natasha.aries
    • one year ago
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  2. natasha.aries
    • one year ago
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    The question is what is the height of where the collision takes place!

  3. RANE
    • one year ago
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    r u given the answer ?

  4. natasha.aries
    • one year ago
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    sadly, no :(

  5. RANE
    • one year ago
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    ahan well i dis q's like this last year , i think i remember it

  6. natasha.aries
    • one year ago
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    really!? how do u do it!?

  7. RANE
    • one year ago
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    i think so, let me try first

  8. natasha.aries
    • one year ago
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    okay! thankk youu!

  9. natasha.aries
    • one year ago
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    i get a few tries to see if i got the question right so if you give me an answer i could put it in and see if youre right. and then you could explain it! but you cant round on anything! and this is only if youre willing to help me! sorry

  10. RANE
    • one year ago
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    ok i did it and i got 91.6m but im not sure if thats the answer

  11. natasha.aries
    • one year ago
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    did you round anything?

  12. RANE
    • one year ago
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    nop

  13. RANE
    • one year ago
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    was i suppose to?

  14. natasha.aries
    • one year ago
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    nope! okay let me check

  15. natasha.aries
    • one year ago
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    nope its wrong :(

  16. RANE
    • one year ago
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    whts the answer then?

  17. natasha.aries
    • one year ago
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    idk i can put in answers and it will tell me if its right or wrong

  18. RANE
    • one year ago
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    idk then i cant figure out any other way to do it

  19. natasha.aries
    • one year ago
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    its okay thanks anyways!

  20. RANE
    • one year ago
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    np:) but dont u have nay clue wht could be the answer around ?

  21. natasha.aries
    • one year ago
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    absolutely no idea lol

  22. RANE
    • one year ago
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    have u done q's like that before?

  23. natasha.aries
    • one year ago
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    not as hard!

  24. natasha.aries
    • one year ago
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    this one is really complex

  25. RANE
    • one year ago
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    sure it is

  26. RANE
    • one year ago
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    maybe he can help @UnkleRhaukus

  27. natasha.aries
    • one year ago
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    YES PLEASE @UnkleRhaukus lol

  28. oksuz_
    • one year ago
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    |dw:1380448186791:dw| You know Vx and d. So you can calculate time t. Then you can find what the AP is by using \[\left| AP \right| =\frac{ g*t ^{2} }{ 2 }\] Then you can calculate BP easily. |BP|=|AB|-|AP|

  29. CarlosGP
    • one year ago
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    For target:\[h_t=h_0-1/2g t^2\]For bullet\[h_b=v_0\sin(\theta)t-1/2g t^2\]At time t_c both bodies collide:\[h_b=h_t \rightarrow v_0\sin(\theta)t_c-1/2g t_c^2=h_0-1/2g t_c^2 \rightarrow t_c=\frac{ h_0 }{ v_0\sin(\theta) }\]and at that moment, target is at:\[h_t(t_c)=h_0-\frac{ 1 }{ 2 }g \left( \frac{ h_0 }{ v_0\sin(\theta) } \right)^2=91.7-4.9·\left( \frac{ 91.7 }{ 109·\sin(48.4)} \right)^2\]

  30. CarlosGP
    • one year ago
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    and during time t_c, bullet has to cover distance "d". Let us see:\[x(t=t_c)=v_0\cos(\theta)t_c=v_0\cos(\theta)\frac{ h_0 }{ v_0\sin(\theta) }=h_0/\tan(\theta)=d\]

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