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nimamiz
If cos(t)=−3/5 where pi<t<3pi/2, find the values of the following trigonometric functions. Cos(t/2) Sin(t/2) I found the answers but for some reason Cos is negative and sin is positive. Aren't they both supposed to be negative?
Well if pi<t<3pi/2 then pi/2<t/2<3pi/4 And that area of the rectangular coordinate system, cos is negative and sin is positive since x is negative and y is positive there.
I just took the inequality given and divided by 2. t/2 is between pi/2 and 3pi/4
ohh. got it thanks buddy