A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
Mech88
 one year ago
2logx to the base 3  3log4 to the base 2 = log1 to the base b
Mech88
 one year ago
2logx to the base 3  3log4 to the base 2 = log1 to the base b

This Question is Open

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0What is the question?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1is this the question? \[2\log_{3}(x)  3\log_{2}(4) = \log_{b}(1)\]

Mech88
 one year ago
Best ResponseYou've already chosen the best response.0Yes... That's the question thank you

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1ok... so \[\log_{2}(4) = \log_{2}(2^2) = 2\] so you have \[\log_{3}(x^2)  6 = \log_{b}(1)\] so I'd suggest using change of base...

Mech88
 one year ago
Best ResponseYou've already chosen the best response.0How would I do that? I also get to that step but can't get further

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1ok... so this is how I would do the question, after rereading it the log of 1 to any base is always zero... its just a fact. and you saw how I managed the base 2 log of 4 so you have \[2\log_{3}(x)  6 = 0\] which becomes \[2 \log_{3}(x) = 6\] divide both sides of the equation by 2 \[\log_{3}(x) = 3\] now raise each side of the equation to the power of 3 \[3^{\log_{3}(x)} = 3^3\] which is x = 27
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.