Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
EdG
Group Title
Find the function y = y(x) such that the line tangent to the graph of y = y(x) at (x, y) intersects the xaxis at x/2 .
 11 months ago
 11 months ago
EdG Group Title
Find the function y = y(x) such that the line tangent to the graph of y = y(x) at (x, y) intersects the xaxis at x/2 .
 11 months ago
 11 months ago

This Question is Closed

EdG Group TitleBest ResponseYou've already chosen the best response.1
i know i have to end up with dy/dx = something but i cant figure out how to get there with this clue... any suggestions?
 11 months ago

wolfe8 Group TitleBest ResponseYou've already chosen the best response.0
Well, dy/dx is the gradient at a specific point of a curve.
 11 months ago

EdG Group TitleBest ResponseYou've already chosen the best response.1
ok, so i need to find the equation of the tangent line
 11 months ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
tangent line \[yy_1 = m(xx_1)\] \[m = \frac{dy}{dx}\] line crosses point (x/2 , 0) \[y_1 = \frac{dy}{dx}(\frac{x_1}{2}x_1)\] from here you can set up diff equ and separate variables to solve for y(x)
 11 months ago

EdG Group TitleBest ResponseYou've already chosen the best response.1
Got you, I see where im going now. The only thing im not sure about is the sign on y. Are u positive is negative?
 11 months ago

EdG Group TitleBest ResponseYou've already chosen the best response.1
im meant y being negative...
 11 months ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
yes because the line is tangent to curve at (x_1, y_1) the "y" value of line is 0 at x intercept 0  y_1 = y_1
 11 months ago

EdG Group TitleBest ResponseYou've already chosen the best response.1
Got it. So i solved it and got: \[y(x) = x^2 +C\] What do you think?
 11 months ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
yep well close, i get constant in front y = Cx^2
 11 months ago

EdG Group TitleBest ResponseYou've already chosen the best response.1
ahhhhh, yes. Because 2lnx + C becomes the exponent for e and e^C becomes C
 11 months ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
haha yeah was just going to say that :)
 11 months ago

EdG Group TitleBest ResponseYou've already chosen the best response.1
I always mess up whenever e or ln are involved
 11 months ago

EdG Group TitleBest ResponseYou've already chosen the best response.1
Thank you for your help, you got me out of a pickle :)
 11 months ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
no problem
 11 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.