## anonymous 2 years ago f(theta)=sin(theta)...solve f(theta/2)....theta =60 degrees

$$f(\theta) = \sin(\theta)$$ $$f \left(\dfrac{\theta}{2}\right) = \sin \left(\dfrac{\theta}{2} \right)$$ $$\theta = 60$$ $$f \left(\dfrac{60}{2}\right) = \sin \left(\dfrac{60}{2} \right)$$ $$f(30) = \sin(30)$$ $$f(30) = \dfrac{1}{2}$$