jennychan12
  • jennychan12
Integral of (−9sin(t)sec^2(cos(t))dt ?
Calculus1
katieb
  • katieb
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hartnn
  • hartnn
put u= cos t du =... ?
jennychan12
  • jennychan12
du = -sintdt
hartnn
  • hartnn
good, so your integral, 9 sec^2 (cos t) (-sin t dt) becomes, integral 9 sec^2u du right ?

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jennychan12
  • jennychan12
oh, i see now. thanks :)
hartnn
  • hartnn
cool, welcome ^_^

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