jennychan12
Integral of (−9sin(t)sec^2(cos(t))dt ?



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hartnn
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put u= cos t
du =... ?

jennychan12
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du = sintdt

hartnn
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good,
so your integral,
9 sec^2 (cos t) (sin t dt)
becomes, integral 9 sec^2u du
right ?

jennychan12
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oh, i see now. thanks :)

hartnn
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cool, welcome ^_^