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jennychan12

  • 2 years ago

Integral of (−9sin(t)sec^2(cos(t))dt ?

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  1. hartnn
    • 2 years ago
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    put u= cos t du =... ?

  2. jennychan12
    • 2 years ago
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    du = -sintdt

  3. hartnn
    • 2 years ago
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    good, so your integral, 9 sec^2 (cos t) (-sin t dt) becomes, integral 9 sec^2u du right ?

  4. jennychan12
    • 2 years ago
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    oh, i see now. thanks :)

  5. hartnn
    • 2 years ago
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    cool, welcome ^_^

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