Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
With respect to?
If the derivative of theta is 1, it has to be in respect to theta
The question asks me to find the derivative of H(theta)= thetasintheta
Not the answer you are looking for? Search for more explanations.
if with respect to theta, yes it's 1.
Nicole, I don't really understand the question you have. Could to rephase it at all?
it says: If H(theta)= thetas(sin theta), find H'(theta) and H"(theta)
Yeah, just do it the standard way.
If the question is H(Ø) = Øsin(Ø) and you're differentiating with respect to Ø, then you'd have to use the Product Rule here since you have one variable quantity, Ø, being multiplied by another variable quantity, sin(Ø). Thus...
H(Ø) = Øsin(Ø)
H'(Ø) = (1)(sin(Ø)) + (Ø)(cos(Ø)) = sin(Ø) + Øcos(Ø)
H''(Ø) = cos(Ø) + (1)(cos(Ø)) + (Ø)(–sin(Ø)) = 2cos(Ø) – Øsin(Ø)
Unless the question also gave you an initial condition or a value for Ø to plug in to the original function and/or its derivatives, I'm not very sure where the value of 1 came into the picture.