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primeralph Group TitleBest ResponseYou've already chosen the best response.0
With respect to?
 11 months ago

dmelando Group TitleBest ResponseYou've already chosen the best response.0
If the derivative of theta is 1, it has to be in respect to theta
 11 months ago

Nicole1313 Group TitleBest ResponseYou've already chosen the best response.0
The question asks me to find the derivative of H(theta)= thetasintheta
 11 months ago

primeralph Group TitleBest ResponseYou've already chosen the best response.0
if with respect to theta, yes it's 1.
 11 months ago

dmelando Group TitleBest ResponseYou've already chosen the best response.0
Nicole, I don't really understand the question you have. Could to rephase it at all?
 11 months ago

Nicole1313 Group TitleBest ResponseYou've already chosen the best response.0
it says: If H(theta)= thetas(sin theta), find H'(theta) and H"(theta)
 11 months ago

primeralph Group TitleBest ResponseYou've already chosen the best response.0
Yeah, just do it the standard way.
 11 months ago

AakashSudhakar Group TitleBest ResponseYou've already chosen the best response.0
If the question is H(Ø) = Øsin(Ø) and you're differentiating with respect to Ø, then you'd have to use the Product Rule here since you have one variable quantity, Ø, being multiplied by another variable quantity, sin(Ø). Thus... H(Ø) = Øsin(Ø) H'(Ø) = (1)(sin(Ø)) + (Ø)(cos(Ø)) = sin(Ø) + Øcos(Ø) H''(Ø) = cos(Ø) + (1)(cos(Ø)) + (Ø)(–sin(Ø)) = 2cos(Ø) – Øsin(Ø) Unless the question also gave you an initial condition or a value for Ø to plug in to the original function and/or its derivatives, I'm not very sure where the value of 1 came into the picture.
 11 months ago
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