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UnkleRhaukusBest ResponseYou've already chosen the best response.0
dw:1380875877019:dw
 6 months ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
dw:1380875928995:dw
 6 months ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
dw:1380876030469:dw
 6 months ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
is my diagram right?
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
sag in rope due to mass of rope ?
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
then u wud take 'mg = 2T cos(theta)' is it im not sure how the entire mass of rope gets manifested at center ?
 6 months ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
that's the tension at the end of the rope , but i'm looking for the tension in the middle
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
oh tension can be different thru out the rope in this system ?
 6 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
since the rope has mass... things may not be ideal hmm
 6 months ago

KainuiBest ResponseYou've already chosen the best response.0
Is this a rope of uniform density?
 6 months ago

KainuiBest ResponseYou've already chosen the best response.0
Is it in a vaccuum with a neutral charge?
 6 months ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
yes the rope is uniform density , and has a total mass of m
 6 months ago

wioBest ResponseYou've already chosen the best response.0
Tension at the middle? Where is the middle?
 6 months ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
yes i think we can make these assumptions
 6 months ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
yeah in the middle of the symmetric rope
 6 months ago

wioBest ResponseYou've already chosen the best response.0
It would depend on the length between tethers and the length of the rope.
 6 months ago

KainuiBest ResponseYou've already chosen the best response.0
So if we're leaving this general, it's just based on the angle, which doesn't really matter to us though.
 6 months ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
dw:1380883258783:dw
 6 months ago

KainuiBest ResponseYou've already chosen the best response.0
Unless they're telling us the length of the rope and the length of the distance it's stretched across, then we're screwed.
 6 months ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
the tensions should be a function of (m,θ,g)
 6 months ago

KainuiBest ResponseYou've already chosen the best response.0
So the rope's not moving right? That means the forces up and forces down should be equal, right? So... mg=2Tcos(theta) Solve for T, problem solved.
 6 months ago

wioBest ResponseYou've already chosen the best response.0
That's assuming all the mass is in the center?
 6 months ago

KainuiBest ResponseYou've already chosen the best response.0
Since it has a uniform density, center of mass is there, so it's safe assumption.
 6 months ago