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UnkleRhaukus

  • one year ago

Tension in a rope

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  1. UnkleRhaukus
    • one year ago
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    |dw:1380875877019:dw|

  2. UnkleRhaukus
    • one year ago
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    |dw:1380875928995:dw|

  3. UnkleRhaukus
    • one year ago
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    |dw:1380876030469:dw|

  4. UnkleRhaukus
    • one year ago
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    is my diagram right?

  5. ganeshie8
    • one year ago
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    sag in rope due to mass of rope ?

  6. UnkleRhaukus
    • one year ago
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    yes

  7. ganeshie8
    • one year ago
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    then u wud take 'mg = 2T cos(theta)' is it im not sure how the entire mass of rope gets manifested at center ?

  8. UnkleRhaukus
    • one year ago
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    that's the tension at the end of the rope , but i'm looking for the tension in the middle

  9. ganeshie8
    • one year ago
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    oh tension can be different thru out the rope in this system ?

  10. ganeshie8
    • one year ago
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    since the rope has mass... things may not be ideal hmm

  11. wio
    • one year ago
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    |dw:1380882967712:dw|

  12. Kainui
    • one year ago
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    Is this a rope of uniform density?

  13. Kainui
    • one year ago
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    Is it in a vaccuum with a neutral charge?

  14. UnkleRhaukus
    • one year ago
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    yes the rope is uniform density , and has a total mass of m

  15. wio
    • one year ago
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    Tension at the middle? Where is the middle?

  16. UnkleRhaukus
    • one year ago
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    yes i think we can make these assumptions

  17. UnkleRhaukus
    • one year ago
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    yeah in the middle of the symmetric rope

  18. wio
    • one year ago
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    It would depend on the length between tethers and the length of the rope.

  19. Kainui
    • one year ago
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    So if we're leaving this general, it's just based on the angle, which doesn't really matter to us though.

  20. UnkleRhaukus
    • one year ago
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    |dw:1380883258783:dw|

  21. Kainui
    • one year ago
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    Unless they're telling us the length of the rope and the length of the distance it's stretched across, then we're screwed.

  22. UnkleRhaukus
    • one year ago
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    the tensions should be a function of (m,θ,g)

  23. Kainui
    • one year ago
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    So the rope's not moving right? That means the forces up and forces down should be equal, right? So... mg=2Tcos(theta) Solve for T, problem solved.

  24. wio
    • one year ago
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    That's assuming all the mass is in the center?

  25. wio
    • one year ago
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    |dw:1380883547495:dw|

  26. wio
    • one year ago
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    |dw:1380883559040:dw|

  27. Kainui
    • one year ago
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    Since it has a uniform density, center of mass is there, so it's safe assumption.

  28. wio
    • one year ago
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    |dw:1380883578211:dw|

  29. Kainui
    • one year ago
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    |dw:1380883594219:dw|