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UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1380875877019:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1380875928995:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
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 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
is my diagram right?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
sag in rope due to mass of rope ?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
then u wud take 'mg = 2T cos(theta)' is it im not sure how the entire mass of rope gets manifested at center ?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
that's the tension at the end of the rope , but i'm looking for the tension in the middle
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
oh tension can be different thru out the rope in this system ?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
since the rope has mass... things may not be ideal hmm
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
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 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
Is this a rope of uniform density?
 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
Is it in a vaccuum with a neutral charge?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
yes the rope is uniform density , and has a total mass of m
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Tension at the middle? Where is the middle?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
yes i think we can make these assumptions
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
yeah in the middle of the symmetric rope
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
It would depend on the length between tethers and the length of the rope.
 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
So if we're leaving this general, it's just based on the angle, which doesn't really matter to us though.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1380883258783:dw
 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
Unless they're telling us the length of the rope and the length of the distance it's stretched across, then we're screwed.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
the tensions should be a function of (m,θ,g)
 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
So the rope's not moving right? That means the forces up and forces down should be equal, right? So... mg=2Tcos(theta) Solve for T, problem solved.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
That's assuming all the mass is in the center?
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
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wio Group TitleBest ResponseYou've already chosen the best response.0
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 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
Since it has a uniform density, center of mass is there, so it's safe assumption.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
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 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
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 one year ago