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UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1380875877019:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1380875928995:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1380876030469:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0is my diagram right?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0sag in rope due to mass of rope ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0then u wud take 'mg = 2T cos(theta)' is it im not sure how the entire mass of rope gets manifested at center ?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0that's the tension at the end of the rope , but i'm looking for the tension in the middle

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0oh tension can be different thru out the rope in this system ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0since the rope has mass... things may not be ideal hmm

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0Is this a rope of uniform density?

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0Is it in a vaccuum with a neutral charge?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0yes the rope is uniform density , and has a total mass of m

wio
 one year ago
Best ResponseYou've already chosen the best response.0Tension at the middle? Where is the middle?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0yes i think we can make these assumptions

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0yeah in the middle of the symmetric rope

wio
 one year ago
Best ResponseYou've already chosen the best response.0It would depend on the length between tethers and the length of the rope.

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0So if we're leaving this general, it's just based on the angle, which doesn't really matter to us though.

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1380883258783:dw

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0Unless they're telling us the length of the rope and the length of the distance it's stretched across, then we're screwed.

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0the tensions should be a function of (m,θ,g)

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0So the rope's not moving right? That means the forces up and forces down should be equal, right? So... mg=2Tcos(theta) Solve for T, problem solved.

wio
 one year ago
Best ResponseYou've already chosen the best response.0That's assuming all the mass is in the center?

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0Since it has a uniform density, center of mass is there, so it's safe assumption.