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anonymous
 2 years ago
2x1 < x^2
answers are: x < 1  sqrt(3) or x > 1+sqrt(3)
I'm having trouble coming up with these solutions. Could someone help me with the steps?
anonymous
 2 years ago
2x1 < x^2 answers are: x < 1  sqrt(3) or x > 1+sqrt(3) I'm having trouble coming up with these solutions. Could someone help me with the steps?

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myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Did you try looking at 2x1=x^2 first When we have f(x)=a, we try to solve this by doing f(x)=a of f(x)=a Now keep in mind that a needs to be positive or 0. Guess what? x^2 is a positive number or 0.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1I'm tell you to solve the following 2(x1)=x^2 or 2(x1)=x^2

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I've got it now. I thought that I tried that before, but I think I was just making so many mistakes that I became too sloppy and frustrated

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0getting rid of the inequalities made it a lot simpler.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0how would you know how to replace the inequalities back into the answer?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1One of the equations you solve, you will get a complex answer. The other equation you solve, will give you two real solutions. You should see x=1+sqrt(3) or x=1sqrt(3). You can test intervals to see where we have 2x1<x^2 dw:1380904061968:dw

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1380904086865:dw 2101<10^2 True/False 201<0^2 True/False 2101<10^2 True/False

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1The inequalities that come back true are the intervals you want to include in your solution.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1The first inequality, I went ahead and said 10^2 instead of (10)^2 since 10^2 is the same result at (10)^2.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0right, I get it now. I wasn't thinking about getting rid of the inequalities and just replacing them back at the end. it makes the process a lot simpler

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0and I was thrown off by the complex solution too
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