Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

can you take common factor on the left-hand side?

common factor would be sin(x) right?

... h... actually... after getting rid of the 1, yes

well... 2sin(x)

You add 1 to the right side but what would the left hand side look like after you simplify the gcf

hmmmm

So are you looking to solve 4u^3+2u^2-2u-1=0
Did you try to find the possible 0's?

or you could factor by grouping :) much simpler

Yes I am trying to solve for the possible solutions in degrees. How would you factor by grouping?

\[(4\sin^3(x)+2\sin^2(x))+(-2\sin(x)-1)=0\]

Look at those first two terms. They have common factor.
Look at the last terms. Factor out -1.

Or you can look at it in terms of u instead of sin at first. Your choice.

would it be 2sin^3(x) +sin(x)) + (2sin(x))=0 ?

\[(4u^3+2u^2)+(-2u-1)=0\]

What does 4u^3 and 2u^2 have in common?

2u^2? or just u^2?

2u^2(2u+1) + ( 2sin) = 0

(-2u-1)=-(2u+1)

So (-2sin(x)-1)=-(2sin(x)+1)

2u^2-1=0

Setting both factors equal to 0.

sin x +1 = 0
sin x = -1
and
sin^2x-1=0
sin^2x = 1

Your 2's are disappearing?

How would you convert that to degrees for the final answer?

sin(x)=-1/2
Did I just show you the unit circle?

is it 210 and 330 degrees?

so the four answers would be 30, 150, 210, and 330 degrees?

You solved sin(x)=-1/2 correctly.
So part of your answer is 210 and 330 degrees.

okay thanks for the help

Np. You got it from here?

yeah i got it.

Neatness.