anonymous
  • anonymous
Find a polynomial equation of degree 3 such that f(0)=31, f'(1)=4, f"(2)=2, and f'"(3)=6.
OCW Scholar - Single Variable Calculus
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

anonymous
  • anonymous
Find a polynomial equation of degree 3 such that f(0)=31, f'(1)=4, f"(2)=2, and f'"(3)=6.
OCW Scholar - Single Variable Calculus
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
You know that the function has to be f(x) = ax^3 + bx^2 + cx + 31. Next you know that the f'(x) = 3ax^2 + 2bx + c, and that f'(1) = 4, so we know that 3a + 2b + c = 4 Then f''(x) = 6ax + 2b, and f''(2) = 2, Therefore 12a + 2b = 2 Last but not least f'''(x) = 6a, and f'''(3) = 6, and with that you know that a = 1 Go back to 12a + 2b = 2, plug in a, and you get 12 + 2b = 2, therefore b = -5 Now you can go back to 3a + 2b + c = 4, plug in, and you will get 3 + (-10) + c = 4, and c = 11. Finally, you get the equation that f(x) = x^3 - 5x^2 + 11x + 31
anonymous
  • anonymous
thanks so muchhh :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.