anonymous
  • anonymous
Find the domain of the function.
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[f(x)=\sqrt[4]{x^2+3x}\]
myininaya
  • myininaya
Hint: Inside cannot be negative.
anonymous
  • anonymous
I don't understand how to start the problem. :/

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myininaya
  • myininaya
\[f(x)=\sqrt[4]{g(x)}\] Solve the following inequality: \[g(x) \ge 0\] Solving this will give you your domain.
myininaya
  • myininaya
Because g can be zero and it can be positive, but it cannot be negative.
myininaya
  • myininaya
Like you know whatever g is. In this case your g is x^2+3x
anonymous
  • anonymous
Um. I'm not good at math so I'm having trouble understanding what you are saying. sorry.
myininaya
  • myininaya
Can you do fourth root of a negative number? Would that exist?
anonymous
  • anonymous
I don't think you can do that.
myininaya
  • myininaya
like for real numbers anyways, no it wouldn't you are right that is why I'm allowing g to be positive or zero.
anonymous
  • anonymous
oh. so I just solve \[x^2+3x \ge0\]?
myininaya
  • myininaya
That is right.
anonymous
  • anonymous
thank you. :D
myininaya
  • myininaya
Np. Do you know how to solve it?
anonymous
  • anonymous
I think I do haha. Let me try it...
anonymous
  • anonymous
Um. Okay. I don't know how to. ):
myininaya
  • myininaya
Ok. Just think domain are the x values where the function can exist for. If you talk about range later, just ask yourself what are the y values where the function exist. --- Ok... So do you know how to solve x^2+3x=0?
anonymous
  • anonymous
yeah it would be x=0, -3... i think.
myininaya
  • myininaya
Yep yep...You did x(x+3)=0 which implies x=0 or x+3=0 great job... Now make a number line (on this number line you would include the zeros, -3 or 0 , but you would also include what x values made the expression not existing which we don't have any for x^2+3x) so here we go ---------------|-------------|----------- -3 0 Test all 3 intervals. You are looking for what intervals make x^2+3x positive since we are trying to solve x^2+3x>0 (We already solved when x^2+3x=0 ) (-4)^2+3(-4) (-1)^2+3(-1) (1)^2+3(1) = = = ---------------|-------------|----------- -3 0 Now all I'm doing is plugging in numbers around my zeros (-3 and 0) This is to test the intervals Remember we are looking for positive output Which one of those expressions I wrote above those intervals gives us positive output?
anonymous
  • anonymous
Sorry. The site was updating. ): The first and last intervals?
myininaya
  • myininaya
Yes so the domain is the first and last intervals include x=-3, 0. So you would state it as (-inf, -3] U [0, inf) We don't want to include anything in between -3 and 0 because like you said that gave us negative output. And yeah sorry os went down earlier.
anonymous
  • anonymous
Thank you! Your explanation was really helpful. (:

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