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|dw:1381226444353:dw|

This WILL be messy... are you up for it? :D

yes

\[m ^{^{2}}=11\]

What does that mean? D:

\[y=e ^{a}\]

Oh wait... there's no y' term?

get the higher order first D.E

So basically, it's
\[\Large y'' - 11y = xe^x\]?

\[m ^{2} +1 -12 =0\]

then m= square root of 11

then get the vlue of y

\[y=C{1}^{+\sqrt{11}x}+C{2}^{-\sqrt{11}x}\]

Im right? what is the next get the other y which from Xe^x

whic is y= Ae^u

take derivative until second derivative

ang get the value of A I stocked here

help guys if Im wrong :(

subst the value of Y" ,Y' and Y to the y′′+ y -12y

where did you get this y=Axex+Bex

are you sure the second term in the question isn't a derivative?

Odd, isn't it :D

apparently offline :(
Oh well, onwards and upwards XD

^_^
thanks