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terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1This WILL be messy... are you up for it? :D

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1For these kinds of differential equations, the general form of the solution is given by \[\Large f^{(h)}(x) + f^{(p)}(x)\] where the f^h is the general solution to the homogeneous equation while f^p is any particular solution of this equation. Can you find the general solution to the homogeneous equation?

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1What does that mean? D:

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1Oh wait... there's no y' term?

melmel
 one year ago
Best ResponseYou've already chosen the best response.0get the higher order first D.E

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1So basically, it's \[\Large y''  11y = xe^x\]?

melmel
 one year ago
Best ResponseYou've already chosen the best response.0then m= square root of 11

melmel
 one year ago
Best ResponseYou've already chosen the best response.0\[y=C{1}^{+\sqrt{11}x}+C{2}^{\sqrt{11}x}\]

melmel
 one year ago
Best ResponseYou've already chosen the best response.0Im right? what is the next get the other y which from Xe^x

melmel
 one year ago
Best ResponseYou've already chosen the best response.0take derivative until second derivative

melmel
 one year ago
Best ResponseYou've already chosen the best response.0ang get the value of A I stocked here

melmel
 one year ago
Best ResponseYou've already chosen the best response.0help guys if Im wrong :(

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1Well, if it doesn't work with only one undetermined coefficient, did you try 2? Specifically this: \[\Large y = \color{blue}Axe^x + \color{red}Be^x\]

melmel
 one year ago
Best ResponseYou've already chosen the best response.0subst the value of Y" ,Y' and Y to the y′′+ y 12y

melmel
 one year ago
Best ResponseYou've already chosen the best response.0where did you get this y=Axex+Bex

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1are you sure the second term in the question isn't a derivative?

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1Oh by the way, I didn't actually "get" that Axe^x + Be^x, for all intents and purposes, it IS just a guess... see if it gets you the coefficients you want, since Axe^x alone doesn't seem to do it.

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1if not (yes strange), then i think you (@melmel ) got the complementary homogenous solution \[\large f^h(x)=y_c(x)=C_{1}e^{+\sqrt{11}x}+C_{2}e^{\sqrt{11}x}\] {forgot to type the e's in the bases }

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1Which method to calculate the particular solution \[f^h(x)=y_p(x)\] are you going to use; undetermined coefficients, operator D , or variation of parameters, @melmel ?

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1apparently offline :( Oh well, onwards and upwards XD
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