Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
melmel
Group Title
linear D.E of nth order with constant coefficient...help guys
.
 one year ago
 one year ago
melmel Group Title
linear D.E of nth order with constant coefficient...help guys .
 one year ago
 one year ago

This Question is Open

melmel Group TitleBest ResponseYou've already chosen the best response.0
dw:1381226444353:dw
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
This WILL be messy... are you up for it? :D
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
For these kinds of differential equations, the general form of the solution is given by \[\Large f^{(h)}(x) + f^{(p)}(x)\] where the f^h is the general solution to the homogeneous equation while f^p is any particular solution of this equation. Can you find the general solution to the homogeneous equation?
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
\[m ^{^{2}}=11\]
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
What does that mean? D:
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
\[y=e ^{a}\]
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Oh wait... there's no y' term?
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
get the higher order first D.E
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
So basically, it's \[\Large y''  11y = xe^x\]?
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
\[m ^{2} +1 12 =0\]
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
then m= square root of 11
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
then get the vlue of y
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
\[y=C{1}^{+\sqrt{11}x}+C{2}^{\sqrt{11}x}\]
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
Im right? what is the next get the other y which from Xe^x
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
whic is y= Ae^u
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
take derivative until second derivative
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
ang get the value of A I stocked here
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
help guys if Im wrong :(
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Well, if it doesn't work with only one undetermined coefficient, did you try 2? Specifically this: \[\Large y = \color{blue}Axe^x + \color{red}Be^x\]
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
subst the value of Y" ,Y' and Y to the y′′+ y 12y
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
where did you get this y=Axex+Bex
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
are you sure the second term in the question isn't a derivative?
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Odd, isn't it :D
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Oh by the way, I didn't actually "get" that Axe^x + Be^x, for all intents and purposes, it IS just a guess... see if it gets you the coefficients you want, since Axe^x alone doesn't seem to do it.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
if not (yes strange), then i think you (@melmel ) got the complementary homogenous solution \[\large f^h(x)=y_c(x)=C_{1}e^{+\sqrt{11}x}+C_{2}e^{\sqrt{11}x}\] {forgot to type the e's in the bases }
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
Which method to calculate the particular solution \[f^h(x)=y_p(x)\] are you going to use; undetermined coefficients, operator D , or variation of parameters, @melmel ?
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
apparently offline :( Oh well, onwards and upwards XD
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
^_^ thanks
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.