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ABT
find the derivative of y with respect to x, t, or theta; y=x^6lnx-1/3x^3
by putting " ln " for both sides we get \[\ln y = \ln x ^{(6\ln x - 1)\div 3x ^{3}}\] then we get this equation \[\ln y = ( ( 6\ln x - 1) \div 3x ^{3} ) \times \ln x\] this equation is long to derive but easier than its first form