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mdholton32196
 one year ago
how do you get from tan(theta) + cot(theta) to equal sec(theta) csc(theta)
mdholton32196
 one year ago
how do you get from tan(theta) + cot(theta) to equal sec(theta) csc(theta)

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JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Substitute tanx=sinx/cosx and cotx=cosx/sinx. Add the fractions by finding like denominators and simplify.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0You will also need to use the Pythagorean identity for sinx and cosx.

sleung
 one year ago
Best ResponseYou've already chosen the best response.0\[\tan \theta+\cot \theta \]\[\frac{ \sin \theta }{ \cos \theta } + \frac{ \cos \theta }{ \sin \theta } \]\[\frac{ \sin ^{2}\theta }{ \cos \theta \sin \theta }+\frac{ \cos ^{2}\theta}{\cos \theta \sin \theta}\]\[\frac{ 1 }{ \sin \theta \cos \theta }\]\[\frac{ 1 }{ \sin \theta }\frac{ 1 }{ \cos \theta }\]\[\csc \theta \sec \theta\]
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