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mdholton32196
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how do you get from tan(theta) + cot(theta) to equal sec(theta) csc(theta)
 9 months ago
 9 months ago
mdholton32196 Group Title
how do you get from tan(theta) + cot(theta) to equal sec(theta) csc(theta)
 9 months ago
 9 months ago

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JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
Substitute tanx=sinx/cosx and cotx=cosx/sinx. Add the fractions by finding like denominators and simplify.
 9 months ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
You will also need to use the Pythagorean identity for sinx and cosx.
 9 months ago

sleung Group TitleBest ResponseYou've already chosen the best response.0
\[\tan \theta+\cot \theta \]\[\frac{ \sin \theta }{ \cos \theta } + \frac{ \cos \theta }{ \sin \theta } \]\[\frac{ \sin ^{2}\theta }{ \cos \theta \sin \theta }+\frac{ \cos ^{2}\theta}{\cos \theta \sin \theta}\]\[\frac{ 1 }{ \sin \theta \cos \theta }\]\[\frac{ 1 }{ \sin \theta }\frac{ 1 }{ \cos \theta }\]\[\csc \theta \sec \theta\]
 5 months ago
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