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mdholton32196

  • 2 years ago

how do you get from tan(theta) + cot(theta) to equal sec(theta) csc(theta)

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  1. JoannaBlackwelder
    • 2 years ago
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    Substitute tanx=sinx/cosx and cotx=cosx/sinx. Add the fractions by finding like denominators and simplify.

  2. JoannaBlackwelder
    • 2 years ago
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    You will also need to use the Pythagorean identity for sinx and cosx.

  3. sleung
    • 2 years ago
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    \[\tan \theta+\cot \theta \]\[\frac{ \sin \theta }{ \cos \theta } + \frac{ \cos \theta }{ \sin \theta } \]\[\frac{ \sin ^{2}\theta }{ \cos \theta \sin \theta }+\frac{ \cos ^{2}\theta}{\cos \theta \sin \theta}\]\[\frac{ 1 }{ \sin \theta \cos \theta }\]\[\frac{ 1 }{ \sin \theta }\frac{ 1 }{ \cos \theta }\]\[\csc \theta \sec \theta\]

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