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mdholton32196
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how do you get from tan(theta) + cot(theta) to equal sec(theta) csc(theta)
 one year ago
 one year ago
mdholton32196 Group Title
how do you get from tan(theta) + cot(theta) to equal sec(theta) csc(theta)
 one year ago
 one year ago

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JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
Substitute tanx=sinx/cosx and cotx=cosx/sinx. Add the fractions by finding like denominators and simplify.
 one year ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
You will also need to use the Pythagorean identity for sinx and cosx.
 one year ago

sleung Group TitleBest ResponseYou've already chosen the best response.0
\[\tan \theta+\cot \theta \]\[\frac{ \sin \theta }{ \cos \theta } + \frac{ \cos \theta }{ \sin \theta } \]\[\frac{ \sin ^{2}\theta }{ \cos \theta \sin \theta }+\frac{ \cos ^{2}\theta}{\cos \theta \sin \theta}\]\[\frac{ 1 }{ \sin \theta \cos \theta }\]\[\frac{ 1 }{ \sin \theta }\frac{ 1 }{ \cos \theta }\]\[\csc \theta \sec \theta\]
 9 months ago
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