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mdholton32196
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how do you get from tan(theta) + cot(theta) to equal sec(theta) csc(theta)
 11 months ago
 11 months ago
mdholton32196 Group Title
how do you get from tan(theta) + cot(theta) to equal sec(theta) csc(theta)
 11 months ago
 11 months ago

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JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
Substitute tanx=sinx/cosx and cotx=cosx/sinx. Add the fractions by finding like denominators and simplify.
 11 months ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
You will also need to use the Pythagorean identity for sinx and cosx.
 11 months ago

sleung Group TitleBest ResponseYou've already chosen the best response.0
\[\tan \theta+\cot \theta \]\[\frac{ \sin \theta }{ \cos \theta } + \frac{ \cos \theta }{ \sin \theta } \]\[\frac{ \sin ^{2}\theta }{ \cos \theta \sin \theta }+\frac{ \cos ^{2}\theta}{\cos \theta \sin \theta}\]\[\frac{ 1 }{ \sin \theta \cos \theta }\]\[\frac{ 1 }{ \sin \theta }\frac{ 1 }{ \cos \theta }\]\[\csc \theta \sec \theta\]
 7 months ago
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