dougliedigg
differentiate y=e^2x ln (x^2)



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alexgrossbard
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(e^(2xln(x^2)))(2ln(x^2)4)

saturnianalien
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\[y'(x)=\frac{2+\ln(x^2)}{e^2}\]

dougliedigg
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thank you!!

Anunnaki
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\[\frac{ 2e ^{2x} }{ x }2lnx ^{2}.e ^{2x}\]