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dougliedigg

  • 2 years ago

differentiate y=e^-2x ln (x^2)

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  1. alexgrossbard
    • 2 years ago
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    (e^(-2xln(x^2)))(-2ln(x^2)-4)

  2. saturnianalien
    • 2 years ago
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    \[y'(x)=\frac{2+\ln(x^2)}{e^2}\]

  3. dougliedigg
    • 2 years ago
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    thank you!!

  4. Anunnaki
    • 2 years ago
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    \[\frac{ 2e ^{-2x} }{ x }-2lnx ^{2}.e ^{-2x}\]

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