A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0hint > you want dy/dt so: dy/dt = (dy/dx) * (dx/dt)

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0which formula do i use?

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0you have dx/dt at this point and you have the point itself. that should help you

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0dy/dt = (dy/dx) * (dx/dt)

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0dy/dx means derivative of y with respect to x dx/dt is given at this point

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0but what formula should i use, for example there are problems for volume, circle, triangle, etc.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0distance formula?

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0ok so distance from the origin is s = sqrt(x^2 + y^2) so you want ds/dt = (ds/dy) * (dy/dt) + (ds/dx) * (dx/dt)

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0what does s symbolize?

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0so that is it. now you have it all

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0thanks let me try

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0you can, as well, to express y in terms of x in the distance formula and then find ds/dt = (ds/dx) * (dx/dt) it will be much more simple

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0right the whole 5*sqrt(2x+2) is throwing me off though,

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0im not sure if i should find the derivative of that function with respect to time.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0and the whole distance formula too.

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0ok so if we do it the way i said at the end : "you can, as well, to express y in terms of x in the distance formula and then find ds/dt = (ds/dx) * (dx/dt) it will be much more simple" then you dont have to do much

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0cause s=sqrt(x^2 + y^2) = sqrt(x^2+50x+50) now ds/dt = (ds/dx) * (dx/dt)

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0you just need to find ds/dx

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i did this: i found s=10.0499 then i found the derivative which i got 5/sqrt(2x+2) *dx/dt

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i got ds/dt as 10 but i know it's wrong.

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0you dont need to find s. you need to find ds/dx

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0since we express y in terms of x we dont need to worry about it anymore.

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0ds/dx = (x + 25)/sqrt(x^2+50x+50) at the point x=1 it is ds/dx = 26 / sqrt(101) so ds/dt = (26 / sqrt(101))* 4 i might done some mistake though

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0yeah im not sure what's happening.

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0why? s = sqrt(x^2+y^2) = sqrt(x^2+50x+50) so we want ds/dt ds/dt = ds/dx * dx/dt ds/dx = (x + 25)/sqrt(x^2+50x+50) ds/dx at this point = 26/sqrt(101) so ds/dt at this point = 26 * 4 /sqrt(101)

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0plugged into the derivative x=1 and dx/dt = 4

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0understand what i did ?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0sqrt(x^2+50x+50) ?

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0this is the distance.. s=sqrt(x^2 + y^2) = sqrt(x^2 + 50x + 50)

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i know, how'd you come up with this sqrt(x^2+50x+50)

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0plugged y=5sqrt(2x+2)

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i plugged in y and x

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0y=5sqrt(2x+2) y^2 = 50x+50

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0plugged y=5sqrt(2x+2). i plugged in y and x. 10=10

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0so now s = sqrt(x^2 + y^2) but since y^2 = 50x+50 s = sqrt(x^2+50x+50)

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0not the value of y at the point. plug y as a function of x

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0okay thanks alot.

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0s = sqrt(x^2+y^2) = sqrt(x^2+50x+50) so we want ds/dt ds/dt = ds/dx * dx/dt when we calculate ds/dx we calculate is using s as a function of x. not plugging numerical values yet. ds/dx = (x + 25)/sqrt(x^2+50x+50) now plug x=1 ds/dx at this point = 26/sqrt(101) so ds/dt at this point = 26 * 4 /sqrt(101)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.