SolomonZelman
  • SolomonZelman
x^3+Kx^2+12x-8, is divisible by (x-2) so that the remainder is 4 what is K?
Mathematics
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SOLVED
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chestercat
  • chestercat
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hartnn
  • hartnn
this is your question or you just testing other's knowledge again ?
SolomonZelman
  • SolomonZelman
Sorry if that is i nappropriate!
SolomonZelman
  • SolomonZelman
I'll close the question if this is inappropriate.

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More answers

nincompoop
  • nincompoop
very inappropriate
hartnn
  • hartnn
lol, how many times i need to tell you that its not inappropriate, but its not required! and i explained what harm can 'not required' do...
SolomonZelman
  • SolomonZelman
Close?
dan815
  • dan815
|dw:1381783626778:dw|
SolomonZelman
  • SolomonZelman
OK I'm closing?
hartnn
  • hartnn
more important is that you do not repeat this again
nincompoop
  • nincompoop
alt+F4 command works better
SolomonZelman
  • SolomonZelman
I won't do that again if it is inapp...
dan815
  • dan815
so u know that
SolomonZelman
  • SolomonZelman
yep!
SolomonZelman
  • SolomonZelman
Not this equation, but I can certainly do it.
hartnn
  • hartnn
see ? you just wasted 2 minutes of dan. thats the harm i am talking about...
hartnn
  • hartnn
he could have easily helped a needy fellow
SolomonZelman
  • SolomonZelman
OK I'll close.
dan815
  • dan815
lol
SolomonZelman
  • SolomonZelman
just did
SolomonZelman
  • SolomonZelman
Sorry guys! Ignore my math questions if other than calc!
dan815
  • dan815
|dw:1381783979271:dw|
dan815
  • dan815
sign error it shud be -5
SolomonZelman
  • SolomonZelman
What I am getting is that |dw:1381870420911:dw|
SolomonZelman
  • SolomonZelman
See why?
SolomonZelman
  • SolomonZelman
dan815, I don't help, really ignore me!
SolomonZelman
  • SolomonZelman
b/c remainder is 4, that's how....
myininaya
  • myininaya
Well we could have done this much easier way... let f be the expression you were fiven f(2)=4 solve for k .... \[2^3+k(2)^2+12(2)-8=8+4k+24-8=4k+24\] 4k+24=4
myininaya
  • myininaya
Solve for k.
SolomonZelman
  • SolomonZelman
I knew how to do it from the beginning...closed the question... Sorry!
myininaya
  • myininaya
I just wanted to make sure you guys know it wasn't as complicated as you were making it. :P
SolomonZelman
  • SolomonZelman
For sure not! Another way to do it is synthetic division... -8+2(16+2)k=4 -the remainder I get it don't worry.
myininaya
  • myininaya
Yep. That is a way to do it but I think it easier to do if given (poly of higher degree than 0)/(x-c), then all we need to do is that poly evaluated at c to find the remainder. f(c)=Remainder
SolomonZelman
  • SolomonZelman
Yes. U see what i did..... I know it 100% don't worry.
myininaya
  • myininaya
Ok. I'm not worried. I'm only responding here because I wanted to.
myininaya
  • myininaya
And also just in case someone else can learn from it.
SolomonZelman
  • SolomonZelman
let other ppl... they do
myininaya
  • myininaya
What?
SolomonZelman
  • SolomonZelman
know this, since they came to help..... But true, they were making it much more complicated than what it is.
SolomonZelman
  • SolomonZelman
(add to my prev comment)
SolomonZelman
  • SolomonZelman
WHATEVER.
myininaya
  • myininaya
Ok....
dan815
  • dan815
lol
dan815
  • dan815
calm down guys none of us like PHD students here -.- we're all noobs believe it or not
myininaya
  • myininaya
lol. I was just trying to help....
hartnn
  • hartnn
on a lost cause :P
myininaya
  • myininaya
Looks like it.
dan815
  • dan815
well it was helpful! i didnt think of just subbing in 2
myininaya
  • myininaya
Your way was cute too.
dan815
  • dan815
:)
dan815
  • dan815
how did u know that subbing in that value gives you the remainder though? like the way if its 0 then it is a good factor
myininaya
  • myininaya
Theorems.
myininaya
  • myininaya
I actually think it is called the remainder theorem.
dan815
  • dan815
oh ive heard of that before, thanks!
myininaya
  • myininaya
http://en.wikipedia.org/wiki/Polynomial_remainder_theorem

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