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SolomonZelman
 one year ago
x^3+Kx^2+12x8, is divisible by (x2)
so that the remainder is 4 what is K?
SolomonZelman
 one year ago
x^3+Kx^2+12x8, is divisible by (x2) so that the remainder is 4 what is K?

This Question is Closed

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0this is your question or you just testing other's knowledge again ?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Sorry if that is i nappropriate!

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1I'll close the question if this is inappropriate.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0lol, how many times i need to tell you that its not inappropriate, but its not required! and i explained what harm can 'not required' do...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0more important is that you do not repeat this again

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0alt+F4 command works better

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1I won't do that again if it is inapp...

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Not this equation, but I can certainly do it.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0see ? you just wasted 2 minutes of dan. thats the harm i am talking about...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0he could have easily helped a needy fellow

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Sorry guys! Ignore my math questions if other than calc!

dan815
 one year ago
Best ResponseYou've already chosen the best response.1sign error it shud be 5

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1What I am getting is that dw:1381870420911:dw

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1dan815, I don't help, really ignore me!

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1b/c remainder is 4, that's how....

myininaya
 one year ago
Best ResponseYou've already chosen the best response.2Well we could have done this much easier way... let f be the expression you were fiven f(2)=4 solve for k .... \[2^3+k(2)^2+12(2)8=8+4k+248=4k+24\] 4k+24=4

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1I knew how to do it from the beginning...closed the question... Sorry!

myininaya
 one year ago
Best ResponseYou've already chosen the best response.2I just wanted to make sure you guys know it wasn't as complicated as you were making it. :P

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1For sure not! Another way to do it is synthetic division... 8+2(16+2)k=4 the remainder I get it don't worry.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.2Yep. That is a way to do it but I think it easier to do if given (poly of higher degree than 0)/(xc), then all we need to do is that poly evaluated at c to find the remainder. f(c)=Remainder

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Yes. U see what i did..... I know it 100% don't worry.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.2Ok. I'm not worried. I'm only responding here because I wanted to.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.2And also just in case someone else can learn from it.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1let other ppl... they do

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1know this, since they came to help..... But true, they were making it much more complicated than what it is.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1(add to my prev comment)

dan815
 one year ago
Best ResponseYou've already chosen the best response.1calm down guys none of us like PHD students here . we're all noobs believe it or not

myininaya
 one year ago
Best ResponseYou've already chosen the best response.2lol. I was just trying to help....

dan815
 one year ago
Best ResponseYou've already chosen the best response.1well it was helpful! i didnt think of just subbing in 2

myininaya
 one year ago
Best ResponseYou've already chosen the best response.2Your way was cute too.

dan815
 one year ago
Best ResponseYou've already chosen the best response.1how did u know that subbing in that value gives you the remainder though? like the way if its 0 then it is a good factor

myininaya
 one year ago
Best ResponseYou've already chosen the best response.2I actually think it is called the remainder theorem.

dan815
 one year ago
Best ResponseYou've already chosen the best response.1oh ive heard of that before, thanks!
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