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SolomonZelman
 2 years ago
x^3+Kx^2+12x8, is divisible by (x2)
so that the remainder is 4 what is K?
SolomonZelman
 2 years ago
x^3+Kx^2+12x8, is divisible by (x2) so that the remainder is 4 what is K?

This Question is Closed

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0this is your question or you just testing other's knowledge again ?

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1Sorry if that is i nappropriate!

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1I'll close the question if this is inappropriate.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0lol, how many times i need to tell you that its not inappropriate, but its not required! and i explained what harm can 'not required' do...

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0more important is that you do not repeat this again

nincompoop
 2 years ago
Best ResponseYou've already chosen the best response.0alt+F4 command works better

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1I won't do that again if it is inapp...

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1Not this equation, but I can certainly do it.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0see ? you just wasted 2 minutes of dan. thats the harm i am talking about...

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0he could have easily helped a needy fellow

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1Sorry guys! Ignore my math questions if other than calc!

dan815
 2 years ago
Best ResponseYou've already chosen the best response.1sign error it shud be 5

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1What I am getting is that dw:1381870420911:dw

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1dan815, I don't help, really ignore me!

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1b/c remainder is 4, that's how....

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Well we could have done this much easier way... let f be the expression you were fiven f(2)=4 solve for k .... \[2^3+k(2)^2+12(2)8=8+4k+248=4k+24\] 4k+24=4

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1I knew how to do it from the beginning...closed the question... Sorry!

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2I just wanted to make sure you guys know it wasn't as complicated as you were making it. :P

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1For sure not! Another way to do it is synthetic division... 8+2(16+2)k=4 the remainder I get it don't worry.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Yep. That is a way to do it but I think it easier to do if given (poly of higher degree than 0)/(xc), then all we need to do is that poly evaluated at c to find the remainder. f(c)=Remainder

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1Yes. U see what i did..... I know it 100% don't worry.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Ok. I'm not worried. I'm only responding here because I wanted to.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2And also just in case someone else can learn from it.

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1let other ppl... they do

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1know this, since they came to help..... But true, they were making it much more complicated than what it is.

SolomonZelman
 2 years ago
Best ResponseYou've already chosen the best response.1(add to my prev comment)

dan815
 2 years ago
Best ResponseYou've already chosen the best response.1calm down guys none of us like PHD students here . we're all noobs believe it or not

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2lol. I was just trying to help....

dan815
 2 years ago
Best ResponseYou've already chosen the best response.1well it was helpful! i didnt think of just subbing in 2

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Your way was cute too.

dan815
 2 years ago
Best ResponseYou've already chosen the best response.1how did u know that subbing in that value gives you the remainder though? like the way if its 0 then it is a good factor

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2I actually think it is called the remainder theorem.

dan815
 2 years ago
Best ResponseYou've already chosen the best response.1oh ive heard of that before, thanks!
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