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iambatman Group TitleBest ResponseYou've already chosen the best response.1
dw:1381786279195:dw
 one year ago

iambatman Group TitleBest ResponseYou've already chosen the best response.1
Quotient rule on both side
 one year ago

2pie Group TitleBest ResponseYou've already chosen the best response.0
dw:1381786349930:dw
 one year ago

2pie Group TitleBest ResponseYou've already chosen the best response.0
is it correct? what do I do next
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Good so far.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{yxy'}{y^2}=\frac{xy'y}{x^2}\] I would clear the fractions first.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Multiply both sides by x^2y^2.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[x^2y^2 \frac{yxy'}{y^2}=x^2y^2\frac{xy'y}{x^2}\] You see that we can write this without the fractional style now, right?
 one year ago

2pie Group TitleBest ResponseYou've already chosen the best response.0
yes by calcelling the \[y ^{2} x^{2}\] on each side respectively \[x^{2}(yxy^1)+y^2(xy^1y)\] then?
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Distribute. Put y' terms on one side and the other nony' terms on the other side Then factor y' out. The divide by whatever is being multiplied by y'.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You mean equal right not plus?
 one year ago

2pie Group TitleBest ResponseYou've already chosen the best response.0
After I multiply I got\[x^2yx^3y^\prime =xy^2y^\primey^3\]
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Right. Continue. Put y' terms together on one side and then nony' terms on the other.
 one year ago

2pie Group TitleBest ResponseYou've already chosen the best response.0
\[x^2y+y^3=xy^2y^\prime + x^3 y^\prime\]
 one year ago

2pie Group TitleBest ResponseYou've already chosen the best response.0
then im not sure what to do
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Factor the y' out on that one side.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[x^2y+y^3=y'(xy^2+x^3)\]
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Divide both sides by what y' is being multiplied by.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You can reduce your answer.
 one year ago

2pie Group TitleBest ResponseYou've already chosen the best response.0
\[x^2y+y^3/xy^2+x^3\]=\[y^\prime\]
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[y'=\frac{x^2y+y^3}{xy^2+x^3} =\frac{y(x^2+y^2)}{x(y^2+x^2)}\] Anything cancel?
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Now instead of starting the way you guys did at the beginning. I think @hartnn would like to show you a easier way.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
hey 2pie since we have x/y = y/x can we say x^2 = y^2 ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
i just did a crossmultiplication
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I think the slope can be simplified even more by the way when you guys are done. :)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
and then we can differentiate x^2=y^2 to get 2x =2y dy/dx can you isolaye dy/dx from this ?
 one year ago

2pie Group TitleBest ResponseYou've already chosen the best response.0
yes by dividing 2y on both sides
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
and what would u get finally ? as dy/dx ?
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
And recall from your initial equation y/x=x/y
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Now another way... x^2=y^2 or x^2y^2=0 or (xy)(x+y)=0 or xy=0 or x+y=0 or y=x or y=x If y=x, then y'=1 If y=x, then y'=1
 one year ago

2pie Group TitleBest ResponseYou've already chosen the best response.0
wow it was easier than I thought thank you very much for your help and time @myininaya @hartnn :)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
i see you are new here , so \[ \begin{array}l\color{red}{\text{W}}\color{orange}{\text{e}}\color{#e6e600}{\text{l}}\color{green}{\text{c}}\color{blue}{\text{o}}\color{purple}{\text{m}}\color{purple}{\text{e}}\color{red}{\text{ }}\color{orange}{\text{t}}\color{#e6e600}{\text{o}}\color{green}{\text{ }}\color{blue}{\text{O}}\color{purple}{\text{p}}\color{purple}{\text{e}}\color{red}{\text{n}}\color{orange}{\text{S}}\color{#e6e600}{\text{t}}\color{green}{\text{u}}\color{blue}{\text{d}}\color{purple}{\text{y}}\color{purple}{\text{!}}\color{red}{\text{!}}\color{orange}{\text{ }}\color{#e6e600}{\text{:}}\color{green}{\text{)}}\color{blue}{\text{}}\end{array} \]
 one year ago

2pie Group TitleBest ResponseYou've already chosen the best response.0
thank you Im really glad I joined
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Who couldn't pass up free math help?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
we too are glad that you joined :)
 one year ago
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