## anonymous 2 years ago Help! Implicit Differentiation with Radicals :(

1. anonymous

2. Loser66

what do you get so far?

3. anonymous

I'll send it right now, 1 sec.

4. anonymous

5. anonymous

@Loser66

6. Loser66

me here but don't know the reason why cannot open the attachment

7. Loser66

take derivative both sides, the right hand side give you 0, the left hand side has 2 terms, what do you get for the first term

8. anonymous

i got some of it but i didn't get (3+2y) in the numerator.

9. anonymous

|dw:1381795463590:dw|

10. Loser66

$(\sqrt{3x+2y})' +(\sqrt{4xy})'= \frac {3+2y'}{2\sqrt{3x+2y}} +\frac{4y+4xy'}{2\sqrt{4xy}}$

11. Loser66

you have to use chain rule,

12. Loser66

|dw:1381795702483:dw|

13. Loser66

right?

14. anonymous

|dw:1381795570646:dw|

15. Loser66

the net is sooooo bad, ok, let me write it out.

16. anonymous

so why did you bring this on top in the numerator?

17. Loser66

18. Loser66

y is function of x, cannot take derivative as x, derivative of y is y'

19. Loser66

ridiculous the net, me here but I am invisible, hehehe

20. phi

|dw:1381798106573:dw|