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Loser66
 one year ago
Best ResponseYou've already chosen the best response.0what do you get so far?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0I'll send it right now, 1 sec.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0me here but don't know the reason why cannot open the attachment

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0take derivative both sides, the right hand side give you 0, the left hand side has 2 terms, what do you get for the first term

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i got some of it but i didn't get (3+2y) in the numerator.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1381795463590:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0\[(\sqrt{3x+2y})' +(\sqrt{4xy})'= \frac {3+2y'}{2\sqrt{3x+2y}} +\frac{4y+4xy'}{2\sqrt{4xy}}\]

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0you have to use chain rule,

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1381795570646:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0the net is sooooo bad, ok, let me write it out.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0so why did you bring this on top in the numerator?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0y is function of x, cannot take derivative as x, derivative of y is y'

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0ridiculous the net, me here but I am invisible, hehehe
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