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mathcalculus

  • 2 years ago

Help! Implicit Differentiation with Radicals :(

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  1. mathcalculus
    • 2 years ago
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  2. Loser66
    • 2 years ago
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    what do you get so far?

  3. mathcalculus
    • 2 years ago
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    I'll send it right now, 1 sec.

  4. mathcalculus
    • 2 years ago
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    1 Attachment
  5. mathcalculus
    • 2 years ago
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    @Loser66

  6. Loser66
    • 2 years ago
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    me here but don't know the reason why cannot open the attachment

  7. Loser66
    • 2 years ago
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    take derivative both sides, the right hand side give you 0, the left hand side has 2 terms, what do you get for the first term

  8. mathcalculus
    • 2 years ago
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    i got some of it but i didn't get (3+2y) in the numerator.

  9. mathcalculus
    • 2 years ago
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    |dw:1381795463590:dw|

  10. Loser66
    • 2 years ago
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    \[(\sqrt{3x+2y})' +(\sqrt{4xy})'= \frac {3+2y'}{2\sqrt{3x+2y}} +\frac{4y+4xy'}{2\sqrt{4xy}}\]

  11. Loser66
    • 2 years ago
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    you have to use chain rule,

  12. Loser66
    • 2 years ago
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    |dw:1381795702483:dw|

  13. Loser66
    • 2 years ago
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    right?

  14. mathcalculus
    • 2 years ago
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    |dw:1381795570646:dw|

  15. Loser66
    • 2 years ago
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    the net is sooooo bad, ok, let me write it out.

  16. mathcalculus
    • 2 years ago
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    so why did you bring this on top in the numerator?

  17. Loser66
    • 2 years ago
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    1 Attachment
  18. Loser66
    • 2 years ago
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    y is function of x, cannot take derivative as x, derivative of y is y'

  19. Loser66
    • 2 years ago
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    ridiculous the net, me here but I am invisible, hehehe

  20. phi
    • 2 years ago
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    |dw:1381798106573:dw|

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