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Loser66Best ResponseYou've already chosen the best response.0
what do you get so far?
 6 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
I'll send it right now, 1 sec.
 6 months ago

Loser66Best ResponseYou've already chosen the best response.0
me here but don't know the reason why cannot open the attachment
 6 months ago

Loser66Best ResponseYou've already chosen the best response.0
take derivative both sides, the right hand side give you 0, the left hand side has 2 terms, what do you get for the first term
 6 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
i got some of it but i didn't get (3+2y) in the numerator.
 6 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
dw:1381795463590:dw
 6 months ago

Loser66Best ResponseYou've already chosen the best response.0
\[(\sqrt{3x+2y})' +(\sqrt{4xy})'= \frac {3+2y'}{2\sqrt{3x+2y}} +\frac{4y+4xy'}{2\sqrt{4xy}}\]
 6 months ago

Loser66Best ResponseYou've already chosen the best response.0
you have to use chain rule,
 6 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
dw:1381795570646:dw
 6 months ago

Loser66Best ResponseYou've already chosen the best response.0
the net is sooooo bad, ok, let me write it out.
 6 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
so why did you bring this on top in the numerator?
 6 months ago

Loser66Best ResponseYou've already chosen the best response.0
y is function of x, cannot take derivative as x, derivative of y is y'
 6 months ago

Loser66Best ResponseYou've already chosen the best response.0
ridiculous the net, me here but I am invisible, hehehe
 6 months ago
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