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Loser66 Group TitleBest ResponseYou've already chosen the best response.0
what do you get so far?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
I'll send it right now, 1 sec.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
@Loser66
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
me here but don't know the reason why cannot open the attachment
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
take derivative both sides, the right hand side give you 0, the left hand side has 2 terms, what do you get for the first term
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i got some of it but i didn't get (3+2y) in the numerator.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
dw:1381795463590:dw
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
\[(\sqrt{3x+2y})' +(\sqrt{4xy})'= \frac {3+2y'}{2\sqrt{3x+2y}} +\frac{4y+4xy'}{2\sqrt{4xy}}\]
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
you have to use chain rule,
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
dw:1381795702483:dw
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
dw:1381795570646:dw
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
the net is sooooo bad, ok, let me write it out.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
so why did you bring this on top in the numerator?
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
y is function of x, cannot take derivative as x, derivative of y is y'
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
ridiculous the net, me here but I am invisible, hehehe
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
dw:1381798106573:dw
 one year ago
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