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deepthiakella1

  • 2 years ago

hey find the points of inflection on f(x)=6x^4-x^2 thanksss oh and i got plus or minus 1/6

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  1. wilfley
    • 2 years ago
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    was that not correct?

  2. Easyaspi314
    • 2 years ago
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    f'(x) = 24x^3 - 2x f''(x) = 72x^2 - 2 set f''(x) = 0...you get 2(36x^2 - 1) = 0, or x = +1/6 and -1/6 Now, set up an interval chart to see where concavity, if any, exists.

  3. deepthiakella1
    • 2 years ago
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    ok

  4. deepthiakella1
    • 2 years ago
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    do you plug in the number to the first der. ?

  5. deepthiakella1
    • 2 years ago
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    to check for concavity

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