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deepthiakella1 Group Title

hey find the points of inflection on f(x)=6x^4-x^2 thanksss oh and i got plus or minus 1/6

  • 10 months ago
  • 10 months ago

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  1. wilfley Group Title
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    was that not correct?

    • 10 months ago
  2. Easyaspi314 Group Title
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    f'(x) = 24x^3 - 2x f''(x) = 72x^2 - 2 set f''(x) = 0...you get 2(36x^2 - 1) = 0, or x = +1/6 and -1/6 Now, set up an interval chart to see where concavity, if any, exists.

    • 10 months ago
  3. deepthiakella1 Group Title
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    ok

    • 10 months ago
  4. deepthiakella1 Group Title
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    do you plug in the number to the first der. ?

    • 10 months ago
  5. deepthiakella1 Group Title
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    to check for concavity

    • 10 months ago
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