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can you find slope of any given line ?

like say , x-5y = -10 is a line.
can you find slope of this line first ?

Uh no not really... with a quick review I probably can

Yeah I got it

cool, so can you find the slope of x -3y=9 line ? in same way

oh and i forgot to mention,
y= (1/5)x +2
comparing with y=mx+c
gives, m=slope = 1/5

x-37=9
-3y=x+9
Y=(1/3)x+3

So slope would be 1/3 I assume?

correct! :)
now try to find slopes of other 3 lines also!
and tell me, so that i will verify :)

4x+2y=5
2y=-4x+5
Y-(-1/2)x+2.5 ?

2y=-4x+5 is correct, but then divide both sides by 2
what u get ?

10x-5y=8
-5y=10x+8
Y=-2x+1.6?

10x-5y=8
-5y=10x+8 <<<<<

and you would get y=-2+2.5

Ahh okay -10 so the problem would come out with a positive 2x

yes, so the slope will be m= 2 , right ?

Yes

4x+2y=5 slope = -2
make a note of all slopes, we'll need them

and what about last line ?

4x+y=-1
Y=-4x-1

so, slope =?

-4

Yeah I got it, Thanks a ton man. You need to be my teacher xD

haha, :)
but we still require to do the 1st 2 !

Ahhhh okay

because perpendicular lines follow different rule :)

Well I still don't exactly get how it goes from (1/5) to -1...

product of slopes = -1 is the rule
so, m (1/5) =-1
multiplying by 5,
m = -5
got this ?

multiplying by 5 on both sides.

Okay, so basically whenever there is a fraction just take (1/_) blank space number lol

you forgot the negative :P
-1/ stuff

but this only applies to perpendicular lines

for parallel lines, slope are equal

Oh I see says the blind man

what who ?

lol

i hope you got the entire problem clearly ?

ask if any doubts anywhere

Yeah I get it now man thanks a ton

welcome ^_^