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Mttblink Group Title

Help with these:/ I don't understand

  • 10 months ago
  • 10 months ago

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  1. Mttblink Group Title
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    • 10 months ago
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  2. hartnn Group Title
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    can you find slope of any given line ?

    • 10 months ago
  3. hartnn Group Title
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    like say , x-5y = -10 is a line. can you find slope of this line first ?

    • 10 months ago
  4. Mttblink Group Title
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    Uh no not really... with a quick review I probably can

    • 10 months ago
  5. hartnn Group Title
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    good, so i have x-5y =-10 i will try to isolate y and bring it in the form y=mx+c where m=slope so, x=5y-10 5y = x+10 y= (1/5)x +2 got this ?

    • 10 months ago
  6. Mttblink Group Title
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    Yeah I got it

    • 10 months ago
  7. hartnn Group Title
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    cool, so can you find the slope of x -3y=9 line ? in same way

    • 10 months ago
  8. hartnn Group Title
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    oh and i forgot to mention, y= (1/5)x +2 comparing with y=mx+c gives, m=slope = 1/5

    • 10 months ago
  9. Mttblink Group Title
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    x-37=9 -3y=x+9 Y=(1/3)x+3

    • 10 months ago
  10. Mttblink Group Title
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    So slope would be 1/3 I assume?

    • 10 months ago
  11. hartnn Group Title
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    correct! :) now try to find slopes of other 3 lines also! and tell me, so that i will verify :)

    • 10 months ago
  12. Mttblink Group Title
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    4x+2y=5 2y=-4x+5 Y-(-1/2)x+2.5 ?

    • 10 months ago
  13. hartnn Group Title
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    2y=-4x+5 is correct, but then divide both sides by 2 what u get ?

    • 10 months ago
  14. Mttblink Group Title
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    10x-5y=8 -5y=10x+8 Y=-2x+1.6?

    • 10 months ago
  15. hartnn Group Title
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    10x-5y=8 -5y=10x+8 <<<<<<NO! -5y = -10x +8

    • 10 months ago
  16. Mttblink Group Title
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    and you would get y=-2+2.5

    • 10 months ago
  17. Mttblink Group Title
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    Ahh okay -10 so the problem would come out with a positive 2x

    • 10 months ago
  18. hartnn Group Title
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    yes, so the slope will be m= 2 , right ?

    • 10 months ago
  19. Mttblink Group Title
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    Yes

    • 10 months ago
  20. hartnn Group Title
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    4x+2y=5 slope = -2 make a note of all slopes, we'll need them

    • 10 months ago
  21. hartnn Group Title
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    and what about last line ?

    • 10 months ago
  22. Mttblink Group Title
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    4x+y=-1 Y=-4x-1

    • 10 months ago
  23. hartnn Group Title
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    so, slope =?

    • 10 months ago
  24. Mttblink Group Title
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    -4

    • 10 months ago
  25. hartnn Group Title
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    Good! now here's the rule : slope of parallel lines are equal! so, for the last one, slope of line parallel to 4x+y=-1 will also be m=-4 :) so, for last, the correct option will be `C) m=-4` got this ? in same way, can you match the 2nd last and 3rd last ?

    • 10 months ago
  26. Mttblink Group Title
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    Yeah I got it, Thanks a ton man. You need to be my teacher xD

    • 10 months ago
  27. hartnn Group Title
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    haha, :) but we still require to do the 1st 2 !

    • 10 months ago
  28. hartnn Group Title
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    another rule, `product of slopes of perpendicular lines = -1 ` so, for 1st one we had slope = 1/5 let slope of perpendicular line be m. so, \(\Large m\times (1/5)=-1\) find m from here :)

    • 10 months ago
  29. Mttblink Group Title
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    1st one is m=1/5? 2cnd one is m=1/3? It seems like these would be the answers but they are not possible to be selected.

    • 10 months ago
  30. Mttblink Group Title
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    Ahhhh okay

    • 10 months ago
  31. hartnn Group Title
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    because perpendicular lines follow different rule :)

    • 10 months ago
  32. Mttblink Group Title
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    Well I still don't exactly get how it goes from (1/5) to -1...

    • 10 months ago
  33. hartnn Group Title
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    product of slopes = -1 is the rule so, m (1/5) =-1 multiplying by 5, m = -5 got this ?

    • 10 months ago
  34. hartnn Group Title
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    multiplying by 5 on both sides.

    • 10 months ago
  35. Mttblink Group Title
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    I'm confused on the product of slopes part, I get the multiplying on both sides. So like can you explain the product of slopes rule.. I tried looking it up on google but nothing I can comprehend really comes up.

    • 10 months ago
  36. hartnn Group Title
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    if say line 1 has slope M1 and line 2 has slope M2 now if these 2 lines are perpendicular to each other, then M1*M2 =-1

    • 10 months ago
  37. hartnn Group Title
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    another way to remember the same thing is, the slope of line is negative reciprocal of the perpendicular line, so, slope of line perpendicular to line with slope 1/5 will be - (1/(1/5)) = -5

    • 10 months ago
  38. hartnn Group Title
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    so, thats your 1st one, m =-5 for 2nd one, we had slope = 1/3, so m *(1/3) = -1 so, m=-3 is the answer to 2nd one :)

    • 10 months ago
  39. Mttblink Group Title
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    Okay, so basically whenever there is a fraction just take (1/_) blank space number lol

    • 10 months ago
  40. hartnn Group Title
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    you forgot the negative :P -1/ stuff

    • 10 months ago
  41. hartnn Group Title
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    but this only applies to perpendicular lines

    • 10 months ago
  42. hartnn Group Title
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    for parallel lines, slope are equal

    • 10 months ago
  43. Mttblink Group Title
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    Oh I see says the blind man

    • 10 months ago
  44. hartnn Group Title
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    what who ?

    • 10 months ago
  45. hartnn Group Title
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    lol

    • 10 months ago
  46. hartnn Group Title
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    i hope you got the entire problem clearly ?

    • 10 months ago
  47. hartnn Group Title
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    ask if any doubts anywhere

    • 10 months ago
  48. Mttblink Group Title
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    Yeah I get it now man thanks a ton

    • 10 months ago
  49. hartnn Group Title
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    welcome ^_^

    • 10 months ago
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