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Mttblink

  • one year ago

Help with these:/ I don't understand

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  1. Mttblink
    • one year ago
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  2. hartnn
    • one year ago
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    can you find slope of any given line ?

  3. hartnn
    • one year ago
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    like say , x-5y = -10 is a line. can you find slope of this line first ?

  4. Mttblink
    • one year ago
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    Uh no not really... with a quick review I probably can

  5. hartnn
    • one year ago
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    good, so i have x-5y =-10 i will try to isolate y and bring it in the form y=mx+c where m=slope so, x=5y-10 5y = x+10 y= (1/5)x +2 got this ?

  6. Mttblink
    • one year ago
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    Yeah I got it

  7. hartnn
    • one year ago
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    cool, so can you find the slope of x -3y=9 line ? in same way

  8. hartnn
    • one year ago
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    oh and i forgot to mention, y= (1/5)x +2 comparing with y=mx+c gives, m=slope = 1/5

  9. Mttblink
    • one year ago
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    x-37=9 -3y=x+9 Y=(1/3)x+3

  10. Mttblink
    • one year ago
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    So slope would be 1/3 I assume?

  11. hartnn
    • one year ago
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    correct! :) now try to find slopes of other 3 lines also! and tell me, so that i will verify :)

  12. Mttblink
    • one year ago
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    4x+2y=5 2y=-4x+5 Y-(-1/2)x+2.5 ?

  13. hartnn
    • one year ago
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    2y=-4x+5 is correct, but then divide both sides by 2 what u get ?

  14. Mttblink
    • one year ago
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    10x-5y=8 -5y=10x+8 Y=-2x+1.6?

  15. hartnn
    • one year ago
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    10x-5y=8 -5y=10x+8 <<<<<<NO! -5y = -10x +8

  16. Mttblink
    • one year ago
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    and you would get y=-2+2.5

  17. Mttblink
    • one year ago
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    Ahh okay -10 so the problem would come out with a positive 2x

  18. hartnn
    • one year ago
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    yes, so the slope will be m= 2 , right ?

  19. Mttblink
    • one year ago
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    Yes

  20. hartnn
    • one year ago
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    4x+2y=5 slope = -2 make a note of all slopes, we'll need them

  21. hartnn
    • one year ago
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    and what about last line ?

  22. Mttblink
    • one year ago
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    4x+y=-1 Y=-4x-1

  23. hartnn
    • one year ago
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    so, slope =?

  24. Mttblink
    • one year ago
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    -4

  25. hartnn
    • one year ago
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    Good! now here's the rule : slope of parallel lines are equal! so, for the last one, slope of line parallel to 4x+y=-1 will also be m=-4 :) so, for last, the correct option will be `C) m=-4` got this ? in same way, can you match the 2nd last and 3rd last ?

  26. Mttblink
    • one year ago
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    Yeah I got it, Thanks a ton man. You need to be my teacher xD

  27. hartnn
    • one year ago
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    haha, :) but we still require to do the 1st 2 !

  28. hartnn
    • one year ago
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    another rule, `product of slopes of perpendicular lines = -1 ` so, for 1st one we had slope = 1/5 let slope of perpendicular line be m. so, \(\Large m\times (1/5)=-1\) find m from here :)

  29. Mttblink
    • one year ago
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    1st one is m=1/5? 2cnd one is m=1/3? It seems like these would be the answers but they are not possible to be selected.

  30. Mttblink
    • one year ago
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    Ahhhh okay

  31. hartnn
    • one year ago
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    because perpendicular lines follow different rule :)

  32. Mttblink
    • one year ago
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    Well I still don't exactly get how it goes from (1/5) to -1...

  33. hartnn
    • one year ago
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    product of slopes = -1 is the rule so, m (1/5) =-1 multiplying by 5, m = -5 got this ?

  34. hartnn
    • one year ago
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    multiplying by 5 on both sides.

  35. Mttblink
    • one year ago
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    I'm confused on the product of slopes part, I get the multiplying on both sides. So like can you explain the product of slopes rule.. I tried looking it up on google but nothing I can comprehend really comes up.

  36. hartnn
    • one year ago
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    if say line 1 has slope M1 and line 2 has slope M2 now if these 2 lines are perpendicular to each other, then M1*M2 =-1

  37. hartnn
    • one year ago
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    another way to remember the same thing is, the slope of line is negative reciprocal of the perpendicular line, so, slope of line perpendicular to line with slope 1/5 will be - (1/(1/5)) = -5

  38. hartnn
    • one year ago
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    so, thats your 1st one, m =-5 for 2nd one, we had slope = 1/3, so m *(1/3) = -1 so, m=-3 is the answer to 2nd one :)

  39. Mttblink
    • one year ago
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    Okay, so basically whenever there is a fraction just take (1/_) blank space number lol

  40. hartnn
    • one year ago
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    you forgot the negative :P -1/ stuff

  41. hartnn
    • one year ago
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    but this only applies to perpendicular lines

  42. hartnn
    • one year ago
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    for parallel lines, slope are equal

  43. Mttblink
    • one year ago
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    Oh I see says the blind man

  44. hartnn
    • one year ago
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    what who ?

  45. hartnn
    • one year ago
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    lol

  46. hartnn
    • one year ago
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    i hope you got the entire problem clearly ?

  47. hartnn
    • one year ago
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    ask if any doubts anywhere

  48. Mttblink
    • one year ago
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    Yeah I get it now man thanks a ton

  49. hartnn
    • one year ago
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    welcome ^_^

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