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praxer

If an electric dipole is placed along the X axis and we measure the potential at a point in the negative X axis then why does the sum of the potential not becomes zero.

  • 6 months ago
  • 6 months ago

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  1. praxer
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    |dw:1381951889730:dw|

    • 6 months ago
  2. abb0t
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    I'm not sure. But Isn't this refering to superposition principle? You have more of a pull on A.

    • 6 months ago
  3. praxer
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    • 6 months ago
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  4. praxer
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    In the attachment there is a example and in the solution it is given that there is no possibility of potentials due to two charges to adding upto zero for x<0

    • 6 months ago
  5. abb0t
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    I think for this you should be using \(\sf \color{}{F = 2aqr_0}\) ? Right? In terms of el. dipole.

    • 6 months ago
  6. praxer
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    hmmm, but when it comes for potential it is pk/r^2 in an axial dipole

    • 6 months ago
  7. abb0t
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    Isn't that torque??

    • 6 months ago
  8. abb0t
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    Sorry I forgot all my phsycs I took E&M like 4 years ago. And I have no books to help me. lol

    • 6 months ago
  9. praxer
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    But the question said about potential, so i think we should not bring about electric field. Because in the solution it was given that on the negative axis there is no possibility of the potential to become Zero.

    • 6 months ago
  10. abb0t
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    Maybe @zepdrix can help.

    • 6 months ago
  11. Study23
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    I don't have much experience with this topic in physics... I just started physics recently (on vectors displacement and the like...) Sorry, @praxer! Maybe you could help me out?

    • 6 months ago
  12. praxer
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    @e.mccormick can u hlp me undrstnd this..

    • 6 months ago
  13. abb0t
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    I'm sure @Luigi0210 can help.

    • 6 months ago
  14. praxer
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    @abb0t no one did help :(

    • 5 months ago
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