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praxer
 one year ago
If an electric dipole is placed along the X axis and we measure the potential at a point in the negative X axis then why does the sum of the potential not becomes zero.
praxer
 one year ago
If an electric dipole is placed along the X axis and we measure the potential at a point in the negative X axis then why does the sum of the potential not becomes zero.

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abb0t
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure. But Isn't this refering to superposition principle? You have more of a pull on A.

praxer
 one year ago
Best ResponseYou've already chosen the best response.0In the attachment there is a example and in the solution it is given that there is no possibility of potentials due to two charges to adding upto zero for x<0

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0I think for this you should be using \(\sf \color{}{F = 2aqr_0}\) ? Right? In terms of el. dipole.

praxer
 one year ago
Best ResponseYou've already chosen the best response.0hmmm, but when it comes for potential it is pk/r^2 in an axial dipole

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0Sorry I forgot all my phsycs I took E&M like 4 years ago. And I have no books to help me. lol

praxer
 one year ago
Best ResponseYou've already chosen the best response.0But the question said about potential, so i think we should not bring about electric field. Because in the solution it was given that on the negative axis there is no possibility of the potential to become Zero.

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0Maybe @zepdrix can help.

Study23
 one year ago
Best ResponseYou've already chosen the best response.0I don't have much experience with this topic in physics... I just started physics recently (on vectors displacement and the like...) Sorry, @praxer! Maybe you could help me out?

praxer
 one year ago
Best ResponseYou've already chosen the best response.0@e.mccormick can u hlp me undrstnd this..

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0I'm sure @Luigi0210 can help.

praxer
 one year ago
Best ResponseYou've already chosen the best response.0@abb0t no one did help :(
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