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If an electric dipole is placed along the X axis and we measure the potential at a point in the negative X axis then why does the sum of the potential not becomes zero.

Physics
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I'm not sure. But Isn't this refering to superposition principle? You have more of a pull on A.
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Other answers:

In the attachment there is a example and in the solution it is given that there is no possibility of potentials due to two charges to adding upto zero for x<0
I think for this you should be using \(\sf \color{}{F = 2aqr_0}\) ? Right? In terms of el. dipole.
hmmm, but when it comes for potential it is pk/r^2 in an axial dipole
Isn't that torque??
Sorry I forgot all my phsycs I took E&M like 4 years ago. And I have no books to help me. lol
But the question said about potential, so i think we should not bring about electric field. Because in the solution it was given that on the negative axis there is no possibility of the potential to become Zero.
Maybe @zepdrix can help.
I don't have much experience with this topic in physics... I just started physics recently (on vectors displacement and the like...) Sorry, @praxer! Maybe you could help me out?
@e.mccormick can u hlp me undrstnd this..
I'm sure @Luigi0210 can help.
@abb0t no one did help :(

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