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anonymous
 2 years ago
An object is seen at a position (0, 10, 2)m after moving for 12s with an avg velocity of (1/4, 1, 1/2) m/s. What was the magnitude of the displacement of the object during those 12s (I got (3,12,6)? What was the initial location before those 12s (I got 3,2,4). If the object speeds up by 40% where will it end up in 12 more seconds (Would I multiply the given position by the product of 12 and 1.4?)
anonymous
 2 years ago
An object is seen at a position (0, 10, 2)m after moving for 12s with an avg velocity of (1/4, 1, 1/2) m/s. What was the magnitude of the displacement of the object during those 12s (I got (3,12,6)? What was the initial location before those 12s (I got 3,2,4). If the object speeds up by 40% where will it end up in 12 more seconds (Would I multiply the given position by the product of 12 and 1.4?)

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Am I correct? I'm confused now because I think I may have done something wrong!

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Do you have to use fractions? .25, 1, .5 m/s *12 = 3, 12, 6. (0,10,2) (3, 12 6)= 3,2,4, multipy the velocity times 1.4, figure new magnitude, and new end position. .35, 1.4, .7 *12= ....

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Oh okay! That's what I was thinking... Thanks @Fixitupman!
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