PLEASE, SOMEONE HELP ME! THIS IS DUE TOMORROW, AND I'VE BEEN STUCK FOR SEVERAL DAYS!!!! The first stage of a trip has a displacement vector in the negative x direction. The second stage has a displacement vector at an angle of 30 above the positive x axis. The final stage has a displacement 40 degrees below the +x axis at a magnitude of 15km. If after all three stages you end up where you started, what was the magnitudes of the displacement of the first two stages?

Hey! We 've verified this expert answer for you, click below to unlock the details :)

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

This is what I'm thinking: |dw:1381891283053:dw| I was thinking that d1=a+b and d2 is the sum of vectors b and c. If I could find x/y comp of a and b, then I could add up the comp to find displacement... I need HELP though, IM STUCK!!!!

Is there a simpler way???????

Yah! I think this may be late, but use the ordering of the stages to your advantage. You know part 2 has to happen at the end of part 1, etc.. so |dw:1381915710776:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.