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Study23
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PLEASE, SOMEONE HELP ME! THIS IS DUE TOMORROW, AND I'VE BEEN STUCK FOR SEVERAL DAYS!!!! The first stage of a trip has a displacement vector in the negative x direction. The second stage has a displacement vector at an angle of 30 above the positive x axis. The final stage has a displacement 40 degrees below the +x axis at a magnitude of 15km. If after all three stages you end up where you started, what was the magnitudes of the displacement of the first two stages?
 11 months ago
 11 months ago
Study23 Group Title
PLEASE, SOMEONE HELP ME! THIS IS DUE TOMORROW, AND I'VE BEEN STUCK FOR SEVERAL DAYS!!!! The first stage of a trip has a displacement vector in the negative x direction. The second stage has a displacement vector at an angle of 30 above the positive x axis. The final stage has a displacement 40 degrees below the +x axis at a magnitude of 15km. If after all three stages you end up where you started, what was the magnitudes of the displacement of the first two stages?
 11 months ago
 11 months ago

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Study23 Group TitleBest ResponseYou've already chosen the best response.0
This is what I'm thinking: dw:1381891283053:dw I was thinking that d1=a+b and d2 is the sum of vectors b and c. If I could find x/y comp of a and b, then I could add up the comp to find displacement... I need HELP though, IM STUCK!!!!
 11 months ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Is there a simpler way???????
 11 months ago

AllTehMaffs Group TitleBest ResponseYou've already chosen the best response.0
Yah! I think this may be late, but use the ordering of the stages to your advantage. You know part 2 has to happen at the end of part 1, etc.. so dw:1381915710776:dw
 11 months ago

AllTehMaffs Group TitleBest ResponseYou've already chosen the best response.0
θ = 180 9030 = 60 ψ = 40 φ = 1809040 = 50 (θ+φ) = 110 So you have triangle ABC and then use law of sines to find side lengths (for magnitudes only) dw:1381916712888:dw
 11 months ago
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