PLEASE, SOMEONE HELP ME! THIS IS DUE TOMORROW, AND I'VE BEEN STUCK FOR SEVERAL DAYS!!!! The first stage of a trip has a displacement vector in the negative x direction. The second stage has a displacement vector at an angle of 30 above the positive x axis. The final stage has a displacement 40 degrees below the +x axis at a magnitude of 15km. If after all three stages you end up where you started, what was the magnitudes of the displacement of the first two stages?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
This is what I'm thinking: |dw:1381891283053:dw| I was thinking that d1=a+b and d2 is the sum of vectors b and c. If I could find x/y comp of a and b, then I could add up the comp to find displacement... I need HELP though, IM STUCK!!!!
Is there a simpler way???????
Yah! I think this may be late, but use the ordering of the stages to your advantage. You know part 2 has to happen at the end of part 1, etc.. so |dw:1381915710776:dw|