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anonymous
 3 years ago
Please help! how do you write y=x^22x3 in vertex and intercept form using the quadratic formula?
anonymous
 3 years ago
Please help! how do you write y=x^22x3 in vertex and intercept form using the quadratic formula?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @satellite73 do you guys know how to do this? :o

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think it is y=2x3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oops I meant xD y=2x+1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is that for vertex form or intercept form? :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oops damn I put that in slopeintercept... Geez I suck at math xD, I don't think I can help you on vertex

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hahah thanks for trying :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1use the quadratic formula and find the xintercepts first

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you help me figure out how to do that? thats where im stuck :(

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1sure :) u knw the quadratic formula ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorta :o im just so confused because we've been using so many different forms!

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1dont wry, this is going to be very easy :) First, we find xintercepts using the quadratic formula.

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1y=x^22x3 a = ? b = ? c = ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1you need to figure out a, b, c values. and plug them above to get the xintercepts

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so a=1 b=2 c=3? what i dont get is that it wants me to put that equation in intercept and vertex form but those have h & k :o

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1b = 2 we will get to vertex/intercept forms later. first, get the xintercepts :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1put them in the formula above, wat do u get for x = ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01 becaue 1^2 is 1? let me do that equation

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1use above, take ur time :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\) \(\large x = \frac{2 \pm \sqrt{(2)^24 \times 1\times (3)}}{2(1)}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got 1 ± 4 .... is that close? :o

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\) \(\large x = \frac{2 \pm \sqrt{(2)^24 \times 1\times (3)}}{2(1)}\) \(\large x = \frac{2 \pm \sqrt{4 + 12}}{2}\) \(\large x = \frac{2 \pm \sqrt{16}}{2}\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1thats close, just a minor mistake u did... check once

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\) \(\large x = \frac{2 \pm \sqrt{(2)^24 \times 1\times (3)}}{2(1)}\) \(\large x = \frac{2 \pm \sqrt{4 + 12}}{2}\) \(\large x = \frac{2 \pm \sqrt{16}}{2}\) \(\large x = \frac{2 \pm 4}{2}\) \(\large x = 1 \pm 2\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh i see what i did wrong! thank you :) so know what do i do?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1that gives, \(x = 1+2 ~~~ or~~~~ x = 12\) \(x = 3, 1\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1we're done wid using quadratic formula. we got the xintercepts : 3, 1

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1so the intercept form would be : y = (x3)(x+1)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1wat about vertex form ? how to get \(h\), \(k\) ... any ideas ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wow that was easier than i thought! thank you :) & no, not too sure :(

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1vertec form is also easy, \(h\) lies exactly at the middle of both the intercepts : \(h \) = \(\large \frac{3 + 1}{2}\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(h \) = \(\large \frac{31}{2}\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(h \) = \(\large \frac{2}{2}\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(h \) = \(\large 1\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1so vertex form wud be : \(y = (x1)^2 + k\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1you still need to find \(k\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, so how do we find k now? :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1put x = h = 1, in given quadratic. it gives u the \(k\) value

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1y = 1^2  2(1)  3 = 1 2 3 = ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0y=(x−1)^2+4 would be the answer? :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1who ate the  sign before 4 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i messed up again ._. so it would be y=(x−1)24?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you so much!! you're amazing!! :) if it isnt too much too ask could you help me with two more equations similar to that? :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i need to figure out how to put y5=2(x+1)^2 in standard and intercept form & y=(x+2)(x3) in standard and vertex form :o

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1wats the standard form ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1y = ax^2 + bx + c this is the standard form right ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1oh yes... thats right !

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1y5=2(x+1)^2 add 5 both sides y = 2(x+1)^2 + 5

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1next, use the formula \((a+b)^2 = a^2 +b^2 + 2ab\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1y = 2(x+1)^2 + 5 = 2(x^2 + 1^2 + 2x ) + 5 = 2(x^2 + 1 + 2x) + 5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0would it be 2x^24x+3?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1standard form : y = 2x^24x+3

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1y5=2(x+1)^2 to put this guy in intercept form, u need to find its xintercepts. so put y = 0 05=2(x+1)^2 5/2 = (x+1)^2 \(\pm \sqrt{5/2} = x+1\) \( 1 \pm \sqrt{5/2} = x\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1those are our xintercepts

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1can u put t he intercept form ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the intercept form is y=a(xp)(xq)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so if the equation is −1±5/2, how do i solve the fraction part?
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