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ali1029
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Please help! how do you write y=x^22x3 in vertex and intercept form using the quadratic formula?
 10 months ago
 10 months ago
ali1029 Group Title
Please help! how do you write y=x^22x3 in vertex and intercept form using the quadratic formula?
 10 months ago
 10 months ago

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ali1029 Group TitleBest ResponseYou've already chosen the best response.1
@ganeshie8 @satellite73 do you guys know how to do this? :o
 10 months ago

Mttblink Group TitleBest ResponseYou've already chosen the best response.0
I think it is y=2x3
 10 months ago

Mttblink Group TitleBest ResponseYou've already chosen the best response.0
Oops I meant xD y=2x+1
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
is that for vertex form or intercept form? :)
 10 months ago

Mttblink Group TitleBest ResponseYou've already chosen the best response.0
Oops damn I put that in slopeintercept... Geez I suck at math xD, I don't think I can help you on vertex
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
hahah thanks for trying :)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
use the quadratic formula and find the xintercepts first
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
can you help me figure out how to do that? thats where im stuck :(
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
sure :) u knw the quadratic formula ?
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
sorta :o im just so confused because we've been using so many different forms!
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dont wry, this is going to be very easy :) First, we find xintercepts using the quadratic formula.
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y=x^22x3 a = ? b = ? c = ?
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
you need to figure out a, b, c values. and plug them above to get the xintercepts
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
so a=1 b=2 c=3? what i dont get is that it wants me to put that equation in intercept and vertex form but those have h & k :o
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
b = 2 we will get to vertex/intercept forms later. first, get the xintercepts :)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
put them in the formula above, wat do u get for x = ?
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
1 becaue 1^2 is 1? let me do that equation
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
a = 1 b = 2 c = 3
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
use above, take ur time :)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\) \(\large x = \frac{2 \pm \sqrt{(2)^24 \times 1\times (3)}}{2(1)}\)
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
i got 1 ± 4 .... is that close? :o
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\) \(\large x = \frac{2 \pm \sqrt{(2)^24 \times 1\times (3)}}{2(1)}\) \(\large x = \frac{2 \pm \sqrt{4 + 12}}{2}\) \(\large x = \frac{2 \pm \sqrt{16}}{2}\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
thats close, just a minor mistake u did... check once
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\) \(\large x = \frac{2 \pm \sqrt{(2)^24 \times 1\times (3)}}{2(1)}\) \(\large x = \frac{2 \pm \sqrt{4 + 12}}{2}\) \(\large x = \frac{2 \pm \sqrt{16}}{2}\) \(\large x = \frac{2 \pm 4}{2}\) \(\large x = 1 \pm 2\)
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
ohhh i see what i did wrong! thank you :) so know what do i do?
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
that gives, \(x = 1+2 ~~~ or~~~~ x = 12\) \(x = 3, 1\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
we're done wid using quadratic formula. we got the xintercepts : 3, 1
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
so the intercept form would be : y = (x3)(x+1)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
wat about vertex form ? how to get \(h\), \(k\) ... any ideas ?
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
wow that was easier than i thought! thank you :) & no, not too sure :(
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
vertec form is also easy, \(h\) lies exactly at the middle of both the intercepts : \(h \) = \(\large \frac{3 + 1}{2}\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(h \) = \(\large \frac{31}{2}\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(h \) = \(\large \frac{2}{2}\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(h \) = \(\large 1\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
so vertex form wud be : \(y = (x1)^2 + k\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
you still need to find \(k\)
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
okay, so how do we find k now? :)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
put x = h = 1, in given quadratic. it gives u the \(k\) value
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y=x^22x3 put x = 1
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y = 1^2  2(1)  3 = 1 2 3 = ?
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
yup ! thats ur \(k\)
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
y=(x−1)^2+4 would be the answer? :)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
who ate the  sign before 4 ?
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
i messed up again ._. so it would be y=(x−1)24?
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
thank you so much!! you're amazing!! :) if it isnt too much too ask could you help me with two more equations similar to that? :)
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
i need to figure out how to put y5=2(x+1)^2 in standard and intercept form & y=(x+2)(x3) in standard and vertex form :o
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
wats the standard form ?
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
y=ax^2+bx+c?
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y = ax^2 + bx + c this is the standard form right ?
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
oh yes... thats right !
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y5=2(x+1)^2 add 5 both sides y = 2(x+1)^2 + 5
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
next, use the formula \((a+b)^2 = a^2 +b^2 + 2ab\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
expand right side,
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
would it be y=2x+1
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y = 2(x+1)^2 + 5 = 2(x^2 + 1^2 + 2x ) + 5 = 2(x^2 + 1 + 2x) + 5
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
simplify :)
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
would it be 2x^24x+3?
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
correct
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
standard form : y = 2x^24x+3
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y5=2(x+1)^2 to put this guy in intercept form, u need to find its xintercepts. so put y = 0 05=2(x+1)^2 5/2 = (x+1)^2 \(\pm \sqrt{5/2} = x+1\) \( 1 \pm \sqrt{5/2} = x\)
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
those are our xintercepts
 10 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
can u put t he intercept form ?
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
the intercept form is y=a(xp)(xq)
 10 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
so if the equation is −1±5/2, how do i solve the fraction part?
 10 months ago
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