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ali1029
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Please help! how do you write y=x^22x3 in vertex and intercept form using the quadratic formula?
 9 months ago
 9 months ago
ali1029 Group Title
Please help! how do you write y=x^22x3 in vertex and intercept form using the quadratic formula?
 9 months ago
 9 months ago

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ali1029 Group TitleBest ResponseYou've already chosen the best response.1
@ganeshie8 @satellite73 do you guys know how to do this? :o
 9 months ago

Mttblink Group TitleBest ResponseYou've already chosen the best response.0
I think it is y=2x3
 9 months ago

Mttblink Group TitleBest ResponseYou've already chosen the best response.0
Oops I meant xD y=2x+1
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
is that for vertex form or intercept form? :)
 9 months ago

Mttblink Group TitleBest ResponseYou've already chosen the best response.0
Oops damn I put that in slopeintercept... Geez I suck at math xD, I don't think I can help you on vertex
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
hahah thanks for trying :)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
use the quadratic formula and find the xintercepts first
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
can you help me figure out how to do that? thats where im stuck :(
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
sure :) u knw the quadratic formula ?
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
sorta :o im just so confused because we've been using so many different forms!
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dont wry, this is going to be very easy :) First, we find xintercepts using the quadratic formula.
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y=x^22x3 a = ? b = ? c = ?
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
you need to figure out a, b, c values. and plug them above to get the xintercepts
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
so a=1 b=2 c=3? what i dont get is that it wants me to put that equation in intercept and vertex form but those have h & k :o
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
b = 2 we will get to vertex/intercept forms later. first, get the xintercepts :)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
put them in the formula above, wat do u get for x = ?
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
1 becaue 1^2 is 1? let me do that equation
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
a = 1 b = 2 c = 3
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
use above, take ur time :)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\) \(\large x = \frac{2 \pm \sqrt{(2)^24 \times 1\times (3)}}{2(1)}\)
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
i got 1 ± 4 .... is that close? :o
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\) \(\large x = \frac{2 \pm \sqrt{(2)^24 \times 1\times (3)}}{2(1)}\) \(\large x = \frac{2 \pm \sqrt{4 + 12}}{2}\) \(\large x = \frac{2 \pm \sqrt{16}}{2}\)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
thats close, just a minor mistake u did... check once
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\large x = \frac{b \pm \sqrt{b^24ac}}{2a}\) \(\large x = \frac{2 \pm \sqrt{(2)^24 \times 1\times (3)}}{2(1)}\) \(\large x = \frac{2 \pm \sqrt{4 + 12}}{2}\) \(\large x = \frac{2 \pm \sqrt{16}}{2}\) \(\large x = \frac{2 \pm 4}{2}\) \(\large x = 1 \pm 2\)
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
ohhh i see what i did wrong! thank you :) so know what do i do?
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
that gives, \(x = 1+2 ~~~ or~~~~ x = 12\) \(x = 3, 1\)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
we're done wid using quadratic formula. we got the xintercepts : 3, 1
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
so the intercept form would be : y = (x3)(x+1)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
wat about vertex form ? how to get \(h\), \(k\) ... any ideas ?
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
wow that was easier than i thought! thank you :) & no, not too sure :(
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
vertec form is also easy, \(h\) lies exactly at the middle of both the intercepts : \(h \) = \(\large \frac{3 + 1}{2}\)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(h \) = \(\large \frac{31}{2}\)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(h \) = \(\large \frac{2}{2}\)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(h \) = \(\large 1\)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
so vertex form wud be : \(y = (x1)^2 + k\)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
you still need to find \(k\)
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
okay, so how do we find k now? :)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
put x = h = 1, in given quadratic. it gives u the \(k\) value
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y=x^22x3 put x = 1
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y = 1^2  2(1)  3 = 1 2 3 = ?
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
yup ! thats ur \(k\)
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
y=(x−1)^2+4 would be the answer? :)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
who ate the  sign before 4 ?
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
i messed up again ._. so it would be y=(x−1)24?
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
thank you so much!! you're amazing!! :) if it isnt too much too ask could you help me with two more equations similar to that? :)
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
i need to figure out how to put y5=2(x+1)^2 in standard and intercept form & y=(x+2)(x3) in standard and vertex form :o
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
wats the standard form ?
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
y=ax^2+bx+c?
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y = ax^2 + bx + c this is the standard form right ?
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
oh yes... thats right !
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y5=2(x+1)^2 add 5 both sides y = 2(x+1)^2 + 5
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
next, use the formula \((a+b)^2 = a^2 +b^2 + 2ab\)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
expand right side,
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
would it be y=2x+1
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y = 2(x+1)^2 + 5 = 2(x^2 + 1^2 + 2x ) + 5 = 2(x^2 + 1 + 2x) + 5
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
simplify :)
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
would it be 2x^24x+3?
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
standard form : y = 2x^24x+3
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
y5=2(x+1)^2 to put this guy in intercept form, u need to find its xintercepts. so put y = 0 05=2(x+1)^2 5/2 = (x+1)^2 \(\pm \sqrt{5/2} = x+1\) \( 1 \pm \sqrt{5/2} = x\)
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
those are our xintercepts
 9 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
can u put t he intercept form ?
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
the intercept form is y=a(xp)(xq)
 9 months ago

ali1029 Group TitleBest ResponseYou've already chosen the best response.1
so if the equation is −1±5/2, how do i solve the fraction part?
 9 months ago
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