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sarah786

  • one year ago

A cyclist cycling around a circular racing track skids because A.the centripetal force upon him is less than limiting friction B.the centripetal force upon him is greater then limiting friction C.the centripetal force upon him is equal to the limiting friction D.the friction between the tyres of the cycle and road vanishes

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  1. sarah786
    • one year ago
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    @AllTehMaffs :)

  2. AllTehMaffs
    • one year ago
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    Which one do you think?

  3. AllTehMaffs
    • one year ago
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    hai

  4. AllTehMaffs
    • one year ago
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    |dw:1382088401350:dw| Which way would the cyclist slide, and what are the two forces working against each other?

  5. AllTehMaffs
    • one year ago
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    :)

  6. sarah786
    • one year ago
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    Centripetal and Centrifugal forces :/

  7. sarah786
    • one year ago
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    is it B ?

  8. AllTehMaffs
    • one year ago
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    1/2 of that is right:) That half is 100 % right. Centripetal force pushing towards the center of the circle, and it's the friction that's applying the force. I drew the first diagram wrong. |dw:1382107001459:dw| The sum of all the forces is equal to the centripetal force \[ \sum F = F_f =m a_c = F_c \] I think I may have explained that poorly ;/ Centrifugal force doesn't really exist. The thing people call "centrifugal" force is just the tendency of your body to keep going straight while the car is turning. That's another question though :)

  9. sarah786
    • one year ago
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    its B then ???

  10. AllTehMaffs
    • one year ago
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    Yup yup :) \[ a_c = \frac{v^2}{r} \] so if \[F_c > F_f\] the bike skids.

  11. sarah786
    • one year ago
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    ty so much :)

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