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sarah786
 2 years ago
A cyclist cycling around a circular racing track skids because
A.the centripetal force upon him is less than limiting friction
B.the centripetal force upon him is greater then limiting friction
C.the centripetal force upon him is equal to the limiting friction
D.the friction between the tyres of the cycle and road vanishes
sarah786
 2 years ago
A cyclist cycling around a circular racing track skids because A.the centripetal force upon him is less than limiting friction B.the centripetal force upon him is greater then limiting friction C.the centripetal force upon him is equal to the limiting friction D.the friction between the tyres of the cycle and road vanishes

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AllTehMaffs
 2 years ago
Best ResponseYou've already chosen the best response.1Which one do you think?

AllTehMaffs
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1382088401350:dw Which way would the cyclist slide, and what are the two forces working against each other?

sarah786
 2 years ago
Best ResponseYou've already chosen the best response.1Centripetal and Centrifugal forces :/

AllTehMaffs
 2 years ago
Best ResponseYou've already chosen the best response.11/2 of that is right:) That half is 100 % right. Centripetal force pushing towards the center of the circle, and it's the friction that's applying the force. I drew the first diagram wrong. dw:1382107001459:dw The sum of all the forces is equal to the centripetal force \[ \sum F = F_f =m a_c = F_c \] I think I may have explained that poorly ;/ Centrifugal force doesn't really exist. The thing people call "centrifugal" force is just the tendency of your body to keep going straight while the car is turning. That's another question though :)

AllTehMaffs
 2 years ago
Best ResponseYou've already chosen the best response.1Yup yup :) \[ a_c = \frac{v^2}{r} \] so if \[F_c > F_f\] the bike skids.
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