how can I factor 2x^2-X-10?

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how can I factor 2x^2-X-10?

TriC-MathMOOC
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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multiply first/last --> 2*-10 = -20 find 2 factors of -20 that add up to "middle coefficient" -1
4 and -5
correct now split up the "-x" into "4x -5x" then factor by grouping

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that's what I don't quite understand
ok once you get factors rewrite it 2x^2 +4x -5x -10 split into 2 groups (2x^2 +4x)+(-5x-10) factor each group 2x(x +2)-5(x+2) pull out common factor of "x+2" (x+2)(2x-5) done
that easy?! Thanks! (:
thats it....use same steps for any quadratic factoring prablem

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