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Diana0920
 one year ago
cot(theta)tan(theta) over sin(theta) + cos(theta) equals csc(theta)  sec(theta)
how do I proof this?
Diana0920
 one year ago
cot(theta)tan(theta) over sin(theta) + cos(theta) equals csc(theta)  sec(theta) how do I proof this?

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Mertsj
 one year ago
Best ResponseYou've already chosen the best response.3Let's use x instead of theta

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.3\[\frac{\cot x\tan x}{\sin x+\cos x}=\csc x\sec x\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.3Do I have the problem stated correctly?

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0would I have to replace cot(x) with cos(x)/sin(x)

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0and tan(x) with sin(x)/cos(x)

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.3\[(\frac{\frac{\cos x}{\sin x}\frac{\sin x}{\cos x}}{\sin x+\cos x})\times \frac{\sin x \cos x}{\sin x \cos x}=\frac{\cos ^2x\sin ^2x}{\sin x \cos x(\sin x+\cos x)}\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.3Can you get it from there?

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0sadly no? can you explain how I can simplify it more please?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.3Factor the numerator and then the cosx + sinx will cancel.

alejandrop95
 one year ago
Best ResponseYou've already chosen the best response.0I'm still lost :(

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.3@alejandrop95 This is not your question

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0how would I factor it though? I'm sorry I am new to trig.

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.3Can you factor this: \[a^2b^2\]

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0I don't think you can because it doesn't have the same coefficient

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.3\[\cos ^2x\sin ^2x=(\cos x\sin x)(\cos x+\sin x)\]

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0oh okay that makes sense. so would it be cossin(cos+sin)

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0then that would cancel with the denominator correct?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.3Yes. sinx + cosx will cancel

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0which will leave 1/sin(x)+cos(x)

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0using the reciprocal identities this will equal csc(x)sec(x) ?

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0cos(x)sin(x)/sin(x)+cos(x0

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0this is where I would use the reciprocal identities?

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0the cos(x) cancel and the sin(x) cancels?

Diana0920
 one year ago
Best ResponseYou've already chosen the best response.0yay!!!! the cancel and its one,which now you are left with the csc(x) and sec(x) reciprocal identities!! Thank you!! the key idea here that I need to work on was the factoring
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