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osanseviero
 one year ago
Best ResponseYou've already chosen the best response.0if \[F(x)=\frac{ 1 }{ x }\] find and express its simplest form: \[\frac{ f(a+h)f(a) }{ h }\]

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.0That's all I have, what should I do?

Easyaspi314
 one year ago
Best ResponseYou've already chosen the best response.1You should get 1/ (a(a+h))

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.0\[(\frac{ 1 }{ a+h }\frac{ 1 }{ a }) \div h\]

Easyaspi314
 one year ago
Best ResponseYou've already chosen the best response.1I'll start you off.......... Given: f(x) = 1/x So, f(a+h) = 1/(a+h) and f(a) = 1/a So the expression you typed above is just: [ (1/(a+h)  1/a] /h When you simplify that complex fraction above (not hard at all), you get 1/[a(a+h)] as your final answer.

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.0Can you explain how did you simplify, please?

Easyaspi314
 one year ago
Best ResponseYou've already chosen the best response.1Let's take the numerator........ 1/(a+h)  1/a To subtract, you get the LCD which is a(a+h), so 1/(a+h)  1/a = [a(a+h)]/a(a+h) = h/(a(a+h)) Now, the denominator is just h, so you get h/(a(a+h)) divided by h/1 = 1/(a(a+h))

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.0I had a silly math confusion
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