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osansevieroBest ResponseYou've already chosen the best response.0
if \[F(x)=\frac{ 1 }{ x }\] find and express its simplest form: \[\frac{ f(a+h)f(a) }{ h }\]
 5 months ago

osansevieroBest ResponseYou've already chosen the best response.0
That's all I have, what should I do?
 5 months ago

Easyaspi314Best ResponseYou've already chosen the best response.1
You should get 1/ (a(a+h))
 5 months ago

osansevieroBest ResponseYou've already chosen the best response.0
\[(\frac{ 1 }{ a+h }\frac{ 1 }{ a }) \div h\]
 5 months ago

Easyaspi314Best ResponseYou've already chosen the best response.1
I'll start you off.......... Given: f(x) = 1/x So, f(a+h) = 1/(a+h) and f(a) = 1/a So the expression you typed above is just: [ (1/(a+h)  1/a] /h When you simplify that complex fraction above (not hard at all), you get 1/[a(a+h)] as your final answer.
 5 months ago

osansevieroBest ResponseYou've already chosen the best response.0
Can you explain how did you simplify, please?
 5 months ago

Easyaspi314Best ResponseYou've already chosen the best response.1
Let's take the numerator........ 1/(a+h)  1/a To subtract, you get the LCD which is a(a+h), so 1/(a+h)  1/a = [a(a+h)]/a(a+h) = h/(a(a+h)) Now, the denominator is just h, so you get h/(a(a+h)) divided by h/1 = 1/(a(a+h))
 5 months ago

osansevieroBest ResponseYou've already chosen the best response.0
I had a silly math confusion
 5 months ago
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