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osanseviero
 3 years ago
A function operation
osanseviero
 3 years ago
A function operation

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osanseviero
 3 years ago
Best ResponseYou've already chosen the best response.0if \[F(x)=\frac{ 1 }{ x }\] find and express its simplest form: \[\frac{ f(a+h)f(a) }{ h }\]

osanseviero
 3 years ago
Best ResponseYou've already chosen the best response.0That's all I have, what should I do?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You should get 1/ (a(a+h))

osanseviero
 3 years ago
Best ResponseYou've already chosen the best response.0\[(\frac{ 1 }{ a+h }\frac{ 1 }{ a }) \div h\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'll start you off.......... Given: f(x) = 1/x So, f(a+h) = 1/(a+h) and f(a) = 1/a So the expression you typed above is just: [ (1/(a+h)  1/a] /h When you simplify that complex fraction above (not hard at all), you get 1/[a(a+h)] as your final answer.

osanseviero
 3 years ago
Best ResponseYou've already chosen the best response.0Can you explain how did you simplify, please?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Let's take the numerator........ 1/(a+h)  1/a To subtract, you get the LCD which is a(a+h), so 1/(a+h)  1/a = [a(a+h)]/a(a+h) = h/(a(a+h)) Now, the denominator is just h, so you get h/(a(a+h)) divided by h/1 = 1/(a(a+h))

osanseviero
 3 years ago
Best ResponseYou've already chosen the best response.0I had a silly math confusion
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