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osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Natural domain of \[f(x)=\frac{ 1 }{ x3 }\] g(x)=5x \[(Fog)(x)\] It is x\[x \in[1,infinite)\] ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1what did you get for f(g(x)) = .... ?

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Let me do it, give me a sec

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1sure, take your time :)

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1ooops sorry, confused question, give me another sec

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1am i reading the question correct ? f(x) =1/ (x3) g(x) =5x ? i don't see ..... oh, okk

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Sorry, the mistake was the question

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x)=\sqrt{x+1}\] g(x)=14x

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yes, f(g(x)) is correct then

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1now quantity under square root cannot be negative

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1So the domain is x<= 1/2 for the square root, and I take the intersection

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yep, thats correct! good :)

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1So I need to take the domain of FoG with \[\left\{ x \in Dgg(x)\in Df \right\}\]

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1And intersect that with the domain of the last result?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1i am not sure about what that notation says, but yes, you take the intersection domains of both the funtion with composite function to get the final domain
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