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osanseviero Group TitleBest ResponseYou've already chosen the best response.1
Natural domain of \[f(x)=\frac{ 1 }{ x3 }\] g(x)=5x \[(Fog)(x)\] It is x\[x \in[1,infinite)\] ?
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what did you get for f(g(x)) = .... ?
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
Let me do it, give me a sec
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
sure, take your time :)
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{24x}\]
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
ooops sorry, confused question, give me another sec
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
am i reading the question correct ? f(x) =1/ (x3) g(x) =5x ? i don't see ..... oh, okk
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
Sorry, the mistake was the question
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
\[f(x)=\sqrt{x+1}\] g(x)=14x
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, f(g(x)) is correct then
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
now quantity under square root cannot be negative
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
So the domain is x<= 1/2 for the square root, and I take the intersection
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
[1,1/2]
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yep, thats correct! good :)
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
So I need to take the domain of FoG with \[\left\{ x \in Dgg(x)\in Df \right\}\]
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
And intersect that with the domain of the last result?
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i am not sure about what that notation says, but yes, you take the intersection domains of both the funtion with composite function to get the final domain
 10 months ago

osanseviero Group TitleBest ResponseYou've already chosen the best response.1
Perfect, thanks
 10 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcome ^_^
 10 months ago
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