osanseviero
  • osanseviero
asymptotes of this function:
Mathematics
schrodinger
  • schrodinger
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osanseviero
  • osanseviero
\[\frac{ 2x-1 }{ x+2 }\]
osanseviero
  • osanseviero
Horizontal: x+2= 0, x=-2...how for the vertcial one?
anonymous
  • anonymous
The vertical asymptote would be x=-2 (because adding -2 to 2 would give you a zero in the denominator), and the horizontal asymptote would be 2 (as calculated by dividing 2x/x)

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osanseviero
  • osanseviero
oh...sorry, I did the vertical before...and what would the horizontal be?
ranga
  • ranga
Vertical asymptote is when y goes to infinity. Horizontal asymptote is when x goes to infinity. To find the horizontal asymptote, find the limit of (2x - 1) / (x + 2) as goes to infinity.
osanseviero
  • osanseviero
y=2 :)
ranga
  • ranga
yes.
osanseviero
  • osanseviero
So the range is (-inf,2)U(2,INF) ?
ranga
  • ranga
Yes the range is correct. Domain is (-inf, -2) U (-2, inf)

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