Here's the question you clicked on:
osanseviero
asymptotes of this function:
\[\frac{ 2x-1 }{ x+2 }\]
Horizontal: x+2= 0, x=-2...how for the vertcial one?
The vertical asymptote would be x=-2 (because adding -2 to 2 would give you a zero in the denominator), and the horizontal asymptote would be 2 (as calculated by dividing 2x/x)
oh...sorry, I did the vertical before...and what would the horizontal be?
Vertical asymptote is when y goes to infinity. Horizontal asymptote is when x goes to infinity. To find the horizontal asymptote, find the limit of (2x - 1) / (x + 2) as goes to infinity.
So the range is (-inf,2)U(2,INF) ?
Yes the range is correct. Domain is (-inf, -2) U (-2, inf)