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osanseviero
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 2x1 }{ x+2 }\]

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.0Horizontal: x+2= 0, x=2...how for the vertcial one?

rach_ell
 one year ago
Best ResponseYou've already chosen the best response.0The vertical asymptote would be x=2 (because adding 2 to 2 would give you a zero in the denominator), and the horizontal asymptote would be 2 (as calculated by dividing 2x/x)

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.0oh...sorry, I did the vertical before...and what would the horizontal be?

ranga
 one year ago
Best ResponseYou've already chosen the best response.1Vertical asymptote is when y goes to infinity. Horizontal asymptote is when x goes to infinity. To find the horizontal asymptote, find the limit of (2x  1) / (x + 2) as goes to infinity.

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.0So the range is (inf,2)U(2,INF) ?

ranga
 one year ago
Best ResponseYou've already chosen the best response.1Yes the range is correct. Domain is (inf, 2) U (2, inf)
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