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osanseviero

  • 2 years ago

Logarithm function question

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  1. osanseviero
    • 2 years ago
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    The graphic of this function passes through P(3,1) \[F(x)=\log_{a}x \] Where a>0. What is a?

  2. hartnn
    • 2 years ago
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    so, x = 3 and f(3) =1 \(1 = \log_a 3 \) got this ?

  3. hartnn
    • 2 years ago
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    now use \(\Large \log_mn=p \implies n = m^p \)

  4. osanseviero
    • 2 years ago
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    Ok, got the first right...

  5. osanseviero
    • 2 years ago
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    3=a

  6. hartnn
    • 2 years ago
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    correct! :)

  7. osanseviero
    • 2 years ago
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    if I did y=f(x+1), what would happen?

  8. osanseviero
    • 2 years ago
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    to the graphic, retricemptote, and domain?

  9. osanseviero
    • 2 years ago
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    everything will go one to the right?

  10. osanseviero
    • 2 years ago
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    or one up?

  11. hartnn
    • 2 years ago
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    x ----> x+1 the graph moves one to left

  12. ranga
    • 2 years ago
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    For a > 0, f(x - a) moves f(x) to the right by a units; f(x + a) moves f(x) to the left by a units.

  13. ranga
    • 2 years ago
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    |dw:1382592889784:dw|

  14. osanseviero
    • 2 years ago
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    So the domain would be from -1 to infinite, the retriceptote would be x=-1

  15. osanseviero
    • 2 years ago
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    and now this would pass through (0,0) instead of (1,0) :D

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