osanseviero
Logarithm function question



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osanseviero
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The graphic of this function passes through P(3,1)
\[F(x)=\log_{a}x \] Where a>0. What is a?

hartnn
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so, x = 3 and f(3) =1
\(1 = \log_a 3 \)
got this ?

hartnn
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now use \(\Large \log_mn=p \implies n = m^p \)

osanseviero
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Ok, got the first right...

osanseviero
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3=a

hartnn
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correct! :)

osanseviero
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if I did y=f(x+1), what would happen?

osanseviero
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to the graphic, retricemptote, and domain?

osanseviero
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everything will go one to the right?

osanseviero
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or one up?

hartnn
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x > x+1
the graph moves one to left

ranga
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For a > 0,
f(x  a) moves f(x) to the right by a units;
f(x + a) moves f(x) to the left by a units.

ranga
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dw:1382592889784:dw

osanseviero
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So the domain would be from 1 to infinite, the retriceptote would be x=1

osanseviero
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and now this would pass through (0,0) instead of (1,0) :D