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Logarithm function question

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The graphic of this function passes through P(3,1) \[F(x)=\log_{a}x \] Where a>0. What is a?
so, x = 3 and f(3) =1 \(1 = \log_a 3 \) got this ?
now use \(\Large \log_mn=p \implies n = m^p \)

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Other answers:

Ok, got the first right...
correct! :)
if I did y=f(x+1), what would happen?
to the graphic, retricemptote, and domain?
everything will go one to the right?
or one up?
x ----> x+1 the graph moves one to left
For a > 0, f(x - a) moves f(x) to the right by a units; f(x + a) moves f(x) to the left by a units.
So the domain would be from -1 to infinite, the retriceptote would be x=-1
and now this would pass through (0,0) instead of (1,0) :D

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